Introductory Fluid Mechanics L14 p4 - Buckingham Pi Example - Drag on Sphere

[@carlostma643]

This is the only video out of around 20 I've watched on this that makes this makes sense!

[@9LimaAlpha7]

could u help me out hrere

[@alvarodomenech358]

thanks for this great video! It does help students all around the world a lot!

[@khaledabdulaziz9063]

Best videos about this theorem

[@LoneWolf-zj8it]

THANK YOU VERY MUCH (South Africa)

[@issaNjonyProductins]

This was so helpful Thanks alot

[@Ruddog12]

how do we determine which Pi term is a function of the other ? or is it arbitrary?

[@lpfan2457]

Hopefully, you are already done with this exam and earning a lot of money!. But for the others that still struggle with this. I think he mentioned it in the beginning or in the last video. You have to look out for dependent and independent variables. In the case of force on a sphere, the force depends on all the other parameters. Thus you would write F = f(p1, p2, ...). You could also look at the pressure drop through a pipe, then delta_p = f(p1, p2, ...). I hope this makes sense.

[@abdulrahmanali7594]

thank you so much for this helpful video.

[@mfoucault1984]

ron hugo, do you (for any chance) have a lenovo yoga book? or i just wondering how do you write with your optic pen and also use paper at the same time? Thanks in advance. Great series of lectures.

[@jcnot9712]

seemed to me like he was looking at the pages for reference, not actually writing on them.

[@muhammadmubashir2615]

thank you sir.

[@sunmichoi6888]

thank you!

[@beyondsyllabus954]

thanks a lot

[@CEBMohammadyounusKhan]

Small f kiya h??

[@9LimaAlpha7]

this is utterly confusing !!!

[@human2373]

07:59 -2 -b = 0 b = 2 minus cancels out

[@goncalo3940]

That is actually incorrect. To check, just plug -2 in place of b, -2-b would be equal to -4 instead of 0. Starting from -2-b=0 you can add b on both sides -2-b+b=+b, where the left side b cancel out, remaining -2=b or b= -2. You seem to have canceled out the minus sign in the beginning, -2-b=0 is in fact the same as -(2+b)=0, but that still leaves b+2=0 which is b= -2.