Refrigerators, Heat Pumps, and Coefficient of Perfomance - Thermodynamics & Physics

[@TheOrganicChemistryTutor]

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[@fangyini5950]

best refrigerator video I can find, thank u so much!!

[@devendrabaghela5341]

All is perfect. But in last example, you used a formula to calculate total heat transferred to hot reservoir as k=QH/W, where as you have introduced formula for coefficient of performance as K=QC/W in the first example. It creates confusion, which one is correct, if formula given in example 1 is correct then in example 3 the heat transferred to hot reservoir must be equal to 12500J. And heat taken out from cold reservoir equal to 10000J,

[@khaledsissi3762]

in the last example he used K=Qh/W because he was solving for a heat pump, whereas in the previous example when he used k=Qc/W, he was solving for a refrigerator.

[@punithr8661]

​@@khaledsissi3762 how are both different? They work the same right?

[@godhelpme8977]

Efficiency is 1-T2/T1=W/Q W=w/k P=Fv

[@manikantan4809]

what are you talking about shat is p and w/k

[@ram_pande8039]

Shukriya love it

[@aryansoni1586]

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[@andrembro9063]

Thanks

[@landerbanez263]

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did u end up passing?

[@landerbanez263]

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Thank you so much sir.

[@amitmahato8101]

thanks bro

[@seujiprene6138]

how does the system behaves if we use the heat pump to recover heat from an exhaust fluid which is at a higher temperature than the heat sink. It is normally a spontaneous flow, and will not require energy input, but will instead output energy as work done. However, can we still use a heat pump in this case to increase the heat gained by the cold reservoir? For example to recover heat from some exhaust fluids which are at higher temperatures compared to the heat sink.

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you saved my ass, again!

[@Nategreat923]

Hi! Would you please consider doing a short video on the "Galilean Transformation"? Neil DeGrasse Tyson used it in a tweet today and I'm having trouble understanding it. Thanks!

[@seujiprene6138]

In a real life application of the heat pump, what temperature do we consider as that of the hot reservoir TH. In a heat pump for example, lets say we circulate water at 298K in the hot side(condenser of heat pump) which heats it up to 333K for home use. I guess Tc in this case would be the outside temperature, but which temperature in this case should we consider as TH?

[@YASHMAHALINGE]

5:20

[@josuegutierrez3906]

why in the first problem in the coefficient of performance formula you didn't multiply by 100% ? for part a) Thank you! very useful video

[@gurshrutisingh8412]

JG

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[@alyssacastillo5479]

Hi can you do variables? Pls it's my birthday tomorrow

[@loopingmoon1444]

he did not do variables :(

[@holthuizenoemoet591]

How does this work with respect to the conservation of energy? it seems to cheat

[@golirida620]

Cop = t1 / ( t1 - t2 ) ???????

[@anilsharma-ev2my]

At which temperature ice cracking the steel tumbler inside the fridge 😰😁🔄🔀🌀⚡✴

[@lukybird6085]

🎖

[@lukybird6085]

🎖

[@Kobs.A]

You need to show us your face, you saved me

[@JRockTT]

Wouldn't the sign of the work be < 0? If work is done ON the system, then the sign of the work is positive because the system is gaining energy at the expense of the surroundings?

[@muneibrauf9779]

formulas for internal energy diffrent in physics and chem

[@JRockTT]

@@muneibrauf9779 Would you kindly give examples?

[@tusharsharma428]

That is the case in thermo-d of chemistry...... In physics work done on the system is negative

[@JRockTT]

@@tusharsharma428 That means that the system loses energy when work is done on it: a system loses energy when the surroundings (an outside force), transfers energy into it. This is precisely the opposite of what happens.

[@tusharsharma428]

@@JRockTT yes, in the physical world we want machines to do work for us. That's why we consider it +ve.That's how I remembered it.

[@frehiwotgetachew542]

Ur so sweet