Your observation that we're trying to "get rid of redundancy" actually provides ample motivation for students with an applications bent. I'm an advocate of pure math, yet even I was appreciated the insight. New subscriber here. Thank you.
@AdamGlesser2 ай бұрын
@@vector8310 Very nice of you to notice. Most of my students are not pure math majors, so I'm always trying to reach across the aisle.
@alla66313 жыл бұрын
Sir, you are the best! Your students are very lucky! Our Professor doesn't explain anything, but expected to know everything!
@AdamGlesser3 жыл бұрын
Glad I could help :)
@mc811mc3 жыл бұрын
I usually don't write comments but sir, you've literally saved my life
@AdamGlesser3 жыл бұрын
Always happy to have saved a life :)
@rubhasreekrishnan46605 жыл бұрын
Thank u so much.....i have searched so many videos..but you explained the best
@agathakafuko23797 ай бұрын
Thankyou so much this was so amazing can't believe I understood in 5 minutes 🥺❤️
@baroncandy39393 жыл бұрын
I have my semester tomorrow and I was utterly confused in this I can do a bit thanks to this vid
@lethabompotoane28202 жыл бұрын
Thank you so much! I spent the whole day doing this😂😂😂😂... only to get it in 5 minutes
@shawnmofid71314 жыл бұрын
Thanks. It was just what I needed to understand it. What is the spelling of the notation name please? It sounds like you say "kochi's" notation?
@AdamGlesser4 жыл бұрын
Cauchy
@3lk0sak04 жыл бұрын
Wow, only one video, which could resolve my problem. Thank You.
@KermitTheHermit.11 ай бұрын
Thanks for the infor sir! Was stuck quite a bit
@kennethben-boulo71276 ай бұрын
Hello Is it possible to express (1 2 3 4) in S4 as a product of disjoint cycles ? Thanks
@AdamGlesser6 ай бұрын
Yes, but you may not like the answer. Because (1 2 3 4) is already a cycle with no repetitions, we consider it a product of disjoint cycles. I suspect you really want to know if we can write (1 2 3 4) as a product of two (or more) disjoint cycles. The answer to that is no. This is because, up to reordering the disjoint cycles, we can write any permutation as a product of disjoint cycles in only one way. Since (1 2 3 4) is already one such way, there are no others.
@kennethben-boulo71276 ай бұрын
@@AdamGlesser I get it now, thank you so so much ❤️🔥🔥 Subscribed 🙂
@nadeembhatt40587 ай бұрын
Thanks 👍👍👍
@umarplayzhd52204 жыл бұрын
Thank you!
@mathbeyondbasics2 жыл бұрын
Thank you sir
@drummerjuans5 жыл бұрын
Thank You! This video is much appreciated...
@lemyul5 жыл бұрын
thank you for sharing Ada
@firewingsipl3 жыл бұрын
sir one doubt in ans a there is only one cycle we got so this is the disjoint cycle right
@AdamGlesser3 жыл бұрын
That's right. In order to make the language easier, we allow for "product of disjoint cycles" to include there being a single cycle. In fact, we even allow it to mean zero cycles. For example (1 2)(1 2) equals the identity permutation which, if forced do so, we would refer to as the empty product of disjoint cycles.