Simple Equations 4 | CAT Preparation 2024 | Algebra | Quantitative Aptitude

Advance Algebra by Ravi Prakash | Quantitative Aptitude for CAT 2024
Join RODHA : www.rodha.co.in/
Follow RODHA : www.instagram....
#rodhafullcourse #catexamfullcourse #learnfromscratch #cat2024 #catexamsquantfullcourseonyoutube #99percentile #quant #lrdi #mocks
Welcome to our dedicated KZbin channel, your go-to destination for a comprehensive CAT course, all available for free! With an extensive library boasting over 350 videos and more than 150 hours of content, we provide unparalleled resources for CAT exam preparation. Why delay? Dive into our channel now and kickstart your preparation journey at zero cost. Don't miss out on this invaluable opportunity!
My Facebook Group Link:
/ 570194513099989
Feedback Post link:
/ 323057846372
Discover the transformative world of Rodha Educational Solutions, where we empower ambitious students to excel in their academic endeavors. Join our thriving community on KZbin and unlock the #RodhaFullCourse, featuring top-tier CAT video lectures of unparalleled quality.
Subscribe now to stay updated with the latest releases and invaluable insights tailored to elevate your CAT exam preparation to new heights.
At Rodha, our mission is simple: to provide dynamic training programs that equip students with the tools they need to succeed. Through our KZbin channel, we deliver the highest caliber content meticulously crafted for entrance exam excellence.
Experience the difference with Rodha Educational Solutions and embark on a journey towards academic greatness. Subscribe today.
Rodha KZbin Channel:
/ @rodha
CAT 2024 || Verbal Preparation
/ @rodha
CAT 2024 || Quantitative Aptitude Preparation
/ @rodha
CAT 2024 | Logic Reasoning and Data Interpretation
/ @rodha
CAT PREPARATION 2024
How to Prepare for Quantitative Aptitude
best cat prep strategy, best KZbin channel for cat preparation, cat 2024, cat 2024 preparation best free content, cat 2024 preparations, cat 2024 strategy, cat preparation 2024, cat preparation 2024, cat preparation strategy 2024, how to start cat preparation for 2024, 100 PERCENTILE CAT 2024, ARITHMETIC ADVANCE LEVEL QUESTIONS, BEST FREE CONTENT FOR CAT 2024, HOW TO PREPARE FOR QUANT CAT 2024, BASIC TO ADVANCE CAT 2024

[@ankitgarg8986]

18:40 there should be 24*2-1 solution

[@ankitkesharwani8336]

Bhai u r right Sir se dhoke se ho gya h

[@vertika6119]

Why *2?

[@NormalPerson053]

Why not *4

[@vertika6119]

@@NormalPerson053 yahi tareeka *2 karke 😹 I got to know later

[@sridharyelisetty8032]

@@NormalPerson053 because no;of factors which means it covers (a,b) &(b,a) so now all we need is all these in negative numbers so x2 .in normal we gets only (a,b) so X4

[@Parulbhatia123]

For anyone who is facing problem in calculating factors, look for "factor-1number system" video of sir at 7:00

[@nithishyuvaraj4513]

Very helpful ❤

[@songoku-jx3cb]

Thanks a lot .

[@MP_kasumi]

Thanks a lot!

[@arijeetpandafit]

Thanks❤

[@ananyamishra608]

thanks a lot!

[@abhitripathi9602]

sir at 19.05 min you did no of factors multiplied by 4 . But earlier you explained that for Intergral solution no of factors * 2 . Can you share the feedback about this ?

[@shubhimakhijani]

Same doubt

[@jishu1998]

it will by *2 only i have checked multiple sources. He might have written it by mistake

[@Sushantkumar-vo8bf]

@@jishu1998 yes there will be 47 solution .

[@mbagamingwala4581]

Each Pair of the integral solutions should be multiplied by 4.

[@pranavabudhabi7664]

Same doubt,I think mistKe

[@vaishnavirathod1829]

If a number is in the form a^p * b^q where a and be are prime numbers then the no.of factors of that number can be calculated as (p+1)(q+1)

[@narravulaprashanthi98]

Thank you:)

[@gourimmenon2726]

Thank you soo much

[@shivamrathod2225]

Thank you

[@Suryakumar-Tsk]

Thank you

[@srishmareddi1003]

For last question it must be be 28 integral solution.. because it is perfect square.. 14*2+1=29 then remove 29-1=28

[@prateekbirthal9649]

no in case of perfect square, no of solutions are 2*no of factors. We then remove one case only.

