Quartic Equations Part 2

[@carterb1478]

Need to check the domain of square root in the bottom of the fraction make should that does not divide by zero.

[@ravenmitchell820]

So √(2k-p)>0, {k|k>p/2 if real, k

[@bobbyheffley4955]

You can choose k>p/2 to ensure real values on the right-hand side. If k

[@holyshit922]

We dont need to get rid of cubic term when we solve it using difference of squares If we want to multiply two quadratics in general form and compare coeffictients then getting rid of cubic term could be useful

[@Kknhg]

It is a correct solution, but it is not considered a general method of solution. I think we must refer to the comparative solution as is the case in solving the third degree equations, but in this case there are three variables with respect to the fourth degree equations, and four variables with respect to the fifth degree and so on ...

[@holyshit922]

General method of solution involves some special functions like hypergeometric functions or Jacobi theta function

[@User-ei2kw]

Why not beta = sqrt(k^2-r) ?? Much simpler algebra