Reduction of alkynes | Alkenes and Alkynes | Organic chemistry | Khan Academy

[@kylepalmer9432]

This is the first video on KZbin that I've found that fully explains the mechanism behind this reaction, you see all these videos about solvated electrons but no one ever explains what's actually happening :)

[@negihere232]

Well actually others are teaching correct and he told the wrong mechanism as solvates electrons are a major part of this reaction.

[@arwa9715]

You are freaking awesome! Thank you so much for your time and effort!

[@user-hp1yx1up4i]

Thanks 😭😭😭😭😭😭

[@SatyamSingh-nq2il]

Great...

[@MaryaM-ov9bq]

What an amazing vedio!!!!!!!

[@nicolebonilla3855]

Thank you so much!! You saved my life!!

[@birdman1265]

NIce video!! Helped a lot!!

[@rishabhpandey3822]

Thank u very much it was really helpful

[@wakylaugh]

Love this!

[@mychanel180]

At 6:20 how come the Na just donates an electron shouldnt it form a bond with the carbon?

[@shariqmajeed8709]

U are best

[@thesciencehubskb]

When do you use NH2/Lindlar as opposed to H2/Lindlar

[@marvel438]

What will be the product when we reduce isocyanide R-NC with LiAliH4/H+. What is the mechanism?

[@nikmartinneau]

7:07; I believe you are referring to an alkyne and not a alkene, thus the triple bond. But a truly helpful video, nonetheless. Thank you.

[@annalerman4255]

your awesome

[@jabased]

good lookin bruh

[@Tundra0128]

good shit ma nigga

[@ehudsolomon1720]

but where goes the fifth electron after the hydrogen was added?

[@tehseenfatima9496]

can we say this is example of carbon carbon bond cleavage reaction

[@negihere232]

Well you didn't explain why nh3 is used as a solvent in this reaction. According to your mechanism the na is directly reacting with the alkyne hence you mean that this reaction can also be carried out without any solvent. Which is definitely wrong. Please do not teach wrong things on KZbin

[@mimori8]

i t de xz ord

[@zba0104]

great !