JNTU M2 R22 Method of Variation of Parameter in Telugu || JNTU M2 Pakka Question ||

[@jaswanthbobbili8143]

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[@ramareddymathsacademy]

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[@VarshithaLucky-wj2wc]

Xsin2x/,2 mam B value

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[@ramareddymathsacademy]

Ok

[@Bhanu-j7x]

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[@Samreen-ll1lr]

But A=-1/4log|cos2x| And B=x/2 right But mam you have taken only 1/2 in last general solution xsin2x/2 not sin2x/2 I am getting like this.. Y = c1cos2x + c2sin2x - cos2x/4log|cos2x|+xsin2x/2 Which one is correct mam?

[@KorraLakshmanaik-db9qt]

You are correct

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[@ramareddymathsacademy]

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[@Vardhini_.]

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[@ramareddymathsacademy]

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[@SravanBhattu]

Xsin2x/2 mam