Thermodynamics: Steady Flow Energy Balance (1st Law), Nozzle

[@PM-xd6nv]

I have a final tomorrow. Thanks a lot for your help. Your channel is very underrated. Keep up the great work!🤗

[@NilupulieSumanasiri]

Im watching this on 2020, but Im so glad I found this channel! ❤

[@gabrielatem1121]

I almost cry 😭, because it too me 4 months to understand this concepts, thanks a lot for your lecture❤

[@Premium-y9m]

Why did we substitute the RT/P? Since it was a "specific" volume? Isn't "volume" & "specific volume" different so how can it be substituted? Thank you, I really want to understand it.

[@praxedogacrama]

I was confused when the entholpy's unit is kj/kg, i believe you meant to say kj/kg*k. For my book, the entholpy, h, = 119.48 btu/lbm and converting it to kj/kg is 277.91048 kj/kg. However, if you convert entholpy, h, = 119.48 btu/lbm to kj/kg*k is 500.2389 kj/kg*k.

[@kaeshaun4037]

i am so glad for this channel, its helping me alot for college

[@vanessajaneponce509]

when 200.0g of chromium is placed in 200 g of water at 25 degrees Celsius in a coffee cup calorimeter, 6690 j of heat is absorbed by water, the specific heat chromium is 0.449 j/g-k

[@garrettphelps5525]

Well done. Thank you for the content. Much appreciated.

[@stma8258]

Hi all, does someone know why the outlet speed is provided? is it not possible to calculate it somehow from the other inputs? thanks

[@patrickledgerwood5163]

Helpful video thanks

[@Matthew.Moulton]

When you read off the table to get 437K did you assume the outlet pressure was the same as the inlet pressure?

[@irfan8348]

why u didnt say to use interpolation to find T2 ??? make me confuse :D

[@ant0625]

in my "thermodynamics and engineering approach ninth edition" this is 5-28 by the way people

[@rayllenepueblo8963]

Hi. What is the reason for cancelling the mass?

[@josemaldonado2769]

from that 1st law equation she used, the change in velocity part should have been multiplied by an m_dot. then dividing mdot from both sides the mdot goes away

[@angelgonzalez8170]

what

[@AustinJohnson-he5cc]

So what would the conversion factor be for ft^2/sec^2 to BTU/lb?

[@jlewis499]

The conversion factor for ft^2/sec^2 to BTU/lb used in problems in Michael Moran's Fundamentals of Engineering Thermodynamics is (1lbf/32.2 lb-ft/sec^2)(1 BTU/778 ft-lbf). For example 1,125,000 ft^2/sec^2 would convert as follows: (1,125,000 ft^2/sec^2)(1lbf/32.2lb-ft/sec^2)(1 BTU/778 ft-lbf) = 44.9 BTU/lb.

[@alifarahmandi9684]

😅😅 Thanks