Python Program for armstrong numbers | Python Programming Practice For Interview

[@gauravbhatnagar8658]

n=1 while n

[@Codeyug]

Good!

[@kodarajesh35]

Superb sir

[@Codeyug]

Thank you so much...keep learning

[@HUMAN-007]

Bro,could you explain about use of i=str(i).

[@oliverqueen6866]

this is the best method and very simple method it really make a program very short. 😇😇😇😇😇😇

[@Codeyug]

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[@hyd_explorer_360]

superb bro

[@Codeyug]

Yes...please keep watching videos on my channel..you will learn a lot

[@kodarajesh35]

Plz do video on inverted w hollow pattern

[@Codeyug]

You will get videos on pattern in October definitely... currently i am working on other things...

[@Codeyug]

Master in Python :- kzbin.info/aero/PLI4OVrCFuY543naNBsCaRLrLSxI7MUOzZ

[@dark_legions2227]

👍👍👍👍

[@razimd3849]

what is the output for range 1 to 3

[@avisaranand4141]

Output - 1 2

[@gollamamatha7795]

how to this output in one line sir

[@Codeyug]

By using end argument in print.. Put it's value blank... Or search "print function codeyug"

[@gollamamatha7795]

@@Codeyug tq sir😊

[@sakalagamingyt3563]

''' Armstrong Number Checking Algorithm by Bishal jaiswal Copyright (c) 2022 ''' # 53 ---> sum of nth power of the digits ( [ 5^2+3^2 = 25+9 ] = 34 not armstrong number ) def checkArmstrong(n:int) ->bool: if n>=0: myString = str(n) power = len(myString) nList = [] ArmstrongNumber = 0 for ch in myString: integer = int(ch)**power nList.append(integer) for i in range(len(nList)): ArmstrongNumber += int(nList[i]) if ArmstrongNumber == n: return True else: return False else: return None print(checkArmstrong(-1))