Relation & Function Class 12 | JEE Main & Advanced

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JEE Nexus by Unacademy

JEE Nexus by Unacademy

Күн бұрын

Пікірлер: 296
@JEEnexus
@JEEnexus 5 ай бұрын
The PDF of session will attached to the link pinned in the Telegram Channel:- t.me/JEEnexus
@SakshamKR-zy1wi
@SakshamKR-zy1wi 5 ай бұрын
Thank you bhai ❤
@IITIAN_IAS_Motivation
@IITIAN_IAS_Motivation 4 ай бұрын
sir iska PDF nahin mil raha hai pls help team pls tg bhi check kiya content wala bhi
@novazx5193
@novazx5193 Ай бұрын
Sir pdf nhi hai telegram pe
@sanatanisandeepxyz
@sanatanisandeepxyz Ай бұрын
Sir PDF nahi mila 😢
@BenStokes1234
@BenStokes1234 2 күн бұрын
1:45:04 1:53:22 1:53:31 (🌟) 2:00:47 2:04:39 : Onto koi bhi sawal : Range = Codomain krdo bas... Codomain diya hoga, range nikalna hoga.. 1:54:09 : To find Range of y=f(x) : express x=f(y) (express x as a funcn of y) and then find all those values of y for which x is defined [ in x=f(y) ] 1:55:31 🌟 - 2:00:18 One-one / Many-one : M1 : Graph. 1:46:05 1:48:30 M2 : f(x2) = f(x1), (1:46:26 ) aur agar x2=x1 ke alawa koi bhi soln aa jaye then funcn is many one... 1:50:10 M3 : Make rough sketch of curve using AOD 2:26:24 2:21:52 : Pattern dhundho 2:36:53 : f(g(x)) and both are piecewise defined. Step 1 : in f(x), replace x ➡️ g(x) Step 2 : Draw graph of g(x) Step 3 : 2:44:30 : Inverse of a function 2:57:13 3:06:08 : g(f(x)) = x ➡️ g(x) is inverse of f(x) ⚠️ : 3:03:55 Solving Hack : 2:51:15 🌟
@Sassy_657
@Sassy_657 5 ай бұрын
1:36:00 method to find equivalence relation 2:32:01 must revise 2:50:55 trick 2:54:57 revise 2:57:04 imp 2:58:45 definition question 3:02:51 checking true value
@zaramuhx
@zaramuhx Ай бұрын
doing the lords work
@StudyModeActived
@StudyModeActived 5 ай бұрын
Sir , rather than making one shot , a series of lectures covering all topics in detail for a chapter will be useful..(just a humble request)
@akashs7524
@akashs7524 5 ай бұрын
Yes , I agree...
@Palakpukku
@Palakpukku 5 ай бұрын
I also agree
@GaganDwivedi-os5td
@GaganDwivedi-os5td 5 ай бұрын
Koi n Bhai One shot isiliye best h kyuki one shot dekhle jee main ke 80-90 percentage to ho hi jate h Isliye pehle focus on jee main😊
@HITANSH_JEE2
@HITANSH_JEE2 5 ай бұрын
​@@GaganDwivedi-os5td maths ke 80-90%? Air 100< vale ho kya? Kuch bhi ?? 😂
@GaganDwivedi-os5td
@GaganDwivedi-os5td 5 ай бұрын
@@HITANSH_JEE2 bhai main ke to itne bn hi jate h bas advance mein thodi problem ati h
@Vedant-x2q
@Vedant-x2q 5 ай бұрын
Quality learning better than most of the other coachings
@Nitin_gotnochill_18
@Nitin_gotnochill_18 4 ай бұрын
1:09:05 sir correct answer is option a only reflexive
@MohanaPriya-qn1rm
@MohanaPriya-qn1rm 2 ай бұрын
Yes, he's right
@Abhi-w9b
@Abhi-w9b 2 ай бұрын
But x/2 should be less than x so it is not reflexive as sir said in starting y>or equal to x
@abouttech7728
@abouttech7728 5 ай бұрын
Sir Homework : Both reflexive and symmetric so sir ek matrix bana liya A*A kyunki reflexive hai to diagonal to aayega hi relation mai For symmetric(Considering with respect to upper triangle) : ham kisi bhi ek element in upper triangle ko leyenge to uske corresponding ek element lower triangle wala aajayega so ham kisi bhi upper triangle wale element ko le sakta hai ya nahi le sakta baki kaam ho jayega so 2 choices per element of upper or lower triangle . Total no. of element in matrix = n**2 no. of element in diagonal is n no. of element in each triangle equal as square matrix so no. of elements are (n**2-n)/2 So number of relations are 2 raised to power (nsquare - n)/2
@kaliaiit
@kaliaiit 5 ай бұрын
Bahuuut badhya shera.... Keep it up❤❤❤❤
@noobi539
@noobi539 5 ай бұрын
is it helpful for someone who doesn't know A of functions?
