Divisibility Rules 2 || Number Systems || Quantitative Aptitude || CAT Preparation 2024

Number System by Ravi Prakash | Quantitative Aptitude for CAT 2024
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[@ashokkumar-it2wz]

What a powerful concept. Hearing this concept for the first time in my 23 years of life. Wondering why this hasn't been taught in high schools.

[@SHIVERS445]

Same😅

[@bhargavsathuvalli2480]

simply superb-I totally agree with you sir-Many books skips the divisibility rules of 7,13 etc difficult numbers......

[@amyepicduel1320]

YOU ARE LEGEND IN MATHS..NO TEACHERSHAVE EXPLAINED THIS WAY.. NO ONE

[@Rodha]

Thanks

[@Rodha]

Thanks

[@mindfullmallu7511]

Did u score well?

[@shubhneet.x]

​@@mindfullmallu7511 did u score well ?

[@ThatGirlDiarieS45]

What a Conceptual clearity this man has😮...Thank you Priya Mam and satyam sir fr introducing us to this legend

[@swamisharma4666]

An UPSC aspirants

[@sonty6589]

While watching this video i felt like what is the need to learn so much or rules i will just mug the divisibility of each important numbers.....but after completing the divisibility series i came here again to learn this ultimate hack to develop the divisibility rule for any number

[@VenkateshKariappa]

I've been going through multiple places to find the divisibility rule for 7 from a long time now. Your concept explained here seems to be pretty simple and easy to do. Excellent teaching, Thank you Sir.

[@indranujhazarika2369]

Explained a difficult concept so flawlessly. Everything makes sense now!

[@suryavoroy3527]

Very unique concept ,tweaked congruence modulo property of 7 for 1000 ,exploited minus 1 remainder property and groups of three with signs affixed to them was truly unique . Loved it!

[@anmolsharma9397]

U r simply the best sir....after a very long time somebody has impressed me in this subject

[@mantreekumar8923]

I can't express in words, how much I am thankful to you sir🙏...

[@sam16419]

How easily you summed up such a difficult concept Thank you Ravi sir!

[@shivanshimathur9146]

Never heard of this concept before, thankyou so much Sir

[@gokulkrishna3242]

The best teaching class ever in online

[@faraznadeem7918]

Brother could you explain me in the second question why didnt we write (1+2+3+4+5) As according to formula it was (1*10^5+2*10^4 and so on).

[@faraznadeem7918]

@SARTHAK BORA thanks for your concern to help me. Bdw i understood what i wanted to ask

[@arjunmalhotra2662]

Beautiful +Wonderful×Amazing=Superb

[@kalvinvrijbhan4761]

Great concept sir I don't have words how to appreciate you sir

[@muskanmalhotra9035]

i am watching this video in 2024.. and this is just so useful...thank you sir.. you have made a difference in our lives

[@rishitachakraborty6140]

Thank u for clearing my concepts....

[@supriyathakur2968]

What amazing concepts sir

[@gungunjain2623]

Best teacher ever ❤

[@user-yk9ic2td4l]

grateful to your series, sir!

[@Eth_com]

Amazing explanations 😍

[@jaspreetpannu4264]

GREAT CONCEPT!!

[@ManuSrivastava_]

Thank you so much sir.❤❤

[@Ok12376]

When sor says for any number it is 10^x/N, it's just for odd numbers.

[@prashantthakur23]

what a cocept grt way to teach thanks

[@user-qx3wp3qz9w]

thank you so much sir. God bless you.

[@sakshimishra7333]

Amazing sir ..m. Watching your vedios for tcs NQT ...bahut hard work kiya h aapne sir

[@Rodha]

Thankyou :)

[@truptinarkhede4850]

What is tcs NQT!?

[@shaleenjain4220]

Sir mujhe cmat ki preparation karni h but uski videos available nhi h utube pe to m yeh vedios se kr lu to jaega kya ya nhi Or yeh complete course h na

[@rahulsinghrana3378]

Sir we can apply divisiblity of 11 also bcz. 11 is the factor of 33, so 123456 adding alternate dig it and substract like (2+4+6)-(1+3+5) =12-9 =3 remainder very simple Sir let me know it is right or wrong???

[@sparsh....]

