This is the clearest outline of the Riemann hypothesis I've seen here. No tricks or quaint graphics...just facts and necessary backup info...THank you!
@base12universe8 жыл бұрын
Best explanation of the Riemann hypothesis I have come across, thank you!
@kquat78992 жыл бұрын
Excellent synopsis.
@smoorej5 жыл бұрын
The best overview of the RH I’ve ever seen. I love number theory but just have an undergrad degree in math and I was able to follow everything. Well done.
@stephendean28964 жыл бұрын
Best explanation I have found Don’t take this statement lightly because I have watched over 10 videos so far on the zeta function. If I am able to stay interested, then when I either prove or disprove the Riemann Hypothesis I will give you all the credit Thanks
@99bits463 жыл бұрын
It's criminal Riemann's name doesn't pop up in top mathematicians list
@Bob-x7m1vАй бұрын
Excellent video, even after 10 years, it is an outstanding overview of a complex topic, well done!! On a foggy Sunday morning, I enjoyed every minute of it
@MOHNAKHAN5 жыл бұрын
I like your style of polite pronounciation...
@blakff53734 жыл бұрын
bravo
@ImaliveUSA3 жыл бұрын
Pls upload more videos 🙏🙏
@David-dvr3 жыл бұрын
Very nice treatment of Riemann Hypothesis.
@musicalBurr8 жыл бұрын
Thanks *SO* much for putting this video together Andrea - I have it as a goal in life (I'm a little late to be embarking on this particular chapter - at age 55 - mind you I've been poking at it off and on for years now) to fully grasp essentially what you have put together as the contents of this video. You've hit every point I'm interested in, now it's just time for me to dig in deeper and really learn about the details. Thanks again!!
@metapix6 жыл бұрын
Your goal is more nobler than many other stupid things people aim at. Best of luck.
@atulmod12 жыл бұрын
Great effort
@mcook101288 жыл бұрын
There's a lot of information in this video. I think it's actually an excellent summary of some key points, especially concerning the flow of Riemann's thought.
@valor36az5 жыл бұрын
What an elegant explanation,
@seraphik5 жыл бұрын
super underrated channel. please make more vids. i’m liking and subscribing in hopes of seeing more!
@wertherquartett3 жыл бұрын
Lemma: For every KZbin exposition of the Riemann Hypothesis there exists at least one person for whom it’s the clearest such exposition.
@tariklahcen99286 жыл бұрын
جزاك الله خيرا أستاذتنا الغالية شرح غاية في الروعة لقد استفدت كثيرا سيدتي الفاضلة
@tutordave6 жыл бұрын
Nice. A bit dry, but nice. Like a good red wine. I really like the way you defined the zeta function piecewise. I was originally under the impression that the continuation on to the left of s = 0 would also work in the critical strip. Thanks for the info.
@davidwilkie95516 жыл бұрын
The layout of the information about series and sequences "on the face" of Cartesian coordinate math, is a good first principles approach to stating the conditions of the analysis to be done. A comparison of naturally occurring math and a micro equivalent, of something like the Babbage machine taken to the limits of possibilities, demonstrates the cause-effect /calculation of superposition/spin as spin-potential of QM-TIME, generating the structures of constants by irrational continuity convergence and reciprocals of exclusion. We look at resonance constants from an "outside" across a "band-level" wave connection to an eternal engagement with a rotating equal phase, all within the kind of compound spin, characteristic of the Babbage machine. So if the limits of calculation are the spin-potential shells of irrational resonance with the constant complex containment property of i, in completion of irrational series at the coordinated vanishing point of a complex i probability staement, then to prove this Conjecture, the series has to have the same characteristics as those used in Renormalization of infinities and zeros at 1-0 Discreteness/Dimensional prime/probability boundaries. (Math-Philosophy context) In the circumstances of the Riemann Hypothesis, the Gauss and Euler propositions "recognize" 1-0D mathematically in the form of a cause-effect limit of axial-tangential, Ln, e-Pi connection. It's the innate duality ratio, rationalizing of quantization. Excellent lecture.
@diarmuidkeane12 жыл бұрын
Well put together presentation simple clear and without frills
@mattkerle814 жыл бұрын
Great video! (Except for the bit about encryption at the end)
@vector83107 жыл бұрын
Thank you for your first - rate overview of the Riemann Hypothesis. I've just begun reaching Riemann's paper and this video provides helpful context. I'd like to share that so far my experience has been that reading the original German is a modicum more suggestive, which may make sense given that Riemann took notoriously great pains to precisely phrase his writings.