@ei-kun2212
@ei-kun2212 2 ай бұрын
the only teacher who reminds me how beautiful maths can be. planning to drop this subject due to extremely hard questions... but nah its amazing
@RSNPIT11234
@RSNPIT11234 4 ай бұрын
1:25 you will find rajwant sir
@FTGUY10
@FTGUY10 4 ай бұрын
😂😅
@Sachingurjar20072
@Sachingurjar20072 3 ай бұрын
Yeah!!
@FocusonSolution780
@FocusonSolution780 2 ай бұрын
41:13
@jay_ff_1883
@jay_ff_1883 4 ай бұрын
Sir why you not covered even odd fn and periodic fn
@mathsioqm
@mathsioqm 2 ай бұрын
UDA DIYA SIR NE
@ultimatefactsff1785
@ultimatefactsff1785 2 ай бұрын
This is covered by sir in 11th class lecture
@gauranggupta4176
@gauranggupta4176 Ай бұрын
Which one ​@@ultimatefactsff1785
@sagniksarkar8570
@sagniksarkar8570 Ай бұрын
@@ultimatefactsff1785 kisme? standard functions waali mein?
@cherryblossom8959
@cherryblossom8959 5 ай бұрын
Best mathematics teacher 😮. Surely you will fall in love with maths by attending bhai's session ❤
@mariiii09-z6y
@mariiii09-z6y 7 күн бұрын
@@noobi539 bhai function mein toh A huta hi nahi.
@AparnaBaudh
@AparnaBaudh 5 ай бұрын
Lots of love to you dearest sir from my core of pure heart ❤! THANK YOU
@anuragmondal
@anuragmondal Ай бұрын
The only JEE teacher who makes complex maths topics simple and beautiful!
@Shine.for.creator
@Shine.for.creator Ай бұрын
1:37:55 , 1:45:30 , 1:47:48 , 1:49:45 , 1:52:25 , 1:58:23 , 2:00:05 , 2:07:58 , 2:26:33
@IITD-or6fw
@IITD-or6fw 4 ай бұрын
Bhai pdf upload NHI hui hai , pls karva dijiye.
@ARJUN_OG69
@ARJUN_OG69 Ай бұрын
26:00 reflexive , symmectric , transitive sets
@YASHDARAK
@YASHDARAK 2 күн бұрын
Koi mujhe vo 11 th lecture konsa hai bata sakte ho yaha pe sir jo baar baar keh rahe ki 11 me padha tha
@target__iit
@target__iit Ай бұрын
𝐓𝐈𝐌𝐄𝐒𝐓𝐀𝐌𝐏𝐒 4:12 *Topics* 4:48 Critical Topics 5:44 *RELATIONS* 5:54 Cartesian Product of two sets 7:43 Definition of Relation 9:12 Remark (Relation on A) 10:03 Description of Relations 14:57 Domain, Codomain & Range 18:32 *Total Number of Relations* 20:23 *Inverse of Relation* 23:43 *Types of Relations* 24:38 1️⃣ Empty Relation 24:57 2️⃣ Universal Relation 25:09 3️⃣ Identity Relation 25:55 4️⃣ Reflexive Relation 29:25 5️⃣ Symmetric Relation 31:10 6️⃣ Τransitive Relation 30:28 NOTE 47:50 _QUESTION: Minimum number of elements that need to be added_ 1:14:59 7️⃣ Equivalence Relation 1:15:13 _Checking Type of Relation Theoretically_ 1:24:03 👉 Equivalence Class 1:26:04 *Number of Relations* 1:36:07 *Number of Equivalence Relation* 1:38:04 8️⃣ Antisymmetric Relation 1:39:32 *Basics of Functions* 1:42:08 *Classification of Functions* 1:48:01 Checking One-One Function 1:53:15 Checking Onto Function 1:58:34 _Finding range of Piecewise Function_ 2:08:29 *Composition of Functions* 2:09:41 Example 2:16:14 Domain & Range of Composite Function 2:20:44 _Question (Multiple times Composition)_ 2:30:31 *🌟 Composite Function of Piecewise Defined Functions* 2:43:07 *Inverse of Function* 2:45:29 Identity Function 2:47:25 *Definition* 2:47:51 Algorithm to find Inverse of Function 2:52:11 *Inverse of Piecewise Defined Function* 2:58:54 Finding inverse if relation b/w functions given 3:01:36 *NOTE:* Inverse of a Function is unique 3:04:10 *Inverse of Itself* 3:07:00 *Inverse of Composite Function* 3:08:27 Condition for function to be invertible 3:11:08 _Conceptual Question_ 3:16:22 ① Graph of Inverse Function 3:17:35 ② Solutions of f(x)=x & f⁻¹(x)=x are same
@Paarth-g6q
@Paarth-g6q 5 ай бұрын
I was searching for this chapter today morning and sir uploaded it today itself thank you sir
@noobi539
@noobi539 5 ай бұрын
Is it helpful for someone who doesn't know A or function?
