Python Tutorial - For Loop - Passwords

[@mirashiki1739]

Thanks for the tutorial, really needed it for computer assignment

[@barringtonpatterson6449]

you have just earned a new sub :)

[@tylersanada508]

This was very helpful. Thanks.

[@sirkingsomo1]

Wow three years ago, and am just learning it now..... thanks for the video, it was helpful, straight to the point..... please I need help getting a remote internship with...even though am not been paid huge amount....

[@soggy1566]

This is a bit off topic but how does the date on the calendar say oct 2 when this video was uploaded oct 1?

[@GeekTutorials1]

Well spotted ;)

[@gaurangparulekar363]

If there are two block of code for example password which you just showed and second are some steps if I do run all and give 4incorrect password in last attempt it will give you acess denied but below code will work am I right

[@scytnx3914]

after the second "else:" i got error. Can somebody tell me why and how to fix it?

[@faizanmadki5711]

If you enter first 2 attempts wrong code but in the 3 rd attempt if I enter correct password it says you have been denied access

[@homeresquivel8960]

How do you fix this?

[@TamLe-yh3eg]

print( "Hi man, you have 3 attempts ") password="123456" for i in range(3,0,-1): attempt=input("password?: ") if attempt == password: print("WELCOME") break if attempt != password: i = i-1 print("INCORRECT, you have", i ,"attempts left") continue if i == 0: print("You've ran out of attempts") Try this one i think this is better

[@sairajmarshetty7152]

@@TamLe-yh3eg if i want to add username ??how can i do it

[@TamLe-yh3eg]

assign name = input("What is ur username?: ") then the print line will be print('Hi', name, 'you have 3 attempts') so when you input any username the command will send a greeting

[@hernanaquino7100]

thanks for this , you help me bro

[@megamagma4422]

This tutorial is really good but has 1 problem - If you enter the right answer it will break and the same thing at denied 3 attempts, how do I make it lock?

[@henrydanjayag6703]

Try on line 10: change if i == 1: to, if i == 4:

[@willclifford7314]

it only gives you two attempts, how do you fix that?

[@GeekTutorials1]

If you wish to change the number of attempts, change the numbers in the brackets at the for loop line of code. Maybe try changing the 3 to a 4, which would read for i in range(4, 0, -1)

[@europeguy78]

print( " Hi man , you have 3 attempts ") password = "sun" for i in range(0,3): enter_password = input("Enter the password : ") j=2 if enter_password == password: print("Password has been accepted") break elif i < 2: print("Incorrect password try again, attempt number ",j+i) else: print("fuck off, you have been denied acces :-)") continue print(" have a nice day")

[@satorugojo9529]

wow nice tutorial but when i type the wrong password 3 times it dosent do anything it just makes the user see the other codes input so simple question is how do i make it so that when you type the password 3 wrong times it should not show what the next thing is

[@GeekTutorials1]

You must have missed something in the code - my app does what you are saying, doesn't it?

[@satorugojo9529]

@@GeekTutorials1 it does everything thing perfectly but if the user gets the password wrong it still shows them the thing

[@muhammadhasan7551]

man can i copy pasta it

[@GeekTutorials1]

Yes

[@carliechapman4188]

it say access denied because the word break doesnt work