Rethinking Functional Limits (

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Keith Jerosky Maths

Keith Jerosky Maths

Күн бұрын

Пікірлер: 61
@PeterBarnes2
@PeterBarnes2 Жыл бұрын
Thomae's Function is a cool variation. It's Dirichlet's function, but for rationals of the form p/q the function equals 1/q. Now you have continuity on the irrationals, and I'm pretty sure the limit exists everywhere.
@ErsagunKuruca
@ErsagunKuruca Жыл бұрын
Oooh. Another function: 0 for computable numbers, 1 otherwise. It doesn't have a limit at x=0, but you cannot ever start to write an example of a series that doesn't converge to 0.
@PeterBarnes2
@PeterBarnes2 Жыл бұрын
@@ErsagunKuruca Constructivists hate it! Find out the one wierd function they don't want you to compute limits for!
@bobater
@bobater Жыл бұрын
Extremely cool use of limits! The idea of looking not just at positive and negative approaches when evaluating a limit, but different sequences of numbers, really blew my mind. Great video and great presentation!
@angeldude101
@angeldude101 Жыл бұрын
While the formal epsilon-delta definition only came up at the end, what was shown at only 2:00 is really the exact same thing, just with less precise language and also not necessarily being symmetric. What was shown there is a very intuitive understanding of a limit, and all epsilon-delta does is phrase that intuition in formal notation.
@vladislavanikin3398
@vladislavanikin3398 Жыл бұрын
I would have to disagree. These are two distinctly different notions of a limit of a function stemming from generalizing two different "approaches" of a limit of a sequence. A limit of a sequence a(n) is defined as ∀ε>0 ∃N∈ℕ n>N→|a(n)-L|
@brendanchamberlain9388
@brendanchamberlain9388 Жыл бұрын
@@vladislavanikin3398 Would you say it is incorrect to say that, even though these two definitions are “different”, they are “equivalent”? I.e., a function has a sequential limit iff it has an epsilon-delta limit, and these two limits are equal
@vladislavanikin3398
@vladislavanikin3398 Жыл бұрын
@@brendanchamberlain9388 In real analysis, sure, they are completely equivalent and you actually prove it in any standard course, so it wouldn't be incorrect. But if you aren't working with real numbers, things might get tricky. In fact, you can show that there are spaces where those two definitions are different, namely, Heine's definition is weaker. That means that in some topological spaces you can have a situation where Heine's definition (or actually something close to it in spirit) applies, but Cauchy's definition (or again something like it) fails. My comment, in fact, was less about this technicality and more about different "modes of thought" behind them, so to speak. But sure, if you are concerned with real or complex analysis, then they are completely equivalent.
@lexinwonderland5741
@lexinwonderland5741 Жыл бұрын
lovely graphics and explanation!! I appreciate the nod to epsilon-delta while still focusing entirely on cauchy sequences -- this was intuitive and educational!! I frequently refer to Real Analysis as "Calculus for Adults" lol
@noamyakar8554
@noamyakar8554 Жыл бұрын
Love it Keith! Our souls will forever be tied through our struggles in advanced calc :)
@alexbennie
@alexbennie Жыл бұрын
13:45 ish Examples of two such sequences: A: a_n = n¯¹ B: b_n =sqrt(2) × n¯¹ A is always Rational & B is always Irational.
@Simchen
@Simchen Жыл бұрын
That is a wonderful animation and introduction of the concept. However I have to point out a blunder. At around 13:00 you start constructing two sequences that each should converge to zero. But what you construct is in both cases a sequence that is monotonous and bounded but doesn't necessarily converge to zero. It is easily fixed tho. Just chose your next number to be between half of the former number and zero.
@pimcoenders-with-a-c1725
@pimcoenders-with-a-c1725 Жыл бұрын
I think it would have been easier to pick an arbitrary rational number q, and an arbitrary irrational number a, and then have the sequence be q, q/2, q/4, q/8, ... and a, a/2, a/4, a/8, ..., since any rational multiple of a rational is again a rational, and any rational multiple of an irrational number is an irrational number.
@Simchen
@Simchen Жыл бұрын
@@pimcoenders-with-a-c1725 Yes that also works. I just wanted to keep the process close to the one presented in the video.
@academyofuselessideas
@academyofuselessideas Жыл бұрын
Great! A video on the equivalence between the sequential, epsilon-delta, and open sets definitions of continuity would be cool... It would also be cool but perhaps too advanced to see in which spaces those three definitions are different (obviously, you need a metric space for epsilon-delta definition but a topological space should suffice for the other two definitions... But in general topological spaces, sequential continuity is different than continuity... this could be an interesting way of introducing nets as a generalization of sequences)... great video!
@chennebicken372
@chennebicken372 Жыл бұрын
I think, you actually covered the epsilon delta definition, just in your own words. You said roughly speaking "A limit existing means, that for every tolerance we can find an input from that on all the outputs lie within the tolerance" The difference just being, that you handled the specific case, when the input (n) approaches infinity. The Epsilon Delta Definition only states that "The limit that x approaches a of f(x) means, that for every tolerance ε (>0) we can find an input-range [a-δ; a+δ] (δ>0), such that all x from that range map to an output that lies within the tolerance".
