Inequalities 3 | CAT Preparation 2024 | Algebra | Quantitative Aptitude

Advance Algebra by Ravi Prakash | Quantitative Aptitude for CAT 2024
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[@binnapaul2126]

Sir, I have been following your content for some time now and I have to say there are so many concepts taught here that can't be found anywhere else which makes solving questions so much easier and faster. Thank you so much sir. Also a humble request, please do upload videos on pipes and cisterns back again.

[@Rodha]

Never deleted

[@yashasharma9963]

Great level of thinking + great level of explaining that thinking = Rodha.

[@Atulvermaa76]

is that you comment on all videoss

[@monishmoolya8919]

We got a stocker here

[@AkshayN-rh5ek]

@@monishmoolya8919 stalker*

[@aahistachirps]

Thank you so much, sir. This video has cleared all my doubts and your methods are much easier than the conventional methods of AM and GM.

[@harshalxd7533]

Super level of Questions to raise the thinking bar ! thank you for such videos!

[@phoenixcrew6045]

RAVI SIR YOU ARE A GEM OF PERSON NEVER HAD A TEACHER LIKE YOU BEFORE ........ SIMPLY THE BEST!!!!!!! THANK YOU VERY MUCH😍

[@ksaikiran1781]

i donno why but directly applying AM-GM concept is far more satisfying and less time consuming than the traditional method discussed above

[@devashish4690]

true..wanted to just crosscheck if at 7:00 the answer should be 3^9? please acknowledge

[@bhaskarmaniraj]

@@devashish4690 Yes, even i got the same answer through am and gm method.

[@Rodha]

@@devashish4690 no. Right answer is 3^10

[@jaiganeshbaskar9888]

@@devashish4690 The value that you got is the maximum value of (x^2.y^3.z^4) by AM-GM method but in the question they asked the maximum value of (x^4.y^2.z^3) so for this case using AM-GM method will not fetch you the result.

[@sujalsonkar1657]

will you please explain how ?

[@vineetichake5014]

The great Ravi sir!

[@ayushisingh1471]

Awesome Content .......Thankyou Sir.

[@prithasingh6254]

The first question was easily solvable by linear equations.

[@vinaykapil1413]

Sir, a humble request, please do upload videos on coordinate geo back again.

[@Daredavil_298]

Super content sir👍🙏🙏

[@swapnil5162]

Great 👍 sir

[@nidhiyadav8903]

Thanks a ton sir🌼

[@PratyushAtghara266]

interesting topic, well explained👏

[@tanmaydey3008]

Thank You Sir

[@aashita203]

Legend🤩

[@kunalmjain]

Sir can we take ratio of x y z and then solve eqn

[@muskantiwary606]

How can u identify the no. Is maximum or minimum? In 7th question, 2 is minimum and -2 is maximum . How please explain

[@Shivam_General_Fitness]

Thanku sir

[@adityajain1984]

at 17:41, min can be 0, if we put a=-1

[@AbhishekKumar-kl9ug]

@ 7:03 ques, shouldn't the values of x:y:z (max) be 24:8:9 got it by the traditional method we did in prev ques to this one and eventually we'll be getting largest value (24)^4(8)^2(9)^3. @Rodha sir plz correct me if I'm making an error.

[@avijanpaul9367]

Well it’s just the ratio not the real answer to the question

[@arimachezhian8631]

Since it was never mentioned but both x and y to be positive in the first question. Can't we just assume a big value of negative x and corresposing y and yield Infinity as an answer

[@happy_bolta_hai]

Sir in first question... Cant X be -15 and Y be 15 as 2(-15)+3(15) = 45 and (-15)² + (15)³ = Maximum Value of x²y³.

[@debdipdutta3953]

this is the second lecture in inequalities🤗

[@neelammaurya8970]

in frst ques.if we keep close value as x=7, and y=8 then we'll get maximum value....y don't this to be done

[@DhanushAdns]

Then the value of 2x+3y would be 2(7) + 3(8) = 38

[@devarshpanchal9743]

Sir how is it possible that number and its reciprocal sum is =2 ifi take 100+1/100 then it is more than 100 how can it be 2 ?

[@swapneelrao8276]

Bro, read the questions carefully. Here he never said the value is 2. The "minimum value" is 2.

[@Rodha]

Min value is 2

[@vibhavadhikari8013]

2:29 Max value of (x^2).(y^3) is not 243 but infinity. For instance, x=-3, y=7, satisfy the equation 2x+3y=15, thus making (x^2).(y^3)=3087, which is greater than 243... Keeping reducing the value of x by 3 and y by 2 indefinitely, thus x approaches negative infinity and y positive infinity, thereby making the answer as infinity...

[@garlapatisaibhargavreddy4834]

Actually question was incomplete. Their should be x and y are natural numbers. Hope you got it

[@anoshirani5682]

The 1st question is for maximum and 3rd question is for minimum, but we use the same rule for both. How is that possible?

[@kronikevaporation6007]

Look intently. 1st question is asking for product and 3rd is asking for sum. It's maximum for product and minimum for sum.

[@bhaskarmaniraj]

@9:15 I got the answer as 9. through am and gm method.

[@priyabratanayak4359]

Bro can you explain the am and gm method or share some link where i can find those!!

[@bhaskarmaniraj]

@@priyabratanayak4359 You can learn it from Takshzila KZbin channel.

[@bond-hn4wd]

@@bhaskarmaniraj but its not full, we can still get problem with the fact the if we got maximum of addition and minimum of multiplication, then we have to rely on his teaching.

[@ankitsharma-pf3zx]

u did calculation mistake... in gm part u have to write product as [(2x/4)^4][(3y/2)^2][(4y/3)^3] ..now u will get right

[@pradiptode7087]

@6:15 it should be (3 raised to 9)

[@parvathymarangattu7097]

Yes it is 3 raised to 9

[@parvathymarangattu7097]

And answer will be 19683

[@TarunAsthana]

Is there any formula for (AB)min. When A+B=constant ?

[@AbyjithK]

Take A=1 and B= n-1 if A+B=n This will give the min value

[@vibhavadhikari8013]

17:37 Error... Minimum value of expression is not 64, but 0. Put a=b=c=-1.

[@Rodha]

1st read the main statement Question at 12:22. a,b,c,d are positive real numbers. Already given.

[@shishir6340]

2x+3y+4z=27 . solution is wrong. if we calculate x,y,z by normal method we get the values as x=8, y=8/3,z=3. this gives the maximum value as : 786432. but if we put your values to get maximum we get a smaller number than this.

[@avinashbajpai7091]

Bro it's (2)x + (3)y +(4)z =27 . So if we put your values the sum will exceed the constant value of 27.

[@akshat9282]

according to your values for x, y, z; the initial equation of 2x+3y+4z=27 is not satisfied