Rectilinear motion | Problem in Uniform Acceleration | Solved in Tamil

[@ajay.a3516]

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h-1 in 10 minutes .find its acceleration . explain sir

[@LetsExploreCivilEngineering]

Acceleration= (v-u)/t,

[@ezhilarasan3776]

Sir..Push over analysis& Time history analysis concept pathi solunga

[@LetsExploreCivilEngineering]

Thank yu .. Sure..will upload a video regarding seismic analysis near future ..

[@gunapathran9240]

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[@CIVNijanthanM]

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[@utt6076]

acceleration AB = BC nu epdi eduthukitinga bro? BC ku acceleration 0.067 varuthu

[@LetsExploreCivilEngineering]

No brother.. Its uniform acceleration from A to C..

[@sathyanarayanan2159]

The train starts from A and crosses B and reaching C with uniform acceleration which is found out in path AB(because in path AB only we have datas like initial velocity, distance and time so we can use that formula).. after C brakes are applied and the acceleration quantity changes. The path BC is having uniform deceleration from B to C.

[@utt6076]

ok brother. i just tried to find acceleration of BC using B-velocity=15 BC-time =150 secs BC- distance = 3000 uniform velocity na above data substitute pannalum ans same ah varanumla! athan en doubt.

[@LetsExploreCivilEngineering]

Ama varathu bro..

[@vishnusenthil9918]

​@@LetsExploreCivilEngineeringsame doubt for me to bro

[@Ragulmohan]

t=2000 nu varuthu last total timetaken

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