@timpani112
@timpani112 Жыл бұрын
There is a small mistake (or omission, however you like to view it) when you give a sequence of rational numbers that converges to zero (at ~ 13:00 in the video). While it is true that the rational numbers are dense in R, there are sequences of rational numbers constructed the way you prescribe that do not converge to zero (but to, say, -1 instead). In these cases it is much better to give a concrete rational sequence that converges to zero instead of trying to give a more "general" one, as the general approach is much easier to get wrong and all we need is one sequence. For instace, one could consider the very explicit sequence (-1,-1/2,-1/4,-1/8,...) of rational numbers, and take an equally simple and explicit sequence of irrational numbers (just multiply the rational sequence given by -sqrt(2) for instance...).
@quantumgaming9180
@quantumgaming9180 Жыл бұрын
Bro this is so cool
@MathVisualProofs
@MathVisualProofs Жыл бұрын
nice work here! Enjoyed this.
@H3XED_OwO
@H3XED_OwO Жыл бұрын
Fancy seeing you here, i love your proof of the golden ratio
@FredericoKlein
@FredericoKlein Жыл бұрын
Oh thanks for this. I was playing around one day and constructed this function by mistake (I wanted to come up with a construction for a function that would give me integers, but I failed at that). Seeing on wikipedia, the construction i came up with is slightly different (I wonder if my version is correct). In any case, what I did was consider that the cross-correlation between 2 sine waves for irrational multiplicatives of their frequencies will never align, so they should integrate (from negative to positive infinity) so something that is zero, but when they are rational, they should have a value. I mean, i don't know if this is actually correct, but in any case, thanks for showing the name of the thing I thought I came up with!
@avyakthaachar2.718
@avyakthaachar2.718 Жыл бұрын
Very well animated and explained 👍
@enstucky
@enstucky Жыл бұрын
Hey! Found your video on the SoME voting page. My process didn't allow me to write official feedback, but I wanted to give you my thoughts anyway. The animation is well-done, and it also serves an essential role for this explanation, which would not work nearly as well if it were written down. It's clear that you made this video for a less experienced audience, and I think you did a good job at usefully meeting folks where they are. I am concerned that some of them will feel like you've essentially completed the task by the 5:00 mark with the left-right explanation, before you've actually gotten to the part that you seem most interested in. Because of this, the middle section feels a bit audience-less to me, even if the explanation is still appropriate for these more novice viewers. I'll conclude by saying I really liked the end. It's a really empathetic touch to recognize how a DNE result might not be satisfying. Moreover, while you didn't go through a full proof, I appreciate that you addressed the mixed rational-irrational case explicitly, not sweeping that tougher business under the rug.
@pizzarickk333
@pizzarickk333 Жыл бұрын
The explanation is good actually.
@RSLT
@RSLT Жыл бұрын
Very cool! Since the limit of the function exists, what is the derivative of the modified function?
@KeithJeroskyMaths
@KeithJeroskyMaths Жыл бұрын
Great question! Keep in mind that a function "g" is differentiable at an input value "a" if the limit as x approaches a of (g(x) - g(a))/(x - a) exists, not just if the limit exists at the input value of the function itself. It turns out that the modified Dirichlet function is not differentiable at any point in its domain ("nowhere differentiable")!
@RSLT
@RSLT Жыл бұрын
@@KeithJeroskyMaths Interesting. You have indeed shown that the limit as x approaches 0 of g(x) (with a=0) exists and is zero. What am I missing here?
@RSLT
@RSLT Жыл бұрын
@@KeithJeroskyMaths By any chance, do you happen to know the ratio of rational numbers to irrational numbers?
@KeithJeroskyMaths
@KeithJeroskyMaths Жыл бұрын
Finding the limit as x approaches 0 of g(x) (what this video shows) is not the same thing as finding the limit as x approaches 0 of (g(x) - g(0))/(x - 0).
@RSLT
@RSLT Жыл бұрын
​@@KeithJeroskyMaths By any chance, are you familiar with any other function where the limit exists and is equal to the value of the function, but the derivative doesn't exist?
@idrankwhatt
@idrankwhatt Жыл бұрын
Dr C would be proud
@Hi_Brien
@Hi_Brien Жыл бұрын
Really enjoyed this one😊
@zildian1983
@zildian1983 Жыл бұрын
Amazing!
@josephmaloney9116
@josephmaloney9116 Жыл бұрын
Came here for the math, stayed for the sexy voice
@ガアラ-h3h
@ガアラ-h3h Жыл бұрын
Well let’s just be very ones since the output is either 1/0 and nothing in between the limit is undefined just like the limit of any sin function is undefined sure there’s way more irrational numbers than rational ones however we still can’t tell if it’d be 1 or 0
@BlockOfRed
@BlockOfRed Жыл бұрын
Let f : R → R be the modified Dirichlet function, i.e., f(x) = 0 if x is irrational and f(x) = x if x is rational. Let (x_n) be any real sequence such that x_n → 0. We show that f(x_n) → 0. Let ε > 0 and choose N such that |x_n| < ε for all n ≥ N. Then, for all n ≥ N, we have |f(x_n)| = max(0, |x_n|) < ε. Hence, f(x_n) → 0.
