First-order reaction (with calculus) | Kinetics | Chemistry | Khan Academy

[@j316divinagraciaiii]

Which Khan Calculus video should I watch to understand this one?

[@jonwindle8778]

+Jose all of them

[@themooseyoyos]

The one with Calculus in it

[@satyajeetpatil8177]

This is an application of differential equation. You need to go through Derivatives, Integrals before you do Differential Equations

[@christinesuwandy3005]

THANKS !!

[@coriiuu2886]

im in ap chem and ap calc ab and about to have my chem test, i was curious

[@dirtroad4229]

I don't understand what is "d" starting at 1:25 ? What happened to Delta symbol above?

[@ruverneto7459]

it's a derivate, from calculus

[@zebashaikh8499]

Nathan Parrish 'd' is for the instantaneous rate

[@zebashaikh8499]

Nathan Parrish 'd' is the smaller change cuz its instantaneous whereas delta is the larger change in concentration

[@chemistryART]

kzbin.info/www/bejne/sHStcn94l7yYgq8

[@my80yearoldman]

This was blessed. Thanks man. #APSC132

[@iqraurooj6516]

I am a Tiger what is APSC132

[@my80yearoldman]

Queen's University 2nd Sem 1st year engineering chem.

[@rjravaz8283]

Rather than go through all the steps will the last equation work?

[@thegunslinger966]

This is how you calculate the physics of starkiller base

[@thelearner3962]

For the differential equation part (the part when he integrated both sides with different limits), I don't really understand why does it work since both sides are of different quantities. For me I will just integrate indefinitely to obtain a general equation with c then use [A]_0 to complete the equation.

[@chemistryART]

kzbin.info/www/bejne/sHStcn94l7yYgq8

[@tobywang9679]

Your method also works. He uses accumulation function which has been discussed in AP Calculus.

[@khusnur_iffat]

all vedios sound is very low that we cannot heear them rightly

[@mohimaahmedsneha3860]

Why is the line of the graph straight and going downward? Can anyone pls explain

[@tobywang9679]

The graph is the same as a linear function y=mx+b. In this case, ln[A] is the y in linear function, t is x, and -k is m. Since k is positive, -k must be negative, which makes the graph go downward.

[@tobywang9679]

Remember, the equation is ln[A]=-kt+ln[A]0

[@zechlee9098]

Can't we do this without using calculus?

[@tobywang9679]

No, lol.

[@tobywang9679]

Learn some calculus is always helpful on learning ANY sciences.

[@zechlee9098]

@@tobywang9679 we don't have calculus in our syllabus tho, but anyways I'm learning it

[@wedfrest]

I still can't get my head around why you take the natural logs. Is this some log law I've missed?

[@tenorosmanaj5588]

+Chewie Lewie they are tabelar integrals

[@goclbert]

It is the integral of (1/[A]) d[A]. If you know your calculus, then you know that the integral of 1/x dx = ln(x). It's the same thing.

[@wedfrest]

goclbert yup cheers

[@shahbukhari2573]

Is there a way to do this without calculus?

[@alial-musawi9898]

Shah Bukhari yep, just stick with the derived equation ln([A]_t/[A]_0) = -kt

[@aduraedosa]

is this like college level stuff in america?

[@shahbukhari2573]

This is first year level chemistry, how is it in your country?

[@AdityaSharma-lf9xj]

@@shahbukhari2573 It is taught in class 12 in India..

[@Wolfeywolf16]

Please slow down....youre working through this too fast

[@ewoutbijlsma5254]

setting -> speed 0.5