Understanding Oscilloscopes - Bandwidth

[@kumara5288]

Nice explanation about Bandwidth. Thank you so much!

[@pauldenisowski]

Really appreciate the comment - thanks!

[@krish2nasa]

Excellent explanation as always. Thank you very much.

[@pauldenisowski]

Thanks for the feeback!

[@sinojha1]

Great presentation as always, thank you!

[@pauldenisowski]

Thank you!

[@shalom-shlomi-zigdon6465]

GREAT presentation, excellent speaker, Thanks

[@pauldenisowski]

Thank you!

[@ChristianSamsung-z6e]

Hi, the flat response in the graphs on most pages don't correspond with the BW indication...just on page 12 it is shown right. Otherwise really good...thanks!

[@pauldenisowski]

Yes - on slide 11 the BW line is in the wrong place (should be to the right) and on slide 9 it's correct for Gaussian but should have moved to the right for Flat. All the other slides are correct. Thanks for letting me know!

[@Mr.Not_Sure]

Joining the party, on slide 5 lower BW waves should be shifted, because each edge starts at the same moment, but at low BW it rises slower.

[@AdelAlmahmoud-yv3nd]

Sir, how does the bandwidth relate to the scope sample rate ? and should the sample rate be at least twice as the bandwidth of the scope ? Thanks Eng.Paul

[@gonzaloroca5143]

Very useful information.

[@pauldenisowski]

Thanks!

[@genericdynamics6618]

This is great content

[@pauldenisowski]

Thanks! There's more oscilloscope-related content coming soon!

[@arash4232]

Hi, Thank you, that was excellent. Is the 10x on the probe related to this topic as well? How does it contribute? Regards.

[@pauldenisowski]

Thank you! The bandwidth of a probe is a function of several things, but the attenuation (10x) is not a significant contributor to probe bandwidth in most cases.

[@arash4232]

@@pauldenisowski thank you.

[@ゾカリクゾ]

Maybe I'm misunderstanding the comment, but doesn't a 10x probe increase probe bandwidth?@@pauldenisowski

[@pauldenisowski]

@@ゾカリクゾ 10x probes generally have wider bandwidths than 1X probes because the capacitance in the probe tip of a 10x probe helps to cancel out the inherent capacitance of the scope input - it's this capacitance, not the attenuation _per se_ ,that leads to wider bandwidth. Hope that makes sense!

[@ゾカリクゾ]

Thanks for the clarification! Totally clear now.@@pauldenisowski

[@yosmanyhernandezsanchez9760]

Thanks a lot for this video.

[@pauldenisowski]

Thanks for watching!

[@lillyzegarra8025]

Why are you saying that frequency attenuated by 3 dB is (~30%)? WTF!

[@pauldenisowski]

If you listen to the spoken text (or turn on subtitles), I say "The bandwidth of an oscilloscope is defined as the frequency at which the measured amplitude of a sinusoidal input signal is decreased or attenuated by 3 dB" Since oscilloscopes measure voltage, a 3dB reduction is approximately 70% of the original amplitude (sqrt(2)/2). You're absolutely right that it would make no sense to talk about frequency being decreased by 3 dB :) But I can see where the bullet point might be confusing by itself, so thanks for letting me know!

[@gopip2605]

As per mentioned formula, -3dB = 20 log10(Vout/Vin) 0.7=Vout/Vin This is the standard ratio as it attenuate 3dB. So, if Vin=5v, then Vout=3.5v if Vin=10v, then Vout=7v Then it reduces 30% whatever the input voltage.