@naturegirl1999
@naturegirl1999 Жыл бұрын
I tried graphing the equation at 2:39 and didn’t get the gap at 2, what did I miss?
@KeithJeroskyMaths
@KeithJeroskyMaths Жыл бұрын
How did you try graphing it (graphing calculator, desmos.com, etc.)? I pasted "(-x^2 + 5x - 6) / (x-2)" into desmos, and clicking on x=2 shows "(2, undefined)".
@naturegirl1999
@naturegirl1999 Жыл бұрын
@@KeithJeroskyMaths oh, I thought it would show the circle gap, I graphed it again clicked it and it did say undefined. Thanks
@blusham4629
@blusham4629 Жыл бұрын
Great
@gabrielmartins7642
@gabrielmartins7642 Жыл бұрын
Couldn't you do this to any rational point such that it never converges in any rational point ? Edit: like it seems possible to find a sequency of irrational numbers that converges to a rational one. Like a/(b+-sqrt(2)/n) a and b are integers, n goes from 1 to infinity
@sdurien
@sdurien Жыл бұрын
Teach me more things Keith
@joansgf7515
@joansgf7515 Жыл бұрын
PapaFlammy did a video on this too.
@stoneman172
@stoneman172 Жыл бұрын
Usually you define functional limits either via epsilon-delta or the behavior of the function when evaluated against sequences (i.e. the idea elaborated in this video) and then prove the equivalence of both in a very (!) simple exercise as homework. I don’t see the „rethinking“ part.
@volodymyr3169
@volodymyr3169 Жыл бұрын
Looking at the title I thought it would be about functional analysis
@degraj418
@degraj418 Жыл бұрын
The closest number to zero on both sides will be a rational number: -0.000...01 and 0.000...01. Is that not sufficient enough to conclude that the limit is 1?
@KeithJeroskyMaths
@KeithJeroskyMaths Жыл бұрын
Well, remember that there is no rational number that is closest to zero on both sides...due to the density of rational numbers in the real numbers, we can always find a rational number between zero and the rational number you chose. Furthermore, due to the density of irrational numbers in the real numbers, we can always find an irrational number between zero and the rational number you chose, whose function value would be zero and not one.
@abigailsokol3029
@abigailsokol3029 Жыл бұрын
the number 0.00...001 where «...» is an infinite number of zeros actually equals 0, and is not next to it. Consider «1 - 3(1/3)»
@OMGclueless
@OMGclueless Жыл бұрын
I don't think your method of picking sequences of rational and irrational numbers that converge to zero at 12:55 is valid. The sequence you pick might not converge to zero. For example -1-1/n is a sequence of rational numbers obeying your condition of being in between the previous element and zero and starting at a negative rational. But this sequence converges to -1 instead of 0.
@brendanmiralles3415
@brendanmiralles3415 Жыл бұрын
cool now integrate it
@dicandeo9698
@dicandeo9698 Жыл бұрын
Imo, the video could have ended after 4 and a half minutes, because by then you already showed that the limit to Dirichlet's function does not exist because it approaches different numbers for different input sequences.
@vladislavanikin3398
@vladislavanikin3398 Жыл бұрын
Good video overall, but I personally find two (or one, depends on how you count) problems with it. 1. You don't have to talk about Heine's definition of a limit in order to use "if f(aₙ) for two sequences does not converge to the same value, then the limit doesn't exist". It follows more or less directly from the standard ε-δ definition. 2. Heine's definition of a limit is not the same as this result about a limit not existing and that ideally should be at least noted. E.g. you can have the equivalence of Heine's and Cauchy's definition failing (in some topological spaces), but still have the result about a limit not existing holding. Maybe it would worth it to note this in a pinned comment. Other than that, great video, keep it up!
@strikeemblem2886
@strikeemblem2886 Жыл бұрын
On 2, I suspect that he might be unaware of the subtleties beyond functions from R to R, since it seems that he just completed a first course in analysis.
@vladislavanikin3398
@vladislavanikin3398 Жыл бұрын
@@strikeemblem2886 Well, maybe, even though it's less of an analysis thing and more of a logic thing, IMO. I mean, those two statements are converses, so it's more of not noticing that one is A→B and the other is B→A, but it's an understandable mistake when you indeed have the equivalence of A and B, I remember doing it myself (and in this precise context as well), so it's not a dis or anything like that, just a technical note. Me talking about how in some topological spaces those two definitions may not coincide was just providing a relevant example so that it may be more clear that the two statements are not the same, but rather converses. And except this slight technicality, which doesn't really affect the overall narrative, the video is great. I just wanted to note this small bump
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