[@academics7471]

At 18:45 , shouldn't it be 24 * 2 -1 , instead of 24*4 - 1 ? Can you please clear my confusion?

[@phanichundru6405]

yes it is 24*2-1.

[@raviprakash6021]

Ya.. I corrected it later

[@Sidswamiofficial]

@@raviprakash6021 sir can u explain w 24×2-1 .here i could not understand why u multiplied by 2.

[@avipak3]

Yes I agree

[@sulochanavookoti4482]

@@Sidswamiofficial we have to multiply the no.of factors by 2 in order to get no.of integral solutions and have subtract it by 1 in reciprocal solutions Soo,24*2=48 ,48-1=47 solutions

[@rakshaagrawal4311]

I have a query, that at 22:25, why did he multiply it with 2, are we looking for only +ve solutions?

[@mahakmaheshwari9377]

number of integral solutions is asked in question and it includes all possible solutions

[@harshpandey8302]

IF A CASE IS AS SUCH THAT WE GET PAIR OF SOLUTIONS TO BE (a, a) then while we multiply the total number of factor*2(fo r considering ordered solutions shouldn't we subtract the case of repetition of cases when they are eqaul(in case of perfect square)

[@songoku-jx3cb]

Can someone explain to me why we didn’t multiply 2 with the whole equation just the second part . Isn’t it a rule that if we multiple something on rhs the same has to be multiplied on entire lhs

[@abhinavkumar-qg6lj]

Sir at 14:15 you subtracted 1 because (-3, -3) is making both x and y zero but at 18:55 there are two such pairs (-20, -30) and ( -30, -20) for which x and y becomes 0 seperately and both are unique pair it is not like ( -3, -3)

[@saiswaroopvandrangi2760]

if we check the factors pair 20,30; 4 pairs are possible which include 1. (20,30) using this we get x - 20 = 20; y - 30 = 30; i.e., x = 40 ; y = 60 2. (30,20) using this, x - 20 = 30 ; y - 30 = 20; i.e., x = 50 ; y = 50 3. (-20,-30) using this, we get x - 20 = - 20 ; y - 30 = - 30 ; i.e., x = 0 ; y = 0. this case is not possible as the question have reciprocals of x and y. So we don't consider this result and we do - 1 4. (-30,-20) using this we get x - 20 = -30 ; y - 30 = -20 ; i.e., x = -10 ; y = 10

[@ROHIT-SHARMA-897]

RESPECTED SIR KINDLY CLEAR ONE DOUBT. IN QUESTION 1/X+1/Y=1/3 INTEGRAL SOLUTIONS SHOULD BE (24*4 )-1 OR (24*2)-1 KINDLY CLARIFY WITH REGARDS ROHIT SHARMA

[@Rodha]

47. It was a mistake

[@ROHIT-SHARMA-897]

@@Rodha THANKS SIR FOR CLEARING THE DOUBT

[@snehamohapatra7039]

Why (24*2)-1

[@anisree4856]

@@snehamohapatra7039 because no of solutions will be (no of factors *2) And 1 is subtracted becuz 0 cant be in the denominator

[@anamaysingh8490]

@@vishwarajgaur3953 no there will be only one solution which needs to be excluded i.e. when x,y =(0,0) .......(0,-10) and (-10,0) wont satisfy the equation kindly check again

[@akankshaawasthi8728]

At 3:35 how he said 3×3 =9 factors I couldn't get it please somebody explain

[@Likki_likki]

100 can be written as 4 *25 , (which can be written as 2 square * 5 square ) for 4 digit three factors ( 1, 2, 4 ) and for 25 3 factors (1, 5, 25 ) so 3*3 = 9 factors, you can apply the same method for next problem and you will get 2*2*2

[@akshaysagar5235]

@@Likki_likki thanks for the explaination

[@songoku-jx3cb]

Why do we multiply factors with 4 in some questions but with 2 in some . Can someone explain

[@Copyninjaaa]

How to find factor of a number using shortcut? Please help 🙏

[@architjain28877]

SAME

[@akshatgarg3408]

For the last question how 2^4 ×3^2 and why not 2×2×3 is the answer

[@vineetichake5014]

Ravi sir has a shortcut for everything 😋

[@poornimashrivastava9968]

Sir, in the second example explained, isn't it entirely upto us as to how we factorise the equation. And in doing so, one will always get different number of factors (as the factorization changes). For instance, I factorised as: (x+1)(y-5/2) = 25 This way my number of integral solutions came down to only 6 (as 25 has only 3 factors). Kindly explain. Thank you

[@soumadipranjanbiswas1779]

Your equation is : (x+1)(y-5/2) = 25. If you simplify, the equation will be (2xy - 5x + 2y) = 55. But, Sir's equation is (2xy - 5x + y) = 55. I think there is some error in your factorization.

