Quotient rule (KristaKingMath)

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Krista King

Krista King

Күн бұрын

Пікірлер: 52
@zakmatew
@zakmatew 3 жыл бұрын
This woman deserves an award for best explaining difficult concepts. Thank you and keep up the good work!
@kristakingmath
@kristakingmath 3 жыл бұрын
Thank you so much, Emil! :)
@TSBooger
@TSBooger 12 жыл бұрын
You amaze me. As you post videos, its what I'm just learning in class. My professor is from Hungary and has a short tongue (lisp) and his teaching style is not the best. Thank you for posting! =)
@PureInsanity
@PureInsanity 12 жыл бұрын
Although I finished my calculus I subscribed to your channel so far I love it :) keep up the good work
@cl0wn1cula
@cl0wn1cula 11 жыл бұрын
Thanks helped a lot, didn't think i'd see another one of your amazing vids.
@kristakingmath
@kristakingmath 12 жыл бұрын
You're welcome! Glad I could help. :)
@kristakingmath
@kristakingmath 12 жыл бұрын
Thanks so much for subscribing! :)
@vegetagoku7943
@vegetagoku7943 8 жыл бұрын
You are welcome Krista. Can you make a video explaining binomial probability?
@Postcalculus
@Postcalculus 11 жыл бұрын
You don't need to memorise the quotient rule if you rewrite the denominator as a negative exponent, and then it is simply the product rule! :)
@zajdragon6173
@zajdragon6173 10 жыл бұрын
Awesome!!! And again it makes so much more sense now that I watch your videos. You explain very very well. I thank you so much, I need this for my calc 1 class. Thanks a Ton!!!
@kristakingmath
@kristakingmath 10 жыл бұрын
I'm so glad it helped!!
@0503696580
@0503696580 7 жыл бұрын
wooowwww!!! what a brilliant explaining! thanks a lot a lot and a lot ^_^ , and keep going
@hg2.
@hg2. 7 жыл бұрын
Excellent! I'll come here when I need a refresher on Quotient Rule.
@kristakingmath
@kristakingmath 7 жыл бұрын
Glad you liked it! :)
@kristakingmath
@kristakingmath 12 жыл бұрын
That makes me so happy! :D You're welcome!
@zainislam554
@zainislam554 3 жыл бұрын
i didn't understand the last part in which you found the common denominator. can we please explain it?
@c.james1
@c.james1 11 жыл бұрын
Learning with you is a treat, you are a great teacher and are very pretty too :)
@Will-bb4zy
@Will-bb4zy 9 жыл бұрын
nice as always!!! thanks :)
@vegetagoku7943
@vegetagoku7943 8 жыл бұрын
Thank you Krista. this video was excellent.
@kristakingmath
@kristakingmath 8 жыл бұрын
Thank you so much Vegeta!
@SandunilJayasinghe
@SandunilJayasinghe 10 жыл бұрын
wow,you are such a good teacher!l Love your teaching!
@kristakingmath
@kristakingmath 10 жыл бұрын
aww!! thank you so much!! :D
@genesilopez6045
@genesilopez6045 10 жыл бұрын
your the dream girl of mathematicians !!!!!
@zickrap5965
@zickrap5965 4 жыл бұрын
I love this! You helped me so much!! :D I’m in love with your eyes!! 💙 d:
@shubhamkannaujiya5940
@shubhamkannaujiya5940 8 жыл бұрын
thanks
@riacardi7011
@riacardi7011 12 жыл бұрын
Do you have a video on Sinusoid graphs?
@JAFFER3657
@JAFFER3657 9 жыл бұрын
cool i didn't understand it in my college lecture you teach me easily thanks alott
@jamalnaser1933
@jamalnaser1933 9 жыл бұрын
Could you use the product rule to come up with same answer?
@user-nx1lj3ig7w
@user-nx1lj3ig7w 10 жыл бұрын
at 7:22. isnt (x) x (cx^-2)= cx^-1???? you put cx/x^2 im really confused
@kristakingmath
@kristakingmath 10 жыл бұрын
your and my values are actually the same! :) if you start with cx/x^2 and you cancel an x from the numerator and denominator, you'd get c/x, which you could rewrite as cx^(-1). :)
@user-nx1lj3ig7w
@user-nx1lj3ig7w 10 жыл бұрын
ohhh i see, thank you and i hope you don't mind my other 100 questions in the future, just kidding :D
@herbcruz4697
@herbcruz4697 8 жыл бұрын
Just out of curiosity, before taking the derivative, would it have been easier to first multiply both top and bottom of the original function by x?
@kristakingmath
@kristakingmath 8 жыл бұрын
+Herbert Cruz Yes, that would've been a great way to make the problem easier right from the start. Good thinking!
@kristakingmath
@kristakingmath 12 жыл бұрын
No, sorry about that.
@biscaynebuckets
@biscaynebuckets 10 жыл бұрын
Thank you so much!! Awesome smile btw:)
@shubhamkannaujiya5940
@shubhamkannaujiya5940 8 жыл бұрын
you helped me very much
@kristakingmath
@kristakingmath 8 жыл бұрын
Glad I could help!
@ngalexngalex
@ngalexngalex 9 жыл бұрын
May i ask sth? when to use the quotient rule? just like using the L'H rule to solve the limit question eg. Lim f(x)/g(x) =0/0 why cant we use the quotient rule? that just mess up my mind =[
@herbcruz4697
@herbcruz4697 6 жыл бұрын
ngs kenneth L'Hospital's Rule is only used for finding limits, when getting an indeterminate form of either 0/0 or ±inf/±inf. L'Hospital's Rule, however, does not say that the limit of the function is equal to the limit of the derivative of that function. Rather, it says that the limit is equal to the limit of the ratio of the derivatives of the top function to the bottom function, after establishing the fact that the limit turns out to be one of the indeterminate forms, as described above.
@abedaburomman367
@abedaburomman367 8 жыл бұрын
Just a friendly comment, I think you left out taking the product rule of CX^_1 Please correct me if I am wrong 😬
@kristakingmath
@kristakingmath 8 жыл бұрын
You don't need the product rule for the derivative of Cx_1, because C is a constant. So it's like taking the derivative of 3x. The derivative would just be 3, so in the same way, the derivative of Cx_1 would be C.
@abedaburomman367
@abedaburomman367 8 жыл бұрын
Krista King thanks, I didn't assume that C would be the constant thank you for replying back Your videos are extremely helpful. Thanks again
@kristakingmath
@kristakingmath 8 жыл бұрын
You're welcome, glad I can help! :)
@junals03
@junals03 10 жыл бұрын
can you make a quotient rule with trigonometric derivatives
@kristakingmath
@kristakingmath 10 жыл бұрын
this might help! Chain rule for derivatives, with quotient rule :)
@billtruttschel
@billtruttschel 5 жыл бұрын
This is not a rational function because the denominator is not a polynomial.
@ThePinoyMamba
@ThePinoyMamba 12 жыл бұрын
:)
@kristakingmath
@kristakingmath 11 жыл бұрын
:D
@vizestroowash
@vizestroowash 10 жыл бұрын
You remind of laurel from Arrow, only more beautiful.
@armanazimi2587
@armanazimi2587 7 жыл бұрын
OMG you are so sweet.
@M1k4e
@M1k4e 12 жыл бұрын
so hot
@MichaelMantion
@MichaelMantion 12 жыл бұрын
:)
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