Ans for qus 3 is perhaps wrong here. It should be (a+ab)^+ since the regex in the video is also accepting epsilon which is not desired. Education 4u must post the correct answers in comment box if there is any mistake in the video.
@mufeenashahul46372 жыл бұрын
Please write, correct ans, please
@sairamgreeneye90964 жыл бұрын
I have watched some of the lectures those were very understandable thank you ma'am
@deepakdeshmukh20134 жыл бұрын
(a+ϵ).(b+ba)*. Mam How to write this regular expression to simple English.
@newspresentersacdemybd87862 жыл бұрын
If the R:E: for number 3 is= (a+ba)* then whether it would be wright or wrong?? Plz let me know as soon as you can.
@nithinjohnson23182 жыл бұрын
No, that would be wrong. The question says, the language should start with 'a'.
@DirasatLanguage5 жыл бұрын
Great lesson
@beingyourself4553 Жыл бұрын
third question may be wrong 3:19 ,a(ab)*
@8LuCiia84 жыл бұрын
Amazing. Thank you!
@shivendratripathi83064 жыл бұрын
In question 3 it should be + instead of a * as we have start a string from a and empty string is not accepted na?
@archanamahanty85617 ай бұрын
Pls can you find the set of strings for the regular expression (aa+b)*and (bb+a)* And also (aa+b)*(bb+a)*.
@ElifArslan-l9g Жыл бұрын
thank you
@sandeepvineelaresort46364 жыл бұрын
Thqu bhanu mam
@harinisridharan58804 жыл бұрын
In the 5th example why can't we write it as (10)*
@deblinachakraborty12323 жыл бұрын
its because other combination like 100 or 110 will not be accepted by (10)*
@newspresentersacdemybd87862 жыл бұрын
Bro, (10)* is totally wrong right here, suppose 10101010, which is a RE of (10)*, then have a look ,there are 01 string inside.
@mufeenashahul46372 жыл бұрын
Miss, in 3 rd exmp, epsilon not accept, any One know correct ans
@muneebnadeemabbassi32952 жыл бұрын
a(a+ba+ab)*
@prashantrajput48813 жыл бұрын
(0+1)*(11+10+00) Ma'am example no.5th ka R.E esa bhi likhh sktaa ha
@newspresentersacdemybd87862 жыл бұрын
I think no bro, 011 is a valid expression for you RE and here 01 string is remaining!