[@noobiedoo0077]

55-5/2=105/2 as you have taken 1/2 common...just write it down you will understand

[@maheshpatil5663]

18:40 if there are 24 factor means there should be 12 pairs of numbers and if 1 pair of number can be written in 4 ways then calculation goes in a way like 12*4-1 means answer should be 47.. correct me if I'm wrong.

[@naturelover-qr6rk]

It's a ordered question

[@himmyg]

in q 1 sir is saying no. of integral solos = 2x no. of factors but @18:48 we are multiplying by 4. it should be 2 right? or am I missing something ?

[@RV-nx1ok]

it should be 2

[@bollymood02]

yeah integral solutions is 4 , but while using prime factorization we multiply by 2 ......got it

[@bollymood02]

integral solution is 4 when calculating through conventional method

[@bollymood02]

@correct sir @Rodha

[@BakthavathsalanCR]

@ 9:46 can anyone explain why 2 is not multiplied in (2Y-5) and only done in (X+1/2). couldn't understand that part

[@nisheshojha3539]

2 * a * b = 2a * b = a * 2b not 2a * 2b. hope its clear

[@gadiadivya102]

@@nisheshojha3539 but its 2ab

[@anushkaxsilence]

Why is it 24×2 and not 24×4 at 20:56 ?? Can anyone please explain

[@saptarshimozumdar1657]

3:10 how did you get 9 factors? I am not getting that part.

[@aanyarawat9120]

same here

[@aashutoshverma1316]

(Power+1) factors ke liye

[@technocobraa9279]

Yes i am also not getting how to get those factors

[@parthdesai4778]

for anybody who doesnt understand the factorization concept i.e how 2 to power 2 x 5 to the power 2 became 9, check comment by anubhav chaturvedi and reply to that. Probably 10th or 11th comment.

[@coc5334]

Hlo bro actually me also not understa... It how it is 9 . Pls tell me how it is 9

[@parthdesai4778]

@@coc5334 I dont remember which problem but most probably its this. See, the factors were 2 squares x 5 squares right. So, we have to add 2 to the power and multiply. (2+1)(2+1) 3x3 =9. Also check the comment by ANUBHAV CHATURVEDI SOMEWHERE DOWN.

[@mohitpandey6228]

Sir, In 2nd question why can't we do with the same method as Q1 by substracting 3 on both the sides we'll form an equation please reply

[@AyushKumar-wl8cx]

bhai kitna syllabus ho gya ? cat 1st time de rhe ya 2nd??

[@debahotikhound4045]

For the second last question, positive integral solutions will be 12?

[@rajatyadav3699]

24 will be the answer

[@aanyarawat9120]

how at 6:40, we got 9 factors???

[@KrishnaSharma-op6io]

Same doubt

[@aanyarawat9120]

that's because of a formula, when we add the powers to +1 and multiply, we get total no. of factors. for ex: 2²+5²= (2+1)(2+1)=9 we simply added the powers

[@KrishnaSharma-op6io]

@@aanyarawat9120 thank you ❤️

[@Mombakesdaughtertales]

Could please someone tell me how sir did factor what is the logic behind 2*3*4 at 18:32 pls pls how to do factors

[@gadiadivya102]

here 2^3 * 3^1 * 5^2 so we are taking the powers and adding each power by 1 so we got 3+1 * 1+1 * 2+1 = 4*2*3

[@209akashkumar4]

read number system's factors topic of rodha

[@anujabarnwal5767]

can anyone explain me how at 3:40 it is 9 factors?

