Rings 11 Tensor products of modules

[@allvods1385]

Thank you very much professor Borcherds !

[@migarsormrapophis2755]

yeeeeeeeeeeeee

[@weierstra5326]

amazing treasure

[@f5673-t1h]

Is there an example where tensoring 0 -> I -> R -> R/I -> 0 with M doesn't preserve injectivity (on the left part)?

[@xdman4890]

Just take the usual example R=Z and I=Z/2Z, with M=Z/2Z.

[@dannycrytser7268]

Right idea, but there is no nonzero morphism from Z/2Z into Z. I think you mean to take I = R = Z, with n in I mapping to 2n in R, and replace the notation R/I with Z/2Z to avoid confusion.

[@jessehudson7036]

How fortuitous-I was literally just working on tensor products and algebras

[@stenzenneznets]

Thank you