@vihaansrivastava4956
@vihaansrivastava4956 5 ай бұрын
@@noobi539 you should just know set theory for relations. nothing else is required
@ckjain_maths8594
@ckjain_maths8594 6 күн бұрын
Sir, Please, explain the sentences " this relation is symmetric by default." " This relation is transitive by relation." An identity relation is an equivalence relation by default." " Reflexive relation by default is non- existent. ".
@panchalgamer4178
@panchalgamer4178 3 ай бұрын
1:04:37 sir a=2,b=½,c=-½ {(2,½),(½,-½),(2,-½)}
@Rockyboy16-ol3ky
@Rockyboy16-ol3ky 2 ай бұрын
a=-2 b=0 and c=4 best way
@ajit6250
@ajit6250 5 ай бұрын
Sir ITF ka next chapter laye pls Love you Bhai❣️❣️
@veeraraghavanpandurangan7148
@veeraraghavanpandurangan7148 2 ай бұрын
You can understand and appreciate it well If you study ncert by yourself And solved 75% the exercise
@akhilsaini9286
@akhilsaini9286 2 ай бұрын
Si pura to padhate with even odd and periodic fnxs ❤❤🎉🎉
@Ueuehehsjystwywhsyywyw2
@Ueuehehsjystwywhsyywyw2 5 ай бұрын
Thank You Jii 💕
@mo_ayaan_
@mo_ayaan_ 4 ай бұрын
2:26:23 sir answer can be option C also right??
@Garvit-LookatthisDuude
@Garvit-LookatthisDuude 2 ай бұрын
C kaise hoga bhai 2006/2008 aaega toh cut krke 1003/1004 hi toh hoga
@Garvit-LookatthisDuude
@Garvit-LookatthisDuude 2 ай бұрын
Incorrect poocha hai
@saieshulhe4531
@saieshulhe4531 Ай бұрын
pdf is not available on tg
@ArmaanjitSingh-v7j
@ArmaanjitSingh-v7j 6 күн бұрын
Sir iski dpp enough hogi jee mains ke liye
@ManishSingha-ng7ik
@ManishSingha-ng7ik 7 күн бұрын
Is this one shot enough for boards and JEE mains
@GamingWorld-ke3jj
@GamingWorld-ke3jj 5 ай бұрын
Sir Gaming World Me hi Hu😂 Mera naam Abhay hai😅 46:21 & 1:04:00 Thank You sir.
@RajvardhanShrivastav
@RajvardhanShrivastav 5 ай бұрын
Name change Kar na bhai to
@GamingWorld-ke3jj
@GamingWorld-ke3jj 5 ай бұрын
Arey Nahi bhai, Name se kya ho jayega
@GamingWorld-ke3jj
@GamingWorld-ke3jj 5 ай бұрын
​@@RajvardhanShrivastavAbhi 12th me ho kya? Kaise chal rahi h prep?