[@_NavneetDixit]

No of power of prime factor +1 => 3*3=9

[@bollymood02]

first prime factorized the number and then (power of the number +1)...... 100 : 2^2*5^2 : 2+1=2+1 (powers of factors +1

[@AniketKumar-ew3ns]

21:08 , why are we subtracting only 1 from 48 , there is also case of (x,y) = (-20,30) (20,-30) where x and y can be zero , so we should subtract 3 cases

[@fadhilu5171]

those anserws will be -600, not +600,

[@AniketKumar-ew3ns]

@@fadhilu5171 thanks

[@country.mirror]

​@@fadhilu5171 answer ultimately become zer

[@raghav_daga]

for positive, it will still be the no of factors no?@@fadhilu5171

[@adityainsta-h8b]

at 18:25 thieir is wrong concept as factor of 5^2 is 1,5,25 = total 3 factors as at 6:25 everyone can see that 5^2 = total 3 factors

[@vaishantdang4215]

18:47, how does it become 4*2*3= 24 factors, i am not able to understand this concept

[@learnwithbina4100]

me too not able to get this concept

[@044karthikeyans6]

​@@learnwithbina4100did u get this concept by now ?

[@nithishgaming6247]

= 2 × 3 × (10)^2 = 2 × 3 × 100 = 2 × 3 × 2^2 × 5^2 = 2^3 × 3 × 5^2 = 4 × 2 × 3

[@abhinavyadav6987]

In question 2 of this video, out of the 16 solutions, 2 solutions i.e. 1 and -5 make the LHS of the equation as 0. So, do we count them as solutions?

[@VinayKumar-vk3tq]

Can you re-check your calculation once? I don't think any of the ordered pairs of the solution make the LHS 0. (1,-5) leads the original equation LHS to 0, but is not a solution. (2*-5 -5)*(2*1+1) = -15 * 3 = -45 != 105. You made a little conceptual mistake with the nature of solutions. 1 and -5 are not two solutions out of 16. Each solution is going to be an ordered pair of the form (x,y) which contains the respective values of x and y which together satisfy the equation. The solution pairs are: (for (2y-5, 2x+1)) (1,105) --- (105,1) (3,45) --- (45,3) (5,21) --- (21,5) (7,15) --- (15, 7) The remaining 8 solutions are going to be negatives of the above given solution such that their product remains positive and of the same magnitude.

[@anonymous-ek5iq]

is vdo ke ques 2 me factor 8 kese aaya, factor kese nikalte h bata skte ho

[@VinayKumar-vk3tq]

@@anonymous-ek5iq Ye samajhne ke liye number system mein factors ki video dekh lo ek baar. 105 = 3 x 5 x 7 All factors will divide 105 completely. Each factor can either have 3^0 or 3^1 as constituents. The same is true for 5 and 7 as well. So, total choices to create factors/Total number of factors = 2 * 2 * 2 = 8 (3^0 or 3^1) 5^0 or 5^1 7^0 or 7^1

[@abhinavyadav6987]

@@VinayKumar-vk3tq Thanks for helping mate. I figured out where I got it wrong. It's the value of x and y which become 0 and not the equation.

[@rkguitarist]

why 2*2*2* = 8f how u calculate it???? couldn't get it......

[@mayurisethi9525]

hey , if you got the ans can you help me with it

[@rkguitarist]

@@mayurisethi9525 i left mba prep

[@kanakh7775]

the solution at 19:00 where we're multiplying the number of factors by * 4 is incorrect right? Please confirm.

[@kanakh7775]

sir has solved the same question again by *2, so not sure if these were 2 different cases or a mistake.

[@manthansahu5582]

Second one is correct...*2

[@kanakh7775]

@@manthansahu5582 cool, thanks

[@kapilgugoria2002]

Typo it is

[@UMESHMKAKDE]

@@manthansahu5582 it means previous all questions which is multiply by *4 which Is wrong?

[@SamarthDave-u2g]

can smone explain how that 4x2x3 came

[@aryansaini452]

Same question

[@SamarthDave-u2g]

@@aryansaini452 add one to all the powers then multiply

[@aryansaini452]

@@SamarthDave-u2g thx bro ❤️

[@nithishgaming6247]

= 2 × 3 × (10)^2 = 2 × 3 × 100 = 2 × 3 × 2^2 × 5^2 = 2^3 × 3 × 5^2 = 4 × 2 × 3

[@amansaxena7976]

Why did he multiply 24 * 4 while solving the shortcut it should be 24*2-1

[@Theपक]

Its total integers solution including negative integrs aswell

[@divyasadadekar9831]

@@Theपक so basically here "2" is the constant term right which should be multiplied always ?

