Probably not relevant anymore, but I'm pretty sure some people have doubts around the 9:00 mark about why (1,9) and (3,11) aren't paired together - after all this would technically form -0-1, which would make sense right? However, this isn't a possible pairing because the second pairing you are trying to merge has a value lower than the last value in the first pairing So, if you notice throughout all of the pairings, the right hand value is consistently at least larger than the left hand value for example, (1,3), 3 is greater than 1, (3,7), 7 is greater than 3, (9,13), 13 is greater than 9 This same concept is carried over to pairs with two dashes or differing bits: (1,3,9,11): 1 < 3 < 9 < 11 (2,3,10,11): 2 < 3 < 10 < 11 (3,7,11,15): 3 < 7 < 11 < 15 A pairing of (1,9,3,11) would break this rule: 1 < 9 !< 3 < 11
@Vodallus6 жыл бұрын
Finally someone without a strong indian accent
@AniviaS5 жыл бұрын
Nice to see you using a Pilot Metropolitan ;)
@pslr08044 жыл бұрын
Thanks for help me to clear my exam 😀😀
@UmairKhan-ir5yo7 жыл бұрын
thank you soo much! your teaching style is great :)
@johnt13425 жыл бұрын
This was very helpful! Thank you!
@yaboi_sakurai2 жыл бұрын
Amazing explanation, thank you!
@joshuahew4 жыл бұрын
at 15:44, does anyone know why he draws the line from 2 to 3 instead of 2 to 11?
@nanda_84 жыл бұрын
Same doubt... Could you please tell me why?
@mevlutkelle40832 жыл бұрын
same doubt , the video is good for someone new , but not good for someone who studies for a test
@MuhammadLatif-tf2xp7 жыл бұрын
Thank You so much..... Your teaching style is great.............
@petersonjr80154 жыл бұрын
What about (1,9) + (3,11) at 9:47 ?
@GoneRaiding4 жыл бұрын
yeah i saw that too, (1,9,3,11) are -0-1
@DogeCharger2 жыл бұрын
@@GoneRaiding Probably not relevant anymore, but I'm pretty sure it is because the second pairing you are trying to merge has a value lower than the last value in the first pairing So, if you notice throughout all of the pairings, the right hand value is consistently at least larger than the left hand value for example, (1,3), 3 is greater than 1, (3,7), 7 is greater than 3, (9,13), 13 is greater than 9 This same concept is carried over to pairs with two dashes or differing bits: (1,3,9,11): 1 < 3 < 9 < 11 (2,3,10,11): 2 < 3 < 10 < 11 (3,7,11,15): 3 < 7 < 11 < 15 A pairing of (1,9,3,11) would break this rule: 1 < 9 !< 3 < 11
@rohicr33817 жыл бұрын
Thank you so much..! your explanation is nice
@MeetPatel-lm6wx6 жыл бұрын
at 10:12 why u not take (1,9),(3,11) pair
@berserk89145 жыл бұрын
still wondering man, have you figured this out? also (2, 10, 3, 11)
@e_manue15 жыл бұрын
@@berserk8914 Those have already been written so no need to repeat the same combinations
@berserk89145 жыл бұрын
@@e_manue1 No they haven't been man (1, 9, 3, 11) (2, 10, 3, 11) (9, 11, 7, 15) for example. This exercise goes further.
@e_manue15 жыл бұрын
@@berserk8914 stop the video at 9:30 and you can see he just finished writing two of those sets of numbers in a different order. As for the (9, 11, 7, 15), that isn't a possible combination since 3 symbols change.
@purrconnections753 жыл бұрын
Why didnt you use 1,9 and 2,10- for the 2nd table
@bernadethcasio88327 жыл бұрын
Thank you so much brother 😘😘
@naveenkumawat40395 жыл бұрын
Thanks, your video was helpful!
@megatron35912 жыл бұрын
pretty good ngl
@nehal0767 жыл бұрын
Why 9 is not compared with 7
@atharpathan85276 жыл бұрын
Thankewww. Sooo muchh broo.... 😘😘😘
@Spookameer3 ай бұрын
thank
@Futo210_MCJE2 жыл бұрын
thank u
@kavitagrover90247 жыл бұрын
why did u added 1,1o and 15
@SkillWill227 жыл бұрын
Hi, what are these "don't cares" you talk about?
@myfrnd34577 жыл бұрын
thanks, bro!!
@robertharmon43854 жыл бұрын
bruh not gonna lie you low key sound like Mr. Rogers