@RajvardhanShrivastav
@RajvardhanShrivastav 5 ай бұрын
@@GamingWorld-ke3jj ha bhai Chal rahi he prep
@kaliaiit
@kaliaiit 5 ай бұрын
Theek hai shera....❤❤
@aryanverma297
@aryanverma297 3 ай бұрын
Thank you so much sir❤❤😊
@arjunsagar-s8n
@arjunsagar-s8n 5 ай бұрын
Sir Even/Odd Functions Nahi Padhaya Aur Periodic Bhi Nahi Padhaya
@ganeshgouda6507
@ganeshgouda6507 2 ай бұрын
Ha bhai 😢
@target__iit
@target__iit Ай бұрын
functional equation, onto into function, range of function,counting of finction kuch nahi padhaya
@sikhowithshubham5197
@sikhowithshubham5197 Ай бұрын
Last seen1:10:00
@adarshkumar34556
@adarshkumar34556 21 күн бұрын
anybody else having problem in opening pdf of this session? i am having.. the site is not directing to pdf even if i press on view pdf
@Mehendi.vibes99
@Mehendi.vibes99 11 күн бұрын
This video is enough for kcet preparation??
@Aspirant.iitjee
@Aspirant.iitjee 8 күн бұрын
yes
@ManishSingha-ng7ik
@ManishSingha-ng7ik 7 күн бұрын
​@@Aspirant.iitjee is it enough if I am watching for the first time for boards and JEE mains can I watch this full series for mathematics
@protech9416
@protech9416 5 ай бұрын
1:35:53 Is me 1×1×1×2^3 If n=3
@karnikatrivedi
@karnikatrivedi 5 ай бұрын
Sir is this sufficient can we solve pyqs and all kind of questions after this??
@arnavvhhhh
@arnavvhhhh 5 ай бұрын
yuh
@sarangg5348
@sarangg5348 4 ай бұрын
lol this is not board this is jee man
@Shine.for.creator
@Shine.for.creator Ай бұрын
15:44 , 20:13 , 21:01 , 21:17 , 47:23 , 48:28 , 57:58 , 1:09:08 , 1:18:35
@NihalChandsah-vv7sc
@NihalChandsah-vv7sc 5 ай бұрын
Thankyou so much Bhai
@anutagya
@anutagya 17 күн бұрын
Sir group mehe pdf Mahi hai
@creativecraft15
@creativecraft15 4 ай бұрын
1 ghante se important and main cheej .......🙏🙏🙏🙏
@VaishnaviAgrawal-ji1vg
@VaishnaviAgrawal-ji1vg 3 ай бұрын
Very great lecture thanks bhai 🎉❤
@vedprakashsuman1
@vedprakashsuman1 Ай бұрын
sir pdf available krwa digie
@KyoichiShido-ph7ez
@KyoichiShido-ph7ez 5 ай бұрын
When will be the next lecture ???
@arteverytime105
@arteverytime105 4 ай бұрын
2:28:46 the formula of gm is not ab but it is root(ab) so the answer will not be 4 it has to be 2
@NakshShetty-fb1xz
@NakshShetty-fb1xz 4 ай бұрын
cross multiplied... he sent 1/2 to gm side which makes it 4
@TGplayz007
@TGplayz007 5 ай бұрын
Sir Please Take ITF chapter
@harikaramchandar9652
@harikaramchandar9652 14 күн бұрын
???
@33NitinChhangani8d
@33NitinChhangani8d 7 күн бұрын
​@@harikaramchandar9652 inverse trigo function
@realkakarot
@realkakarot Ай бұрын
Iss sir ka naam kya hai bhai zabardast padhate hai ye 🗿 Inke waja se mera cengage calculus pura complete ho gya 🗿
@ManishSingha-ng7ik
@ManishSingha-ng7ik 7 күн бұрын
Is it enough for JEE mains and boards
@priyanshuchauhanvlogs935
@priyanshuchauhanvlogs935 17 күн бұрын
❤❤JAI SHREE RAM 🙏 JAI SHREE GANESH JI 😊 JAI SHREE KRISHNA JI ☺️ THANK YOU SO MUCH SIR JI 😊🙏
@ajay_master_mind4002
@ajay_master_mind4002 5 ай бұрын
Sir iss baar lecture ki starting mein nature of chapter and weightage index kyu nhai hai
@Ikigai747
@Ikigai747 3 ай бұрын
THANK YOU FOR EVERYTHING SIR YOU ARE SUPERB!
@SharvilJoshi-bc7nm
@SharvilJoshi-bc7nm 5 ай бұрын
mera bhai mera bhai💖💖💖💖
@veeraraghavanpandurangan7148
@veeraraghavanpandurangan7148 2 ай бұрын
Before seeing this please read NCERT. You will enjoy
@itz.JEE69
@itz.JEE69 4 ай бұрын
dhanyavad sir 😃😃
@adityakushwaha602
@adityakushwaha602 3 ай бұрын
2:34 personal reference
@sikhowithshubham5197
@sikhowithshubham5197 Ай бұрын
58:46 last seen
@Avengers-do9yf
@Avengers-do9yf 4 ай бұрын
sir what about even odd fns and periodic fns? does anyone know abt these topics?