@dreia24058 жыл бұрын
Great video
@DavidVonR9 жыл бұрын
Great video, please do more.
@chevasit5 жыл бұрын
Very good!
@fmikael15 жыл бұрын
Awesome video - you deserve way more subscribers
@theedspage10 жыл бұрын
If the Riemann Hypothesis is proved, the zeta function could be the function of the 21st century because so much is riding on the hypothesis. Great video!
@99bits463 жыл бұрын
I am six years from the future, RH still hasn't been proven.
@williejohnson51724 жыл бұрын
Solved it. Zeta(0)=-1/2=i=sqrt(-1)=critical line =non trivial zero.
@jessstuart74957 жыл бұрын
Very nice video. Clear and informative. Thank you!
@rmarinov57705 жыл бұрын
BEST OF THE BEST. THANK YOU!
@ghiribizzi7 жыл бұрын
the analytic continuation of zeta function for analyticality of it in order to get the famous zeros
@robharwood35388 жыл бұрын
Really great summary and documentary. Thank you for making this! :-)
@Nasirmah6 жыл бұрын
Isn’t period functions can’t also be expressed in closed form, even e^x since e is transdental, therefore series to the power of x
@ahmadtariq39603 жыл бұрын
Thanks mam
@RSLT2 жыл бұрын
Great Video !!!!!!!!!!!! Does anyone knows the reference and proof for zeta(s) timestamp 9:33?
@ckmishn36648 жыл бұрын
I don't see how the Riemann Hypothesis being proven true could represent any threat to public encryption. The value of the proof is in that it allows other things to be proved, but simply assuming it to be true is sufficient to use them for practical purposes (and that's what matters to someone trying to break encryption). The implied distribution of primes won't change just because we know for sure it's true. The proof itself could, of course, lead to new math the might tell us something about the primes but that's just speculation.
@itsRAWRtime0077 жыл бұрын
But his point is assume it is correct and find such an algorithm, if it works you will know.
@KingHim003 жыл бұрын
I solved Riemann's hypothesis that every zero does end up on the line and I have proof to show you in a way for you to check and see if every zero ends up on a critical line
@calvinjackson81105 ай бұрын
PUBLISH!!
@TheNachoesuncapo7 жыл бұрын
Awesome!thank you so much,your explanation was delightful
@doubop5 жыл бұрын
thank you! beautiful video, i have vibration as if i was listening music!
@RSLT2 жыл бұрын
Does anyone know the reference and proof for zeta(s) timestamp 9:33?
@messaoudifares8089 жыл бұрын
فيديو جميل ومذهل /// ساحاول حل هذه المعضلة عما قريب إن شاء الله 2031
@mattersofheart229 жыл бұрын
great video! thanks
@nikola20249 жыл бұрын
Nice video , thanks
@Alcani3ca8 жыл бұрын
Really well explained! Loved how you explained so many details even the basic stuff from pre-calc. By the way when you say "using some tricks from analysis" at 9:28 are you talking about the class Real Analysis? I haven't taken the course yet but I'm really looking foward to it! Thanks for the video.
@seraphik5 жыл бұрын
please make more videos!
@Matematyk20245 жыл бұрын
Thenk you
@cadceedm.b61925 ай бұрын
The best explanation that i seen ever
@melese198810 жыл бұрын
Many thanks!
@moudar9816 жыл бұрын
Thanks a lot. Very nice explanation
@MostlyIC2 жыл бұрын
Andrea this is awesome, none of the other RH videos I've watched explain Riemann's counting-primes-plus-powers-of-primes and how that gives and explicit formula for PI(x) based on zeros of zeta. However I would like to see an explanation for why pi/n(x^(1/n)) counts n'th powers of primes though. And I wonder what stroke of genius on Riemann's part lead him to think about it this way.
@jigsaw10636 жыл бұрын
if "there is no eplicit formula for the non-trivial zeros" then how the hell did they calculate the non-trvial zeros so far? seems like a contradiction to me. And if we can´t use the function as described between 0 and 1then what is it for? I would like some one to describe the mechanism from point A to point whatever. How do we use the mentioned version of the zeta function to calculate non-trivial zeros?
@stillsayt619211 ай бұрын
Greath job, i will continue learning, thx.
@LifeIsBeautiful-ki9ky3 ай бұрын
Why, you don't do no more videos ?
@manofculture86669 жыл бұрын
Can someone please tell me, or give me a link that shows how the zeta function at 9:26 was derived? I've seen the zeta function for Re(s)>0 and how it was derived. But I've never seen this.
@neeraj3994 жыл бұрын
Max Echendu I just tried to simplify it, and it just yields the original zeta function. Even I need some details now.
