Ext2 Inequalities: Elegant Proof of the AM-GM for n variables

  Рет қаралды 1,297

Mathema Education

Mathema Education

Күн бұрын

Пікірлер: 6
@utubeid7861
@utubeid7861 4 ай бұрын
Waaaaaaaaao what a nice proof.
@SimchaWaldman
@SimchaWaldman Жыл бұрын
Love this proof!
@lavieag6172
@lavieag6172 8 ай бұрын
🤩
@ahmedlutfi4894
@ahmedlutfi4894 10 ай бұрын
i didnt get the logic behind assuming Xk =the AM of Xk-1 how could you be sure that it will be equal to 1
@MathemaEducation
@MathemaEducation 10 ай бұрын
Well from our assumption of the k-variable case, we have as a FACT that the statement is true for ANY k arbitrary non-negative real numbers x_1, x_2, ..., x_k. So if it's true for ANY of them, then it would certainly be true for k specific ones. I will only pick one of them to be specified, and will choose x_k = AM of the other k-1 terms. It all stems from the assumption that it is true for ANY k-ARBITRARY non negative real numbers.
@Ryfuuu
@Ryfuuu 13 күн бұрын
@@MathemaEducation I'm sorry for the inconvenience, but i still don't get it, i'm not that good at maths and i'm trying to hopefully get better, is there any chance you could please re-explain it for me?
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