Thank you sir ❤️

[@rohit49..92]

Thank you sir

[@faraznadeem7918]

In question one why did we write 10^2k and what is k here ??

[@romi896]

Anyone can tell me that how we will get to know that remainder will come + or - in last question

[@cumulusmusic100]

Thank you Sir🙏

[@tanmaydey3008]

Thank you so much sir

[@sanjeetchandra]

Can someone please please explain how did he get the remainder of 10×10×10/7 as +6(-1), i know he used basic remainder theorem, but when you use basic remainder it should have been 3×3×3, which is basically 27/7 again, that gives out remainder 2 using basic reminders theorem.

[@thatsme61]

How are you getting rem as 2? When it's 27/7, 7x3=21 providing the rem of 6, and again 7x4=28 providing the rem of -1. Hope you got it.

[@akashsahu6306]

When we divide 10^x by 24 remainder +1 or -1 will never come. So, how to proceed in case of 24.

[@sakshamgupta3276]

24 = 6*4 so if the no. is divisible by 6 and 4 it will be divisible by 24 also..

[@shubhammaheshwari1191]

Please answer this, Given 7^3 leaves a remainder of -1, we can then find the remainder for any greater number by making groups of 3, but we also know that 7^6 will leave a remainder of 1. So why can't we make groups of 6? we won't even have to worry about signs? Edit: Leave, I tried it, both works. That's just lengthy.

[@monikarathore1550]

Do you know, Where are the questions on LCM and HCF models?

[@siddharthjain7766]

you can even find at 15:20 of the Divisibility Rules 4 video, the method you're referring here

[@siddharthjain7766]

@@monikarathore1550 kzbin.info/door/HXQiDwicRon0tRuWj6r9HAplaylists/playlists

[@karthikmadhusoodanan7274]

divisibility of complex nos like 33 & 7.

[@vishnusharmaek6754]

Sir,what will be the remainder for the number 5675354 when divided by 7? Because as per your concept (354+005-675)/7 where i am getting a negative number.

[@hardikthakur569]

I think you need to just divide it as -675+354 would be -316 and then further dividing -316 by 7 would give you remainder -1 and just change it to positive by subtracting 1 from 7 which would be 8 and this would be further divided to give you 1 as your remainder. Correct me if this is the right way

[@justvibin6601]

​@@hardikthakur569 7-1=6

[@36_parthshrimali84]

At 23:50 ,how can you add and subtract fast ...well done

[@prozac8430]

789-456= 333 333+123=456

[@spkbusinessD--]

shivam kamat (11) 6-8-2021 thank you sir🙏

[@janvisoni2619]

Multiple of 10^2 wont work here u should have said every power of 10^2 gives remainder +1 when divided by 33 . As multiple of 10^2 is 200 also which do not give remainder 1 when its divided by 33. Correct me if m wrong :) and ya I really appreciate your videos,you make all concepts so easy for us.THANKS.

[@Jainankur789]

10^2 is 100, that gives you a remainder of 1. 10^ 2 is nothing but 10*10.

[@janvisoni2619]

@@Jainankur789 thanks for telling me what 10^2 means 😊 u didnt get me read it again... every multiple of 10^2 doesn't give remainder 1 like 200,300,400.. We are talking about numbers like 10^2,10^4,10^6...(every power of 10^2)

[@tanyashankar9685]

Yeah I was confused with his phrases too.

[@sjsthomasnick3002]

@@janvisoni2619 yah u r right. Its not multiples of 10^2. It is powers of 10 which are multiples of 2.

[@rohitnrao4894]

Divisibility of 13?

[@vishusingh3097]

Sir in the divisibility rule of 33 in your example , abcdef divided by 33, you convert it into the form of 10 ^ 2K divided by 33 , so you're taking common 10 to the power 4 and hence the remaining is 10a + b and you write only ab how can we write 10 a + b is equal to a b and 10 C + d is equal to CD, sorry I don't understand I am confused please help me sir or anyone please help me.