@GintoGeorge200710 жыл бұрын
BEST
@zoozolplexOne5 жыл бұрын
wow, i like the explanation
@calvinjackson81105 ай бұрын
The hypothesis of Riemann is that ALL NON TRIVIAL ZEROS ARE ON THE CRITICAL LINE. If only one non trivial zero of the zeta function fails to be on the critical line, the Riemann conjecture is false. So i dont get what being "close" to the line is about.
@orenkrimchansky4 жыл бұрын
Great video. Thanks!! What is the smallest imaginary number on the 1/2 real number strip ever found?
@DeanNiemi-r1m8 ай бұрын
The 2 points you refer to (directly across the real number line from each other) are the start and end of the Riemann Zeta function from -time infinity to +time infinity.
@gurmeet01088 жыл бұрын
Really good video, but there is a small mistake at 16:38, you mistakenly swapped zeta and psi functions, it should be "express psi in terms of the zeros and poles of zeta"
@stephendean28966 жыл бұрын
Sometimes I forget KZbin has a past
@keinKlarname8 жыл бұрын
8:57: the summation should start with j=0
@elcrackkrack95593 жыл бұрын
Bolivian Beimar Wilfredo López found FORMULA THAT HE WANTED TO FIND GAUSS and RIEMANN kzbin.info/www/bejne/g3OzkmOGdrNkqsk - Well, it would be good to verify the demonstration of the BEIMAR FORMULA to give APPROVED or REJECTED. - In CONCLUSION, when a demonstration of the beimar formula was approved, since BEIMAR WOULD GO INTO HISTORY AS ONE OF THE 21ST CENTURY MATHEMATICS.
@mariyammapapabathiniratnam78623 жыл бұрын
1+2+3+4=10 -01=00 00 = 20 as 1=1,2=3,3=6,4=10 that is it is as 1+3+6+10=20 as called two zeeros as 00
@jimmpingwhosthat17473 жыл бұрын
What are non-trivial zeros
@calvinjackson81105 ай бұрын
Zeros that lie in the strip with vertical lines x=0 to x=2. The trivial zeros are the negative even integers.
@stephankuerner3157 жыл бұрын
The problem of the Riemann hypothesis is solved and Quatch what you are talking about here
@manofculture86669 жыл бұрын
I MUST prove this.
@HocineFerradj5 жыл бұрын
Good luck!
@brendawilliams80626 ай бұрын
No
@Tadesan6 жыл бұрын
A quiet reserved German Jew...
@marlonsoto6488 жыл бұрын
A table of prime numbers from the RH? Never heard of it. Riemann mentioned that he believed all the non trivial roots of zeta lie on the line Re(s)=1/2, in passing. His "prime" concern was finding a better approximation to The Number of Primes Less Than a Given Magnitude...He did find it, as all empirical data available today have indicated, data which, by the way, was out of his reach at the time he made his seminal contributions (hats off to the man!). So, we are talking about an analytic formula for an approximation here, not an exact one. How can we then "exactly" count the number of primes? Some things just don't add up here. And by the way, when discussing the functional equation the word "terms" are used to refer to what are really "factors". As far as I know those definitions haven't changed.
@kamalbouarfa3732 Жыл бұрын
Dont worry i found thé finaly Formula of primes nimbés wich descripe them pattern
@chrisbarlow63355 жыл бұрын
Why do you introduce i, complex numbers, roots of an equation, prime numbers etc in this video? Its about the Riemann Hypothesis and its safe to say that people watching this know something about maths. If they have never heard of i or a prime number do you think your video will mean anything to them at all?
@calvinjackson81105 ай бұрын
She was just trying to provide a little background to some who may be interested but who might need a little brush up. Trying to be helpful. If you found it boring, just skip ahead!
@magicfigures3 жыл бұрын
The new finds in the field of prime numbers. The prime numbers form so-called nests of the prime numbers in the fourth dimensions. Please see the homepage www.number-galaxy.eu in the directory "news" and positions: 01.01.2020 3D bordered prime magic squares in world and antiworld configuration 03.02.2021 Projection 3D bordered prime magic squares on critical linie of Riemann zeta-function. This is completely new in the field of the Riemann hypothesis.
@obsidaisy77768 жыл бұрын
I don't see how proving the hypothesis would influence cryptanalysis, unless you made a major breakthrough in order to do so. You couldn't just reverse engineer the hypothesis with some dummy variables and let statements, as most mathematical proofs do nowadays; you'd actually have to come up with some kind of historically unprecedented algorithm or formula that relates to the hypothesis on a basic level. Even then, knowing about the distribution of primes is a long way off from being able to factor primes.
