Excellent sir Really easily understood. Thank u sir
@BS-eu9do11 ай бұрын
Thank you 👍
@LearningCS-jp4cb Жыл бұрын
T2 was added because it was never committed
@HimanshuKumar_247 жыл бұрын
Thank you so much, very well explained, to the point.
@1020gagan7 жыл бұрын
miny miny miny miny thanks :P
@farzeb11985 жыл бұрын
😂😅😂😂😂😂
@JohnDoe-kj2cs2 жыл бұрын
Jai Shree Ram
@herahassan28187 жыл бұрын
amazing. best explained
@s1vc4n9 жыл бұрын
Good explanation. Thanks.
@rishabhgarg73886 жыл бұрын
How atomicity is maintained in this scheme(check pointing) because the operations which appears before checkpoint address being done permanently and operations after checkpoint of active transaction are undone. So some part of active transactions is done and some doesn't. Please clarify.
@saketdhakar8147 Жыл бұрын
did anyone got any answer for this doubt?
@farzeb11985 жыл бұрын
Wanna have idea about check points characteristics
@LearningCS-jp4cb Жыл бұрын
Can someone tell does it matter if undo list is done before redo list or vice versa?
@ahbarahad320311 ай бұрын
You have to do undo list first
@darkexodus64043 жыл бұрын
At 12:36 for T3, why A = 9? Shouldn't it be A = 1 ?
@ajaykumarsoni312 жыл бұрын
Because T3 has committed after checkpoint so need to be redo.
@bestpaawanful7 жыл бұрын
T2 and then T4. Isnt it??
@biginepallinagasai44034 жыл бұрын
In this explanation, 8:33 it is provided that all the transactions in the undo list will be undone in the reverse order but while solving the problem it was not taken into consideration.
@tanieadas3 жыл бұрын
@@biginepallinagasai4403 Reverse with respect to log records order not the list order. There is no wrong in the solution.