[@devanshusingh4739]

10:25 we got 16 as number of integral solutions for (2y-5)(2x+1) but how many out of them would be integral solutions for x and y, because that is what question asked?!

[@namansharma2721]

16 are the number of values/solutions for x and y only

[@danishhussain5592]

14:29. Since if you substitute (-3,-3) in the denomination. You will get -2/3 in the L.H.S which is not equal to 1/3 in the RHS

[@vishwashachadad5646]

(-3,-3) are solution for (x-3) and (y-3), not for x and y

[@abhishekpatidar7740]

@@vishwashachadad5646 thanks bro i have the same doubt...

[@amazingwonders6926]

​@@vishwashachadad5646❤

[@amishiverma5340]

At 18:05 why sir multiplied 24 with 4???

[@deepikadhiman6913]

Bcoz one integral value has 4 soln which is +-, -+,++,-- that's why

[@thefashionhouse5701]

sir why it is 24 x 4 -1 instead we have to multiply 2 .

[@simplethings7000]

mistake

[@rohitbehera4524]

It should be 24*4-1....right??.....As we to find the negative solutions as well

[@prateekbirthal9649]

2*no of factors includes the negative solutions

[@GaganSharma-c8u]

Sir what is ordered form and what do you mean by variables are given in the first lecture of simple equation in1st question there you also say variables are given so it has ordered solutions .sir I'm not getting this thing please explain

[@namansharma2721]

Watch Number System videos by Ravi Sir

[@prashitahurmade4402]

At 22:10 I don't understand how 15 factors will come??

[@mack.manika13]

Exactly same i m facing issue with

[@nirajpradhan1992]

Hello sir, In few question you have multiplied the factors by 2 to get no. of integral solution. And in few question you have multiplied it by 4 to get no. of integral solution ????🙄

[@lakshmisathyan2965]

same doubt

[@niveditharajesh71]

how 2 cube sir

[@garimasahu193]

7:00 for soln(1,100): (X-1)(y-1)=100 1-1)(100-1)=100 Not satisfied....please correct me where I'm wrong

[@sundramgupta9974]

x and y are not 1 and 100 here...,.. x-1 and y-1 are 1 and 100 respectively. thus making it x-1 = 1 and y-1=100 x= 2 and y = 101

[@niranjansv9842]

Why did u multiple with 2 only on 1 side

[@anubhavchaturvedi715]

Can somebody please help how (2 to the power 4 X 3 to the power 2) has 15 factors.

[@nivethakrishnamurthi6410]

If a number is in the form a^p * b^q where a and be are prime numbers then the no.of factors of that number can be calculated as (p+1)(q+1)

[@anubhavchaturvedi715]

@@nivethakrishnamurthi6410 Thanks :)

[@saikartheek992]

2^4 means there are 5 solutions Becoz if you take 4 as 'p'..then the formula for no.of factors is P+1 & for 3^2 there are 3factors.multiply both the factors 5*3=15.

[@shariqueakhtar8349]

@@nivethakrishnamurthi6410 thanx you saved my life

[@deenadurai1734]

Thank you

[@neerajnandal6820]

In 10:29, can anyone explain why sir did 2×2×2?

[@chiragshetty6140]

Find the factors for the number in prime numbers. Then add 1 to power of each number and multiply them. 105=3*35. Further break it down. 35= 7*5 So 105=3*5*7. The powers are. 1*1*1 Each have 1 power. Now add +1 and multiply them. It becomes 2*2*2

[@amanpoddar4758]

do you mean positive integral solutions for the same question?

[@navneetmaurya5297]

both positive and negative soln

[@ss590]

Thankyou 💜 so much sir 🙏🏻

[@ananyamishra608]

at 18:42 how do we get 4x3x2? could someone please explain?

[@nithishgaming6247]

= 2 × 3 × (10)^2 = 2 × 3 × 100 = 2 × 3 × 2^2 × 5^2 = 2^3 × 3 × 5^2 = 4 × 2 × 3

[@jatinpatil372]

Watch no of factors video

[@BNRFake]

Sir factors kaise find out kar rahe ho...I feel like rocket science 😭

[@itsshowtime1720]

If N= a^p.b^q.c^r where a,b,c are prime factor and p,q,r are positive integers then no. of factors of N will be (p+1)×(q+1)×(r+1). Eg- 100= 2²×5² No. Of factor (2+1)×(2+1) = 9

[@harshgupta-kt7kp]

sir in last 2 questions please explain why you multiplied by 2 instead of 4 ? please

[@priyankmehra7416]

it is because: there will be n/2 pairs for n factors. and those n/2 pairs will have 4 patterns each.: (x,y), (y,x), (-x,-y),(-y,-x) therefore, (n/2)*4 = 2n. Hope this solves ur issue.