@ksmyth9995 жыл бұрын
This is a good introduction to the subject. Unfortunately, the last comment concerning public key systems is rubbish. Without going into the details it can easily be inferred that if the truth of the Riemann Hypothesis means factorization becomes much easier, this would have been tried long ago by hackers. Since the concensus and computer evidence to date gives a strong indication the hypothesis is true, why would a hacker wait for the absolute proof? Actually looking at the comments I see that Patrick Wise had already pointed this rather glaring error out about 2 years ago. To put this into perspective. You would really need to do an undergraduate course in number theory to understand how the analytical continuation really works.
@جحخخحج-ل1ض3 жыл бұрын
الترجمه العربيه
@jeffreyluciana87113 ай бұрын
Reimann didn't have the benefit of my sixes or cancellations. All primes are twins next to the 6. And prime times prime cancels prime. Why waste your time on something that is described in base 10 when it is better understood in base 6?
@williejohnson51726 жыл бұрын
A General Solution to the Riemann Hypothesis Zeta(0) = negative one half = non trivial zero. Proof. 1. Superimpose two unit circles. 2. Designate the vertical diameters as 2i and the horizontal diameters as 2x. 3. Starting at zero degrees and rotating counterclockwise, the points of axes along the circumference then assume the values (1, 0); (0, i); (-1, 0) and (0,-i). 4. Pin the common point of the two unit circles at (1; 0) such that this point is restricted from moving. 5. Reduce the diameter of one of the unit circles by half. This creates an inner circle of diameter i vertically and diameter x horizontally, which is pegged/pinned to the larger unit circle at point (1; 0): 6. This pegged inner circle is identical in every respect to the larger parent unit circle except it has been scaled to half the size of the larger unit circle. 7. The origin of the parent unit circle assumes various equivalent values Cartesian: zero, plus or minus 1 Fermatian: zero, limit, derivative, maxima, minima, plus and minus 1, one half, i Newtonian: zero, shrinking the 2i secant to zero= i = limit = derivative = maxima = minima: Inner Circle shift: The (-1; 0) point of the reduced circle now occupies the origin of the larger parent circle. 8. The origin of the reduced/inner circle is identical to the origin of the larger parent circle. They differ only in location. 9. Thus since i = 0 then the entirety of the i diameter of the reduced /inner circle is, and must be, zero. 10. The same result may be obtained by shrinking the 2i diameter/secant of the parent circle to the length of the i = zero diameter/secant of the inner circle. 11. Thus the i diameter comprises the critical line and since its entirety is composed of zeroes then these zeroes are, obligatorily, non trivial zeroes. 12. Given step 7 and Figure 2.0.1, i is equivalent to the tangent = m = slope. 13. Vis a vis the parent circle, given Figure 16.3.2 this slope is manifest as the hypotenuse (tangent line) of a right triangle of height i and base .5x or one half x. 14. This results in the formation of a negative .5 slope or negative one half slope or a positive 2 precessional rate where slope = m = negative one half. 15. Therefore m = i = 0 = nontrivial zero = negative one half. 16. Therefore critical line equals i = 0 = non trivial zero= negative one half = Zeta(0). 17. Thus is it proven that Zeta(0) =negative one half=non trivial zero. QED
@arpcs9 жыл бұрын
Proving or disproving really wouldn't have any impact on cryptography. Calculating exact number of primes would be still as hard, and creating tables of primes is just a silly idea.
@RtZt-jx2uo Жыл бұрын
L ensemble des zéros est une famille génératrice est reliée couramment avec Fp(ns) ' telle que F(s)=hn×Fp(ns)^d tell que l ensemble As possède un sous ensemble Ap ' 1/27^s=1/3^3s ' Ap un sous ensemble de As l image de Ap =o pour s=1/n+ikπ/lnp le de la courbe de Fs il y a une relations ordonné à Fp
@mikevaldez76847 жыл бұрын
interesting
@mikevaldez76847 жыл бұрын
hey mike
@mikevaldez76847 жыл бұрын
+Mike Valdez, Yeah? What's up?
@didierfortune972 Жыл бұрын
10 36 Cos eq fonct
@taresy6789pp7 жыл бұрын
Find a contradiction between heisenberg uncertainty principle disproved riemann hypothesis
@williejohnson16698 жыл бұрын
Solved it. Read the Sagitta Key by Willie Johnson Jr or Gyro-Electrodynamics by the same author.
@andresmauriciopinillarinco2865Ай бұрын
si buscan la solución por simbolismo de absolutos nunca hallaran la solución