[@arindamtaak6843]

A 2 digit no ab can be written as 10a+b

[@vishusingh3097]

Ohk thanku for rply 😊

[@adi_dgaf]

@@vishusingh3097 brother when you write a 2 digit number it can be written in the form 10a + b which can be simplified as ab For ex let us take 24 ..we can write 24 in the form of 10 x 2 + 4 where a = 2 and b = 4 Similarly 3 digit can be written in the form abc

[@vardhmanjain9887]

Why it got so hard ..like you have to multiply the last number with 2 and then subtract that with the remaining numbers .. that one is so easy the this mess

[@swethamadavan5859]

how come 10^3 / 7 reminder is -1? don't understand it 15:38

[@adityathakur005]

Same doubt

[@saikiran-pe9yz]

Want to know how the reminder is +1 =10power 2/33

[@snehatsamuel30]

33 x 3 = 99 . therefore 100-99=1

[@riyashrivastava1460]

How is 10 to the power 1ef/33 is leaving remainder as 1? I am not getting this

[@SHIVAMKUMAR-hi9hb]

watch again from 5:35 , and see 10^0/33 is nothing but 1/33 and its remainder is 1. And (10^1.e +10^0. f) can be written as 10^0(ef) this is what he has done

[@user-bd5py9nh4k]

Is their anyone having problems sheet topic wise. Then please help me

[@sanaparweenansari2333]

Whats the method of divisibility of 6..anyone?

[@snehatsamuel30]

Check if the number is even - divisibility test for 2 and then check if sum of digits is divisible by 3 . because 2 and 3 are factors of 6

[@morningstar2728]

Here you gave questions like which follows order in group of 3,, so what about if such numbers ask like suppose e.g: 1234 / 7. How should we solve it easily?

[@vikasnarasapur3251]

1234/7= Make a group of 3 means (001,234)/7two groups So now sign 234 have +be sign and 001 have negative sign( u know this how sign comes from above concept) so now -001+234/7=233/7=2 So the remainder for ur question is 2! I hope u got the answer

[@muslim1713]

How to take common? Im nt able to undrstnd

[@sakshamgupta3276]

You should take Commen in the form of 10^x and 10^x remainder should be 1 or -1

[@Abhishek-vn1nq]

mujhe smj nhi aya koi ye smja skta hai -1 remainder kesa find krte hai is video mai 15:30 pe 1000/7 ka remainder -1 kessa find kiya

[@legendaryquotes964]

Bhai jab divide krega to last mein 20 aayega which is -1 to the multiple of 7 (21) . Jaise 22 is +1 of 21 ....I hope you got it

[@anujpatil343]

Sir Jipmat and Ipmat ki registration date aah gayi hai kya

[@sujalkumar8634]

have you cleared it !!!??????

[@sakshamgupta3276]

I tried this method for 17 and 19 but unable to solve bcs there are no 10^n which gives rem of +1 or -1

[@HadesBTC]

For 17 do 10^8 = -1 Rem

[@HadesBTC]

For 19 do 10^72 = +1 Rem

[@HadesBTC]

If You Still unable to understand then leave your insta id will send you step by step and help u to understand

[@aryamansrivastava7218]

10^0 ÷ 33 ka rem 1 kaise?

[@HadesBTC]

@@aryamansrivastava7218 Question sahi sa batao

[@shashankdewangan9176]

thanks sir u are awesome. sir is this much videos is enough for cat level preparation?

[@akshaysonavane8629]

39×55×73×90×97×54 is divided by 50 then what is remainder i can't solve this type sir

[@sjsthomasnick3002]

Ans is 0.

[@akshaysonavane8629]

@@sjsthomasnick3002 explain plz

[@sjsthomasnick3002]

@@akshaysonavane8629 39×55×73×90×97×54/50 We can divide individually (39/50)R = -11 (55/50)R = 5 (73/50)R = 23 (90/50)R = -10 (97/50)R = -3 (54/50)R = 4 (-11 × 5 × 23 × -10 × -3 × 4)/50 -(55 ×230 × 12)/50 Again divide individually (55/50)R = 5 (230/50)R = -20 (12/50)R = 12 -(5× -20 × 12)/50 (100×12)/50 Again divide individually (100/50)R = 0 (12/50)R =12 (0×12)/50 =0. Ans = 0. Hope it's clear.

[@sjsthomasnick3002]

@@akshaysonavane8629 are u preparing for CAT'21?

