Realizing Half Subtractor using NOR Gates only

Digital Electronics: Realizing Half Subtractor using NOR Gates only.
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[@barsilgen120]

Thank you sir for wonderful explanation!

[@remyaunnikrishnan2037]

why is difference not realised in the same way as half adder using nor gates

[@gauravbhandari9304]

There is no need of 5 nor gates we have to use only 4 nor gates for find xor of A and B

[@dipjyotibalomajumder9908]

In the previous video of Neso academy the circuit used to form ExOR gate to form half adder by NOR is not used here as to get the borrow that from that circuit we need to use another NOR gate so overall no of gate increased.

[@YashankKumaryk]

why didn't you find borror here first like you did in half adder where u find carry first so as to reduce the no. of or gates??

[@rajeshprajapati6662]

I tried and I think that will require more number of gates compared to the video. He's showing the optimized ones only.

[@jainandanmodi1124]

please upload the video on full sub using nand gate.

[@abdxlive]

Unlike A'B Above We May Have B'A Down Then Why Are We Using Two Extra NAND Gates At Right Side 🤔

[@gusp5762]

Where is the next lecture where you say you will implement the full subtractor usin nand gates? cant find it

[@rachitbansal1555]

Voice of audio in the video is not clear

[@debasiskhadanga862]

How to know there is on 5 gate only

[@anshuleshpandey9042]

Where is full subtractor using NAND/NOR gates ?? not able to find it.

[@YashankKumaryk]

ryt!

[@divyabasati4969]

why we have to use 5 nor gates here????

[@KunwarBharatSingh]

because 5 gates are able to give us the equation which is needed to satisfy here

[@ritikshrivastava9442]

always try to implement things with minimum number of gates que in may be asked like this implement half substractor using minimum numbers of nor gates only .

[@Dop-df8yl]

I thought of using nor gates the way they have been used in implementing half adder that would give me a xor b...and for borrow that is A'B ..I just used another nor with B' and A ...so ( A+B')' = A'.(B')' = A'B ...is this correct or i made some mistake there 🥲