Python Program to Check If the Number is Armstrong or Not?

[@wscubetech]

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[@Nannu-l4i]

x = int(input(" enter a value of x : ")) y = int(input(" enter a value of y : ")) z = int(input(" enter a value of z : ")) xyz = int(str(x) + str(y) + str(z)) answer = x**3 + y**3 + z**3 if answer == xyz: print(" this is an Armstrong number ") else: print(" This isn't an Armstrong number ") THANK ME LATER

[@Krishna_vasudeva]

Thanks

[@itsveronica...]

awesome bro thanks a lot dude

[@Riya-pf3oc]

Beautiful explanation. Thanks so much

[@sushantchougale6818]

Thank you very much Madam 😊 🙏🏻🙏🏻🙏🏻🙏🏻

[@cdhaifule]

Wonderful detailed explanation. Thanks

[@maroofkhan5558]

so confusing please make more simple explanation

[@x_moonboy]

-ve iq ?

[@ArshadAli-yh7dv]

@@x_moonboy it is also wrong

[@aashpay]

No

[@SupriyaKulkarni-b6j]

very nice teaching. I understood very well. Your logic is simple but clear. This is the quality of good programmer.

[@bukkepradeepnaik7826]

i have done using type castings def armstrong(num): su=0 for i in num: su=su+int(i)**3 print(su) if int(num)==int(su): return True else: return False num=input(" Enter the number ") res=armstrong(num) print(res)

[@PythonProjectSolver]

num1 = input("Enter a number : ") length = len(num1) c=0 for i in num1: c += int(i)**int(length) if int(num1) == c: print(num1, "is a Armstrong number") else: print(num1, "is not a Armstrong number")

[@sujanangadi6301]

a = "407" j = 0 for i in range(len(a)): h = a[i] c = int(h) ** 3 j += c if (j == int(a)): print(a, "is an armstrong number") else: print(a, "its not armstrong")

[@UmeshKumar-uy6we]

def armstrong_number(number): alpha=sum(int(item)**len(str(number))for item in str(number)) if alpha == number: print(f"given number is an armstrong number") else: print(f"given number is not an armstrong number") it will work for each case correct me if i am wrong

[@Prashantchaudhary-kf1fb]

i copy paste your code but it can not run i click run then automatically shifted in another cell

[@Mridun29811]

define(def) statement is used to define a function

[@77Aditya77]

Mam ye sirf 3 digit ke liye applicable hai na ?

[@hotshow3691]

convert input value into string then get the length of it and store in a variable then use this variable instead of 3.. emiway bantai:::: Samaj main aya kya..

[@aishwaryabhalbhar7774]

u can use (len(str(num))) instead of 3

[@Truple64]

​@@aishwaryabhalbhar7774 Thank you!!

[@REKHAMEHTA-v6c]

no=input("no") c=int(no) d=0 for i in no: a=int(i)**len(no) print(a) d=d+a if c==d: print(f"{no} is armstrong number") else: print(f"{no} is not armstrong number")

[@REKHAMEHTA-v6c]

is this correct??

[@shravanikeni6218]

No

[@yadavji-d3w]

yes

[@kocengineering769]

Yes i didn't know what is Armstrong number

[@Random_Coder727]

def define_amstrong_value(a): a = str(a) x = 0 for i in a: i = int(i) x = x + i**3 return x num = int(input('upto where you want amstg nums?: ')) for i in range(1,num+1): if i == define_amstrong_value(i): print(i)

[@Random_Coder727]

it prints all the amstrong nums upto which you want

[@sweet_girl_23]

print(sum(int(i)**len(n)) for i in str(n))

[@manisofat2047]

hi! i regularly follow your channels and the python programing lectures you posted on your channel, it really helped me alot. but, in this video i think you accidently narate the wrong statement and put wrong inputs during program execution. Let me narate how: As per "armstrong rule", length of the number entered will the power of each digit, so fixed the digit cube with (3) in logic and during the program execution your also giving input a two digit number (which is wrong as per the logic and as per your given naration in the beginig of video.). SO this program is not a general program. Please correct this video. i hope my this help will not effect ur fab. reputation for the next student who gonna watch this. Please watch your this video carfully. Thanx. :) Lots of Luv to WsCube

[@PythonProjectSolver]

very simple : num1 = input("Enter a number : ") length = len(num1) c=0 for i in num1: c += int(i)**int(length) if int(num1) == c: print(num1, "is a Armstrong number") else: print(num1, "is not a Armstrong number")

[@PythonProjectSolver]

num1 = input("Enter a number : ") length = len(num1) c=0 for i in num1: c += int(i)**int(length) if int(num1) == c: print(num1, "is a Armstrong number") else: print(num1, "is not a Armstrong number")

[@kashmirking2446]

But why sum =0

[@Vikas_27_vlog_panti]

nice madam ji aap ki voice bahot achhi hai thanks

[@easycoder918]

Thank you 😊 didi😊🎉

[@mdkashifmeardad1946]

Thinks mam

[@harshitsrivastava5399]

This program is wrong mam it will not work for any no which has greater than 3 digits.

[@facebookapp521]

Hello sales funnel kaise bnaue video bna do please 🙏

[@AdarshYadav-dd2gq]

Har baar cube hi nahi hoga .

[@justplay2639]

why its not working if i am not using temp variable either of it i am directly using num on its place

[@manishbhatt5355]

Sooo confusing

[@PythonProjectSolver]

num1 = input("Enter a number : ") length = len(num1) c=0 for i in num1: c += int(i)**int(length) if int(num1) == c: print(num1, "is a Armstrong number") else: print(num1, "is not a Armstrong number")