Quick Revision - Alcohols (reactions)

  Рет қаралды 21,047

MaChemGuy

MaChemGuy

Күн бұрын

Пікірлер: 12
@abigailjoeksikei
@abigailjoeksikei Жыл бұрын
Thank you sooooo much from Hong Kong.
@asaiydamati1379
@asaiydamati1379 3 жыл бұрын
this explained it so much more better!
@MaChemGuy
@MaChemGuy 3 жыл бұрын
Thanks for that 🙏
@jacobpinchback2735
@jacobpinchback2735 7 ай бұрын
When balancing the oxygen (for example in combustion) do you have to do it as top heavy fraction or would i still get the marks by multiplying everything out by 2 to use whole numbers to balance.. thanks!
@MaChemGuy
@MaChemGuy 7 ай бұрын
Totally fine to do it either way, unless it’s an enthalpy change of combustion reaction then you must have one mole of the substance
@Aya-l7d
@Aya-l7d 4 жыл бұрын
Thanks for this video! Very easy summary to understand for revision👍
@MaChemGuy
@MaChemGuy 4 жыл бұрын
さばくのあや Great to hear, thanks! That’s the whole point of these videos 😊
@thakanyanesechache4828
@thakanyanesechache4828 2 жыл бұрын
When dehydrating alcohols, why do we remove the hydrogen from the adjacent carbon instead of the same carbon which had the -OH?
@MaChemGuy
@MaChemGuy 2 жыл бұрын
A double bond needs to form
@kimmie8042
@kimmie8042 2 жыл бұрын
thank u!!
@p.p6343
@p.p6343 4 жыл бұрын
When forming haloalkanes by substitution are the products the haloalkane, NaHSO4 and water? In another video it said a haloalkane and NaOH. In a textbook it said a haloalkane, Na+ and water. Please can you explain which one it is? Thanks
@sultan1680
@sultan1680 3 жыл бұрын
It would be the NaOH, this is because the alcohol (OH) is being substituted for a halogen and would result in the hydroxide being a product with the sodium
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