[@shashankkumar6206]

@@priyankmehra7416 at 10.18, how 3*5*7 gives 2*2*2 = 8 factors ? How ?

[@priyankmehra7416]

Shashank Gupta if N = a^p * b^q * c^r, where a,b,c are prime numbers, then N will have (p+1)*(q+1)*(r+1) factors.

[@shashankkumar6206]

@@priyankmehra7416 Thanks got it👍

[@soundsmeller5586]

@@priyankmehra7416 so how in previous question he took *4 instead of *2

[@saikartheek992]

95 or 47????

[@NehaKumari-zn2eb]

47

[@tusharnikose5661]

2xy-5x+y=55 in this question i took 2y(x+1)-5x-5=55-5 (2y-1)(x+1)=50 so 50=2*5^2 so (1+1)(2+1)= 6 no of intergral come out to be 12 in my case what should i follow and what mistake im doing ? @rodha @ravi sir but you answere came out to be 16

[@danishhussain5592]

How can you take 2y common when there is no 2y term

[@rajatpatel4333]

bro u did a mistake in taking common factor thr ... Factors r (2y-5)(x+1/2)=55 -5/2 So we can write (2y-5)(2x+1) = 105 = 3×5×7

[@radhikakodan5352]

Can anybody explain me that after 100= 2^2*5^2 then how these integral factors 3*3 came ???? What’s the logic

[@karthikachandran5348]

add one to the power,then multiply, eg here powers are both two so (2+1) x (2+1) we get 3x3=9, if say factors are 2 power 3 and 3 power 2, then factors are = (3+1) x (2 +1) = 4x 3 = 12 factors

[@swatingle]

Can anyone please explain how to find the integral solution of x^2+y^2. This topic is not covered in the video. Please anyone?

[@shatambhagat3097]

facing same problem , they are saying to watch "numbers system" playlist .

[@ambarsaxena7687]

its quadratic level questions not simple equation level

[@cumulusmusic100]

Thank you Sir 🙏

[@dipanwitakarmakar8424]

At 3:35 , can somebody please simplify how could there be 3×3=9 factors from 2^2×5^2

[@vidushichaturvedi]

No. Of factors a^p*b^q no. Of factors= p+1 * q+1

[@vinitashukla9346]

At 3.41 there is 3*3 as number of factors...how is that?

[@കള്ളിയങ്കാട്ടുനീലി]

refer number system, factor one

[@shrutisingh1519]

How is sir getting the number of factors

[@songoku-jx3cb]

By taking the powers . See his first video on factors at around 7:00

[@userb7026]

left me confused with the last two questions

[@ParvinderSingh-zf4yy]

At 10:28 ,2*2*2 means ?,how

[@satishchodisetti7896]

At 14.00 no of sol are 3 only but sir write 5 how that possible? The sol are 1,9. 9,1 and 3,3

[@samdavidc7166]

Negative (3,3)

[@subratkumarjally149]

why 15* 2 no of factor not 15*4

[@abhishekgautam6331]

10:05 h0w 2×2×2 came from 3×5×7 factorial

[@vinayaksharma7001]

3*5*7 from this we will take number of factors as like (Taking all the previous powers) 3 as 3° and 3^1 =total 2 5 as 5° and 5^1= total 2 7 as 7° and 7^1=total 2 Therefore the total factors came out to be 2*2*2=8

[@moviesverse21]

Sir I have a doubt- how i can find factors..

[@Ashish-ht1ee]

please also lmk if u do find a way

[@rushikesh1206]

thankus sir!😍

[@lordmaster9007]

I have a question 1. When are we supposed to know that ordered solution is required as an answer? 2. What is an ordered solution ? @Rodha

[@meghanas8345]

If variables are given in question, Like a+b = 5, a=1,b=4 and vice versa is also considered Hence order is considered If the question is like sum of 2 numbers is 5, Then (1,4) is considered, vice versa doesn't make sense. This is unordered

[@nish9927]

Hi Sir, Is simple equations important topic for CAT 2023 ?