[@vinitpatil8755]

24:10 456/7 remainder should be 2.correct me if I am wrong.

[@growwithbro01]

456÷7= 65 and remaindr 1

[@vinitpatil8755]

@@growwithbro01 65/7=9 further dividing 9 gives remainder 2.

[@growwithbro01]

@@vinitpatil8755 bhai tu *quotient* ko kyu divide kar rha hai

[@kaushikibhatt1874]

(123+789)-456 how it became 456/7 can you tell me

[@shrutikmanwatkar8019]

And Exactly "7" dislikes...

[@ashitadoshi3047]

How did 10 to the power zero divided by 33 become one?

[@drigo8192]

To make a no. in point form we have to first multiply by zero. As 1/33 so 0.030 So in the first step when u multiply 33 with 0 you get the remainder 1 . As we are dividing 1 by 33.

[@Justsomeguyyoutubing]

10^0 = 1 1/33 = remainder 1 (calculate)

[@aryamansrivastava7218]

@@Justsomeguyyoutubing rem should be 0 na? 1/33 1*33=33 Quotient 33, remainder 0???

[@sanjeetchandra]

Can someone please please explain how did he get the remainder of 10×10×10/7 as +6(-1), i know he used basic remainder theorem, but when you use basic remainder it should have been 3×3×3, which is basically 9/7 again, that gives out remainder 2 using basic reminders theorem.

[@Meena-ud2ry]

Can anyone explain at 8:55 how 1/33 =1?

[@sujalkumar8634]

its not 1/33=1 ...its actually reminder when 1 is divided by 33 which goes like 1=33*0+1 where 0 is devisor and 1 is reminder

[@BharatSingh-mi9xo]

Taaliyan bajti rehni chahiye

[@anishdubey6721]

Bilkul

[@vyankateshpandey8228]

Sir the method is not working in the 6 7 digits

[@vyankateshpandey8228]

Kindly guide sir

[@ashokmacho1932]

Question batao Bhai

[@Ukkmeee]

How does 101 0 leave rem 1?

[@Ukkmeee]

imeant 10 to power O

[@legendaryquotes964]

Divided 0 times , so got 1 remainder

[@Gautam_OG]

13:00 24:00

[@adarshsanil9112]

Sir if we need all the digits of a no. To find the remainder.. we can just use the calculator to find remainder

[@StardomMovies01]

How 1/7 remainder is 1? 😞

[@truptinarkhede4850]

Coz 1 is not wholly divisible by 7 and also we don't want a remainder in fractions as remainders are always in integers.

[@truptinarkhede4850]

So 1 is the positive remainder. And -6 is the negative remainder. Every remainder is in +1and -1 form. Ok!

[@lokeshsanklecha3789]

Sir some questions are there

[@Rodha]

what?

[@kshitijbalonie4361]

thankyou

[@syedshoaib8720]

How is the remainder of 56 one?

[@ShifaArabi]

I also have the same doubt

[@legendaryquotes964]

Bhai yaha particularly 56 ki baat nhi ho rhi , uska Jo common liya hua multiple 10° hai , uska 33 k respect mein remainder 1 hai ....same concept also applied with 12 .,....I hope you got it

[@ashwinmadhu592]

🌹💜

[@Abhishekkumar-ww9rn]

How did 10*10*10/7 became -1 Since ramainder is 6

[@Abhijeetkr_2211]

You say that remainder is either 6 or (6-7)=-1. For e.g 19/9= Remainder is 1. 17/9= Remainder is 8 or - 1. I HOPE YOU UNDERSTAND THIS 😊😊

[@sibgatullahrahmani6079]

Coz for 6/7 remainder is -1

[@elcucuy2236]

negative remainder is -1

[@namratasingh5634]

@@Abhijeetkr_2211 thank you😊

[@Mrupsccse2024]

🤔🤔🤔🤔🤔70 percent Upar sae gyaaa

[@romiljain5107]

I tried the 33 one, i didnt geet the answer

[@anilbhai1652]

What's your question exactly ?

[@romiljain5107]

@@anilbhai1652 nothing, its clear now!!!

[@dishasingh7482]

Thanks sir

[@sadasivamsubramoniam1305]

Thank you sir