@ShivamGupta-oy2rc
@ShivamGupta-oy2rc 4 ай бұрын
Very important
@paramtiwaripoint9694
@paramtiwaripoint9694 5 ай бұрын
11 Wale dekh sakte hai ya rehne de
@gauranggupta4176
@gauranggupta4176 5 ай бұрын
Nhi 12 th ka hai
@aditi31245
@aditi31245 5 ай бұрын
Dekhlo 12 me asani hogi
@vedagyamishra4650
@vedagyamishra4650 5 ай бұрын
Rehne de
@vidyeshvaidya1669
@vidyeshvaidya1669 5 ай бұрын
Rehen dekh 11th kahi kar pehle
@grewknowledge8750
@grewknowledge8750 5 ай бұрын
nope
@SharvilJoshi-bc7nm
@SharvilJoshi-bc7nm 5 ай бұрын
love u bhai , here from class 11th
@Challengerajit
@Challengerajit 5 ай бұрын
Pls raat main rakha karee 8 bje ke kareeb Iss time pe humari main classes chlti hain sir pls raat 8bje ke baad rkhe pls ❤❤
@spicyhaikya8889
@spicyhaikya8889 4 ай бұрын
11 ka relation yaad dila ke emotional kr diya sir😢
@fiteasy001
@fiteasy001 3 ай бұрын
Sir odd even and periodic function nhi padhaya
@BanothThirupathi-q6q
@BanothThirupathi-q6q 3 ай бұрын
Thank you sir
@sikhowithshubham5197
@sikhowithshubham5197 Ай бұрын
Last seen 1:30:00
@KanwarWorld
@KanwarWorld 4 ай бұрын
es lecture koo dekhne ke baad unacademy ka module solve hoo jaye gaa kya
@VinayakKadam-y9j
@VinayakKadam-y9j Ай бұрын
Lag 1:21:47 1:21:47 1:21:47 1:21:48 1:21:48 1:21:48 1:21:48 1:21:48 1:21:48 1:21:48 1:21:49 1:21:49
@SarthakGautam-eb3wf
@SarthakGautam-eb3wf 5 ай бұрын
Sir, The third part proved👍👍👍🙏🙏
@18football18
@18football18 5 ай бұрын
Bhai coordinate kab karwaoge adv level?!🥹
@samaygaba479
@samaygaba479 5 ай бұрын
Proofed 3rd part love u sir
@abouttech7728
@abouttech7728 5 ай бұрын
Sir doubt pls give a look Sir ek calculus ka question hai maybe i guess sir dimak mai vaise hi aagaya book mai nahi hai school teacher ne solve nhi kiya looks simple but when thinks about it its quite difficult sir pls you can help ; Sir a point going in x - axis at 1unit/second when t = 0 but acceleration in x(axis)= y(value of y) and acceleration in y(axis) = x(value of x) sir now it will also move in x and y sir ham trajectory ya path ki equation kuch nikal sakte hai kya?
@kynsign
@kynsign 5 ай бұрын
absolutely love your efforts sir that you do for us, just another humble request to you that, please do something about physics too...physics oneshot would be a blessing for us!!
@noobi539
@noobi539 5 ай бұрын
Is it helpful for someone who doesn't know A of functions
@kynsign
@kynsign 5 ай бұрын
@@noobi539 totally!
@simranbhadani3052
@simranbhadani3052 5 ай бұрын
Thank you so much sir 😊😊
@THEEND-y1x
@THEEND-y1x 3 ай бұрын
Tum kahi dekha dekha lag raha hai
@AKSHAY-1290
@AKSHAY-1290 2 ай бұрын
​@@THEEND-y1xtera mother hain 😂😂😂
@adityakushwaha602
@adityakushwaha602 3 ай бұрын
3:10 concept building ques
@JaskaranSingh-hg5bn
@JaskaranSingh-hg5bn 5 ай бұрын
Sir physics ke bhi detailed one shots chahiye 😢
@suhaniverma6583
@suhaniverma6583 5 ай бұрын
Sir 11th plus 12th limits pe lecture bnaiye please sir ,aap bhot jyada acha padhate hai 🙏
@disciplinedev
@disciplinedev 5 ай бұрын
sir what is difference in these and older lectures?
