Question (2) - Will the Shear Force Diagram for a Triangular Distributed Load be Parabolic? Why?

[@CTSCIVIL]

you are very welcome thanks for stopping by :)

[@CTSCIVIL]

Good to know Thanks for stopping by

[@yoyoud]

thank you very much, you are a great teacher.

[@michaelanthonyabenales]

very good explanation. But what is the importance where the shear and moment curve intersect?? Is there any usefulness on that?

[@CTSCIVIL]

These points are interesting is design mainly. the intersection of the shear diagram usually tells you a local maxima in the moment diagram is present. For simple beams with simple loading, that is translated as follows: at the point where the shear diagram intersects the x-axis, the bending moment has a maximum value. As for the moment diagram intersection, one direct application is reinforcement placement in reinforced concrete beams. when the moment changes signs, the reinforcements changes positions from top to bottom or vice versa.

[@CTSCIVIL]

it is your opinion and I respect that 100% Thank you for stopping by :)

[@Illvuan]

Can you make a video tutorial on how to find singularity function of triangular load?

[@CTSCIVIL]

You are so welcome

[@mexivan71]

would the equations be the same if the triangular load was switch, that is if the higher side of the triangular was at (0,0) and decreased?

[@surfotw10]

Thank you my friend. Your video is so helpful. :)

[@markedminegonzales8568]

sir how to solve the shear and moment of a cantilever beam (fixed-end is in the left side) and a triangular UDL adjacent to it?

[@CTSCIVIL]

You are welcome

[@priyaravipati1271]

sir can you explain bmd diagram for uvl and udl means i can understand how to draw but i dont know about its shape

[@CTSCIVIL]

You are welcome :)

[@michaelanthonyabenales]

also, what if the loading is parabolic instead of triangular?

[@CTSCIVIL]

The moment diagram, mathematically speaking, is a degree higher than the shear force diagram graph or equation. That is if the shear force diagram can be represented by a function of the first degree (straight line), the bending moment diagram will be a function of 2nd degree (Parabolic). Think of it this way, Load diagram then shear then moment. Start adding the degrees up starting with the load diagram. Back to your question, if the load is parabolic (say 2nd degree), the shear will be 3rd degree and the moment is 4th degree.

[@KietNguyen-hy3ys]

but how do we know the sign of the slope (convave up and down) ?

[@rafikmas1]

THANK YOU

[@frankycrankie]

THANK YOU!!!!!

[@robinrai3126]

amazing and super

[@CTSCIVIL]

👌 great

[@dodo12345toto]

what the hell??!!! ... u r smart , but i think u don't have pedagogy