[@Someone-yg9bx]

Same question 🥲 I think quadratic equation are the most important topic

[@tanmayrijwani7914]

Linear quadratic cubic and biquadratic

[@Easypeazy12]

Sir at 6:30 & 9:20 we are not counting the solutions with x or y=0 by using the original equation. I mean shouldn’t we use that too?

[@vineetichake5014]

even if you go your way, the answers will be same

[@sojabhai5883]

i thought about it but when i solved i found no condition like this, solve it you will automatically understand

[@parthdesai4778]

Can anybody please explain how 100 became 2 square x 5 square or how at 10:05 105= 3x5x7?

[@bhormagan7444]

factorization

[@bollymood02]

first prime factorized the number and then (power of the number +1)...... 100 : 2^2*5^2 : 2+1=2+1 (powers of factors +1)

[@Shivam_General_Fitness]

Thanku sir

[@anjalikale4231]

In the last question why it is into 2 ?

[@naveenkamath907]

every factor will have 2 solution in the form (a,b) and (b,a) so no. of soln = no. of factors*2

[@rkguitarist]

in last sum how 2^4 *3^2 = 15f is come???

[@vishalrathi13]

because 5*3 =15. in number system you must have learnt that power +1 of one prime factor * power + 1 of other prime factor

[@peacefulrelaxingmusic9669]

at 10.08 in video 2 x 2 x 2 kaise aara hai like factors kaise nikalre hai vo he nahi samjhra mujhe bas can anyone help

[@chiragshetty6140]

Find the factors for the number in prime numbers. Then add 1 to power of each number and multiply them. 105=3*35. Further break it down. 35= 7*5 So 105=3*5*7. The powers are. 1*1*1 Each have 1 power. Now add +1 and multiply them. It becomes 2*2*2

[@adithyaveldurthi9449]

thanks bro @@chiragshetty6140

[@balavignesh2363]

@16:33 is it (abc)^2 or a b c^2??

[@vasavi5337]

a b c^2

[@shashankkumar6206]

at 10:18, how 3*5*7 gives 2*2*2 = 8 factors ?

[@nehasingh5593]

Power of all prime base in the number is 1 so power+1 and then multiply (2*2*2)

[@shashankkumar6206]

@@nehasingh5593 👍

[@sojabhai5883]

18:40 i think sir mistakenly multiplied by 4, it would be2

[@ShubhamPandey-jk9gw]

Ya you are right there is no other explanation .

[@shreyasingh9207]

Why did he took 2×2×3? At 18:30

[@sojabhai5883]

​@@shreyasingh9207kha h

[@mridulsharma06]

GOAT

[@cinderellaks8514]

sir love ur arithmetic playlist, but ur algebra playlist is such a disappointment!

[@Rodha]

Didn't get time to upload full. Plz watch Advance Algebra workshop

[@yashasharma9963]

Very easy explanation! 🙏

[@Tuuuuusssjjjjjjnrnfnnfnfn]

did u get into any IIM?

[@swapnilrajput8086]

@@Tuuuuusssjjjjjjnrnfnnfnfn no she did not

[@Tuuuuusssjjjjjjnrnfnnfnfn]

@@swapnilrajput8086 how do u know?

[@swapnilrajput8086]

@@Tuuuuusssjjjjjjnrnfnnfnfn she is in MDI gurgaon . i checked on linkedin

[@swapnilrajput8086]

how 3X3 at 3:40 ? pls explain anyone

[@nitish5697]

Finding number of factors of a number.

[@deepanshugarg1497]

because we have to identify every possible factor kind of permutation and combination type of thing i guess

[@bhoomika7304]

hi sir please explain about the factorise in reciprocal case

[@thechannel3420]

sir, why is it 2 x 2 x 2 , after 3 x 5 x 7 integral solutions

[@gouravroy2285]

Watch "numbers" playlist to understand this.

[@thechannel3420]

@@gouravroy2285 ok I will definitely do. 🙏

[@ayushsingh3262]

@@gouravroy2285 bhai abhi yha pe to bta skte ho ap agar ap abhi bta dete to ye doubt clear hota fir hm check kr lete wo playlist 🙇🏻

[@restyletime4918]

20:47 why 24x2 ? , but last sum it was 24x4 ? can anyone please explain

[@darkking9249]

I think he mistankly taken 24*4 in previous one pointed same issue

[@restyletime4918]

@@darkking9249 thanks for the reply

[@AnushkaSinghh_]

@ 18:34 how did we get 4×2×3?

