Quadrilaterals 3 | CAT Preparation 2024 | Geometry | Quantitative Aptitude

Quadrilaterals by Ravi Prakash | Geometry Quantitative Aptitude for CAT 2024
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[@SachinChandra-pb6sh]

You, yes you who is reading this comment. You can do it and you will do it. 99%ile+ is waiting for you.

[@minnieplayzz9642]

You are so sweet❤️

[@prateekthakur1848]

Full power

[@raghavrohilla8241]

Likewise brother🤍

[@friedsugar2701]

76k People saw this video, if everyone is fucking getting 99 toh meh kya halwa

[@academics7471]

In the last question, during the last part while taking the area you have taken 60 instead of 66.

[@vanditshrivastava3571]

Sir you made a small mistake in the last sum... It's (50+66) /2 ×3√21 = 174 √21

[@jayakrishnarachapally1270]

yup

[@himanshugajare1861]

Yeah

[@sahilparkhe7541]

Apply BODMAS.

[@Vineet84]

Ye un bacho me se hai jinhe sab aata hota h par fir bhi paper me fail hote hai 🤣

[@shubhamthakur7299]

yes

[@gaudarvind]

U r "__the__" Ravi Prakash sir no one can explain like u

[@shashagaming4076]

Ye galtiya nikalne wale yehi karte reh jayenge 😅😅 Brilliant lecture as always sir 🙌🏻🙌🏻

[@pruthviraj8244]

Once you say "it's good question", i will stop my way of thinking about solution and continue the video 😂😂

[@roshqsarrosh4225]

In the last part. The Area of Trapezium= Have to use 66 instead of 60.And the area comes out to be 174 √21

[@avinashnair8433]

Yes you are correct.

[@kirtigoyal9623]

We can also take y as 16-x. Would be easier to solve the last question.

[@harishamehta3455]

Amazing content sir. Thankyou♥️

[@ManuSrivastava_]

Thank you so much sir.❤❤

[@Shivam_General_Fitness]

Thanku sir

[@ayushkumar7497]

thanku sir

[@ayushichoudhary7326]

Hello sir, your videos are so great and helpful. Thankyou so much. Can you please share a question bank as well, from where we can practice. All the questions that you discuss are so of such great quality, getting a question bank too would be so helpful

[@MSD07205]

Had u cleared the cat btw i.also preparing for cat 2k24

[@agrim8863]

Sir,please upload more videos of geometry, and also upload trigonometry.

[@Sidswamiofficial]

I m urbiggest fan sir.whatever u r doing is fabulous but i would like to remind u to solve atleast 12 difficut questions on trapezium.so that it can cover all difficult portion trapezium.it is my humble request to u.

[@Aashish14914]

where can I get your polygon lectures? I am not able to find it. Please help me out

[@salwimehta]

Happy teacher's day sir

[@kapil2577]

Assume the two heights to be h1 (OB) and h2 (OA), now PQ/SR = 8/10 so, 8/10= x/3-x , x=4/3 but we need h2=3-x so, 3-(4/3) = 5/3.

[@bikramjitsingh5534]

How 8/10 equal to x/3-x??

[@singh_isking]

sir coordinate bhi padha do pls

[@Diabolical3010]

No video on polygons sir? :/

[@AsmitaShirwadkar]

At the end in area formula value of parallel sides is wrong it is given 50+60 correct it actual value is 50+66

[@dikshakumari1332]

Today trapezium has become clear to me

[@kanakh7775]

Hahaha you always wanted the other side to be 60 😂

[@tanmaymohapatra3926]

Yeah.. Nice catch😂😂😂

[@vikasyadav7893]

So truee😂

[@fAiz-zo9od]

May be sir's roll number always would be 60 that' why😂

[@premshah6507]

LOL

[@anjalianand9359]

🤣🤣🤣🤣🤣

[@raghavrohilla8241]

For area of trapezium in last ques, won't we take the longer parallel side as 66? Instead of 60

[@407rajivpattanayak6]

Sir, if we us the properties of mid pt theorem,in triangle POK where K is perpendicular on SR, and the height turns out to be 3. Then when we put a perpendicular on SR to O then PK || OJ, so OJ=1/2 PK. will it be wrong

[@rehanjeelani3534]

Yes because it is not mentioned that J is the mid point so applying this will be wrong

[@pratikpittule4507]

Is there video quadrilateral 4. Provide link if there is.

[@mindfullmallu7511]

No I guess..

[@hridyathuvassery]

Videos of trigonometry and polygon?😢

[@nehatiwari9297]

In last question how come x+y=16?

[@nikhilbhalla7836]

2nd parallel side was 66. So 50+x+y=66 X+y=16

[@rahulshrivastava8720]

Sir the 2nd side is 66 , but u have written 60 while finding the area

[@avinashnair8433]

It's a typing mistake by Sir. So neglect that. But your answer is right

[@pranavkottappurath6806]

sir in last question, at 13:00 min. why cant we find height using pythagorus triplet 8,15,17?

[@shrianshverma6671]

because then the height would be 15 for the other triangle as wont sit right with pythagoras theorem

[@ruchijoshi8418]

Sir where did 5/9 come from at 4.54

[@kapil2577]

assume the two heights to be h1 (OB) and h2 (OA), now PQ/SR = 8/10 so, 8/10= x/3-x , x=4/3 but we need h2=3-x so, 3-(4/3) = 5/3.

[@ruchijoshi8418]

Thank you 🙏

[@choprasamkitsuresh5513]

Sir what if instead of 15&6 for finding H. If we use 17&10

[@debasishsahu5426]

Same ans , we have find.

[@rahulshrivastava8720]

The answer will be same (17)*2 - (10)*2 = H*2 i.e H*2 = 289 - 100 ....H = √189

[@sanskritinannore7209]

I wish the video had the same volume as the ads in between.

[@nakulkaushal4473]

Just download it and then watch no ads then!:)

[@shubhamnimje419]

I dont understand why people hates ad on free forum. If you have problem with ads then join some expensive coaching classes to get rid of ads. :-)

[@theatomicstories]

ye dislikers kon hn?

[@pranavkottappurath6806]

[@nidhivanisha]

In the last question, during the last part while taking the area you have taken 60 instead of 66.