Quadratic form to Principal Axes Form Tranformation

[@Benjo1102]

From where did you pull out the 128 at 3:15 ?

[@physicsunravelled6741]

That's already given in the problem. It's a given data Q = 128

[@RahulRoy-pw6cb]

Which book you are following??

[@physicsunravelled6741]

Advanced Engineering Mathematics by Erwin Kreyszig

[@RahulRoy-pw6cb]

@physicsunravelled6741 thanks ma'am

[@humorHive266]

A ❌ yaay ✅

[@mafugagaming8915]

Mam why you have taken x1=x2= 1/√3 why not 1 or -1

[@physicsunravelled6741]

Yes you can choose either 1 or -1 then you have to normalise the eigen vector if you want (i.e. you have to make its magnitude one so you have to divide the eigen vector by its magnitude). In your case, the magnitude is √2 so the normalised eigen vector would be 1/√2, 1/√2

[@mafugagaming8915]

@@physicsunravelled6741 got it thankyou very much mam