R3.2.15 Predict and explain the products of electrolysis of aqueous solutions [HL IB Chemistry]

[@TamaraNawaiseh]

Shoutout to everyone here hoping to pass their chemistry exam, good luck guys we're almost done💪💪💪

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[@zairejerry7310]

@Johnny Zyaire yup, I've been watching on instaflixxer for years myself =)

[@ShawnCheah]

i'm here the day before my chem exam tmr :(

[@Mrdark20100]

Exam tomorrow and I really can't express how thankful I am. THANKS TEACH

[@ShawnCheah]

same here, accept in 2022

[@strawberryskates]

Preparing for the november exams without a teacher and you are an absolute life saver

[@ibchemvids]

+Tani Maheshwari Gulp - I hope the exam on Friday went well!

[@mnbvcxz786453]

I ACED MY CHEM TEST BECAUSE OF THESE VIDEOS.... :D You are the best mate...x I now have a predicted of a 7... :D Thanks from Tanzania...

[@DJRavinszkha]

you sir are an absolute legend

[@shreyassuresh7924]

This helps tremendously. Some textbooks don't even have this information stated (ex. Zumdahl). Thank you!

[@hang2091]

Chem exam in 2 and a half hours! thank you mr richard thronley your my hero!

[@ibchemvids]

hang2091 I am more sandwich than superman.

[@johnyfausman959]

@@ibchemvids Then you are a heroic sandwich.

[@neerja4211]

i was not able to understand this process but after watching ur video sir i really understand the process thanx a lot sir

[@sajjadalimi2106]

Sir you are using H+ and OH-. I was thinking is it the water that is being discharged in the negative electron for NACl for dilute one, because water is more likely to get the electron, you were showing the H+ and then you reduce that into H2(g) i was thinking that is it the water or some acid in solution that is being reduced in negative electrode, Thank you :)

[@aurielle112]

When you're trying to evaluate which products get formed based on info in data booklet... which H2O do you look at?? There are -0.83, +0.40, +1.23, and you used 0.00 as well...

[@ibchemvids]

You only need to know positive and negative electrodes, not the use of the words cathode and anode - this is true for every IB exam so far with the syllabus.

[@MegaAdytya]

Only halogens (in a concentrated solution) would be able to give of their ions more easily than the hydroxide. In this case, chlorine. Hope that helps.

[@Mrjarnould]

Thank you for responding so promptly! I have an end of unit test on this tomorrow and its 23:45 where I live :(

[@ibchemvids]

Glad I could be of some help!

[@tinska12]

In the first example, Hydrogen ions get discharged because they have more affinity for electrons. However if we consider a Daniell Cell (Zn|ZnSO4||CuSO4|Cu, NOT Zn|H2SO4...), in a "recharge" configuration, would that also mean that Hydrogen gets discharged, because Zn2+ + 2e -> Zn is -0.76V? But some sources say that Zn|ZnSO4 is reversible, and it is used to electroplate Zinc? OR is it that during recharging of cell, some hydrogen will be discharged, but because H ions are not created, they get exhausted?

[@elcour]

So about the concentrated NaCl. Why is it that Cl is preferentially discharged because it has a higher concentration, but the Na is not?

[@ibchemvids]

If Na was produced (and maybe it is) then Na + H2O --> NaOH +1/2 H2 so the Na would turn back into Na+ (since Na reacts with water), releasing H2 - which is what happens!

[@sung-holee2316]

Mr. Thornley, I have a question: For the electrolysis of concentrated aqueous sodium chloride, why is Cl2 discharged instead of O2 exactly? Because even though it's concetrated, it's still hydrogen that is given off at the cathode instead of sodium metal so why is it different for the anode?

[@JanaRulz]

SO42-(aq) + 4H+(aq) + 2e- --> H2SO3(aq) + H2O(l) is in the data booklet

[@TheNewGenGamers]

i actually wanted this only....thank u so much

[@setht.2308]

At 1:38 you point out that H+ is the lowest on the list. If this were the case it would always be the lowest on the list, and there would be no other cation that would be discharged instead. Don't you mean the water reduction reaction at -.83V as the boundary. Suppose if it was Zn cation, then that would be discharged instead of Hydrogen?

[@whadoyoucare]

awesome video richard!

[@MultiThobani]

Legendary video

[@hexagxn1314]

I love your videos... just one question. my teacher alwasy explained to me that I had to name the elctrode cathode and anode. is this actually required by the IB since I have not seen you explain it in one of your video?

[@allyc2127]

Hi Mr Thornley, I was just wondering how you know which water equations to use because I have seen many variations with some Textbooks using the -0.83, +0.40 or +1.23 values?

[@ibchemvids]

No idea sorry - i think it must be more complicated that the IB - maybe hydration effects the values!

[@GiuliaPrivato]

I don't understand... which one gets lighter in the CuSo_4 with copper electrodes?

[@vivekfrancis7198]

What concentration of NaCl will be considered dilute and what will be considered as concentrated?

[@ibchemvids]

In the past the IB have forgottent to mention conc or dilute and had to exclude the question. In reality both gases are always produced with electrolysis of NaCl(aq). The more concetrated the solution, the more Cl2 evolved and the less O2(g)

[@vivekfrancis7198]

thank you so much for your reply

[@ileymae]

would it be possible for the sulfate to be discharged as marshall's acid? or am i thinking of something totally different?

[@netcordhater5969]

What do you mean at 3:30 by since OH- makes O2...?

[@ibchemvids]

the equation for this is in the data bookley (electro potentials table) turns oh- to o2

[@netcordhater5969]

Oh okay thank you!!!

[@A1v1n1]

SO4^2- does nothing as it takes a noble gas configuration, and would prefer to stay that way

[@thomasmaxfield4994]

Just curious what you mean by that: the molecule shape makes it inert or its in a very low energy state like CO2?

[@lulusaa7499]

Thanks for teaching!

[@MusicReviews1960]

Great lesson!

[@ibchemvids]

no idea - sorry - but even if Na(s) was discharged it would react to produce H2.

[@swiftlaker6]

That was beast

[@Mrjarnould]

I can't find OH^- -e^- --> O2 + H2O :(

[@lathag4293]

Wow thank u man

[@ibchemvids]

p12 of the data booklet, +0.40V !

[@clementchiu6620]

2:09 where the fuck did that series appear out of what the fuck

[@ibchemvids]

Indeed - it is a bit random - it is in the review guide. Frankly it makes little sense to me and is of only limited phucking applicability!

[@ibchemvids]

MYSTERY SOLVED? (Are you sure - or did you pull this out of your AsH3)

[@ibchemvids]

yup, but OH-

[@tjpatel249]

So4 2- + 4H+ +2e- -----> So2 + 2H2O :D

[@doggosmemeshed6924]

am i the only one that came here out of wanting to learn this on my free time and not bcuz of a test?