@sharvarishahare5529
@sharvarishahare5529 8 күн бұрын
Kn vhich pdf rakhte hai
@sikhowithshubham5197
@sikhowithshubham5197 Ай бұрын
Sir 3:04:00 pe galat Kara hai
@sameer_plays0141
@sameer_plays0141 2 ай бұрын
sir very well understood
@shivkrishna8506
@shivkrishna8506 Ай бұрын
sir u are like mahesh babu always young and smiling
@RahulSharma-n3c
@RahulSharma-n3c 4 ай бұрын
Third part answer is =2⁶ [1,4],[1,3] and [1,1 ],[2,2] [3,3] [4,4] 😊 sir proved third part ❤
@sarangg5348
@sarangg5348 4 ай бұрын
this is 12th relation and function only?not 11th included?
@Hemalatha-yu7ht
@Hemalatha-yu7ht 4 ай бұрын
Yes only 12th
@ALLENITE343
@ALLENITE343 5 ай бұрын
sir doubt plz plz reply i have exam tomorrow at 50.25 here in this relation there is ac already then why have you written ca .................. agar ac relation me he toh ca likh ne ki kya jarurat he sir plz reply sir iska answer toh 5 aana chahiyea fir sir plzzzzzzzzzzzzzzzzzz replyzzzzzzzzzzzzzzzzzzzzzzz
@gunmattac4621
@gunmattac4621 4 ай бұрын
nahi mila reply , hahahahhhahahaah
@agnidiptasarkar3024
@agnidiptasarkar3024 4 ай бұрын
1:34:35 Sir proved 3rd part
@18football18
@18football18 5 ай бұрын
Syllabus kb tk complete hoga bhai???
@Cool_dhruva-xt1sq
@Cool_dhruva-xt1sq 5 ай бұрын
December
@Hhhj438
@Hhhj438 5 ай бұрын
Please reduce the price once more to 5499 for droppers it will be a great help
@RakeshGupta-nj1pq
@RakeshGupta-nj1pq 5 ай бұрын
Sir ye video meins level ko lekar chal sakte he. ,advance me ye chapter bhout lendi he😊
@Sanjarhussain5397
@Sanjarhussain5397 5 ай бұрын
Sir is it sufficient for board
@sarangg5348
@sarangg5348 4 ай бұрын
this is for jee for board they dont ask question like this board is so easy
@MohitSingh-ud2wi
@MohitSingh-ud2wi 4 ай бұрын
2:40:08
@AurochandanRana
@AurochandanRana 2 ай бұрын
@18football18
@18football18 5 ай бұрын
Bhai syllabus timeline 🙏🙏🙏
@Hitman-256
@Hitman-256 5 ай бұрын
Sir kya 11-12 pcm ka sara syllabus starting se detail me kraoge na plz 🙏🙏🙏 sir reply
@manangupta2509
@manangupta2509 5 ай бұрын
Only maths and chemistry
@Hitman-256
@Hitman-256 5 ай бұрын
@@manangupta2509 physics ni hogi?
@JaskaranSingh-hg5bn
@JaskaranSingh-hg5bn 5 ай бұрын
Pata nhi ​@@Hitman-256
@PrathmeshKulkarni-iu8jb
@PrathmeshKulkarni-iu8jb 5 ай бұрын
Sir jee aap hi physics and chemistry padhao
@amittomar419
@amittomar419 5 ай бұрын
sir please one shot nhi full series laiye yt pr please sir its myt humble requestipn and with dpp also please sirr
@KanwarWorld
@KanwarWorld 4 ай бұрын
Sir aapne periodic function toh pdhaya hi ni 😢
@shubhamruparel2750
@shubhamruparel2750 26 күн бұрын
Proved at 1:34:45
@yashsoni8714
@yashsoni8714 4 ай бұрын
Thank you sir 🥹🙏🏻🙏🏻🥹
@Ayush-r8t
@Ayush-r8t Ай бұрын
ODD EVEN PERIODIC?
@hrithikroshan2565
@hrithikroshan2565 5 ай бұрын
sir functional equation choot gaya hai
@The_Greatest6969
@The_Greatest6969 Ай бұрын
thank u sir❤❤
@shsbsvsb
@shsbsvsb 4 ай бұрын
2:30:00
@indrajitkumar1907
@indrajitkumar1907 5 ай бұрын
Sir ye series kb khatam hoga
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