[@crictrid267]

add +1 to the powers to calculate the factors

[@AnushkaSinghh_]

@@crictrid267 thankyou so much

[@Mombakesdaughtertales]

@@crictrid267can you please elaborate on

[@shobhitrao]

HOW 4x2x3..CAN U PLS EXPLAIN THIS STEP?

[@soumyajitmondal220]

No. Of total factors

[@choprasamkitsuresh5513]

@@soumyajitmondal220 plz elaborate

[@ajithkumaar3473]

formula for number of factors a^p * b^q = (p+1)(q+1) where a and b prime numbers , eg 216 = 2^3 * 3^3 num of factors = 4*4=16

[@Sanchofan1]

Better check out his initial videos upon factors

[@bodhisattwadas4622]

sir too many calculation mistake

[@raviprakash6021]

Result of recording at 4am :P

[@h96vardhan]

No problem sir....You helped us a lot by puting brilliant videos, thanks for these.

[@choprasamkitsuresh5513]

Sir plz tell me abt 4×2×3 =24(How to do it)

[@ajithkumaar3473]

formula for number of factors a^p * b^q = (p+1)(q+1) where a and b prime numbers , eg 216 = 2^3 * 3^3 num of factors = 4*4=16

[@Mombakesdaughtertales]

@@ajithkumaar3473smjh ni aya

[@hunter_tsp3888]

Lots of silly mistake sir

[@amritarya2923]

In the last question how's that 2^4 and 3^2? I didn't get that can anybody pls explain it to me it would be very helpful. Thanks in advance:)

[@princejha9950]

just factor the 144 (i.e 12^2) number and you will get 2*2*2*2*3*3, (2^4*3^2)

[@faizankhan-ts4ho]

to understand that you need to watch factors video in the start of quants.

[@rishvanerle422]

can anyone please tell me how it is 4*2*3 in 20:30 mins please anyone!!!

[@BoT-gb7qg]

At 10:20 , I didn't get how to get factors . how is that 2x2x2 is coming , can someone explain ?

[@Ananya.RC.]

watch numbers playlist.

[@shashankkumar6206]

I know there is a confusion. Remember the shortcut sir explained earlier?? i.e., No of factors *2 gives the total solution. So when you are solving by the number of factors method, then you need to multiply the number of factors by 2. If you are approaching the solution the usual way, then we multiply it by 4 (x, y), (y, x), (-x, -y), and (-y, -x) As far as, if there is any mistake by Sir then Yes, and he solved the same question again and corrected it. Don't fret over it and waste your time. Hope it helps!

[@SamarthDave-u2g]

can you explain how that 4x2x3 came

[@hriutiksawant7156]

​@@SamarthDave-u2gWatch factors videos from number system

[@nithishgaming6247]

​@@SamarthDave-u2g= 2 × 3 × (10)^2 = 2 × 3 × 100 = 2 × 3 × 2^2 × 5^2 = 2^3 × 3 × 5^2 = 4 × 2 × 3

[@harmeetsingh1]

@@nithishgaming6247 SAMJH NAHI AAYA MATLAB 2^3 × 3 × 5^2 YE TO SAMJH AGAYA KAISE AAYA BUT HOW 2^3 BECOME 4 AND ALL OTHER / PLZ EXPLAIN ANYONE

[@shariqueakhtar8349]

4*2*3 didnt get this part @18:20

[@anushkasingh123ar]

Same

[@rishabhsethi5956]

For the first question, we can also get the eqn: (y-1)(1-x) = 98. Then we'll get 2^1 and 7^2 . 12 total factors then

[@jaidevtyagi1033]

in your eqn it should be -100 and not 98

[@snehilkumar6643]

If you simplify your equation then it won't match the original question

[@vatsalverma4557]

Can anyone plzz help , How there are 9 factors in 1st question At 4:00

[@tusharpanda3528]

Its the formula ..3 x 3= 9 factors...(2+1)(2+1)..where 2 ,2 are the powers of prime factors...look it up in the prime factors video of RODHA

[@m_atul0]

@@tusharpanda3528 which video exactly

[@govindgoyal8633]

Sir How are you getting no. of sol. by factoring the RHS. Can't get that part please help