Root Locus Technique | Solved Problem-1

Root Locus Technique | Solved Problem-1 | Control system

Рет қаралды 47,691

Triple-E: Sudhanshu

Күн бұрын

Пікірлер: 135

@mabdllahjutt2931 7 ай бұрын

Thanks sir aj mara paper ha or ap ke video dakh kar sari smj a gayi impressive love from pakistan

@rockingediting652 7 ай бұрын

Amazing explanation❤. You didn't just throw equation and started bullshit talk like other KZbinr, rather you explained it in logical and beautiful way so that even before exam students can understand easily (Edit :- plz cover more topic like Bode plot, Nyquist Plot, Etc. i have exam in 4 days 😢😅)

@triple.e.sudhanshu 7 ай бұрын

@@rockingediting652 Thanks a million for such a wonderful observation & your kind gesture ❤️ And I will try to upload the videos asap!

@learnwithJahan-o4e 3 күн бұрын

Best explanation,, watched this so many times for my exam ❤️

@mansimore1383 9 ай бұрын

This topic is so tough for me before,but the way you covered each small point clearly,it helps a lot.. thanks sir, ✨

@ashishkumarprabhakar7419 8 ай бұрын

Bhut bahut dhanyawad bhaiya ji ....ye topic mere liye bahut tough tha lekin aap to ese bahut hii ashan kr diye hai ❤❤❤

@NiranjanKumar-vc3vg 8 ай бұрын

Kya sikhaya hai bhaiya, proper concept , to the point, clarity wahhh 🔥

@triple.e.sudhanshu 8 ай бұрын

Shukriya😊

@eesagar 10 ай бұрын

Thank you sir❤

@atharvarajput3748 2 ай бұрын

Bhai tu ek number hai haq hai lala teko aise hi aaage badte rhe dinesh sir ka 2nd version hai tu love u kalyan se bhaut pyaaar❤️❤️❤️❤️❤️❤️

@AmreshGaurav 8 ай бұрын

WAAH... BHUT BHUT DHANYAWAD BHAIYA.

@krishnaghatol1694 Ай бұрын

Maza aagaya 😂 Itne acchese kisine nahi samjhaya Root Locus ❤ Thank you bhai!!!

@triple.e.sudhanshu Ай бұрын

@@krishnaghatol1694 🙏

@hayazainab2402 8 ай бұрын

This is such an amazing explanation.It is such a complicated topic that you made so easy sir.

@triple.e.sudhanshu 8 ай бұрын

Thank you dear❤️🙏

@samrat5093 7 ай бұрын

Very nice teaching... Please continue

@triple.e.sudhanshu 7 ай бұрын

thank you!

@Makarov-- 8 ай бұрын

Hello Sir, I am stuck at a mcq question with the same transfer function. The characteristic equation of a closed - loop system is Which of the following statements is true? Options: 1. It's roots are always real. 2. It cannot have a breakaway point in the range -1

@triple.e.sudhanshu 8 ай бұрын

Pay Attention!! In such types of questions you have to go through each option to check the validity. Option-1: You have to simply solve the characteristics equation and find the multiple values of "s". If any values are not complex poles then it will be true. Option-2: Just locate the poles on the real axis and check for the existence of the root locus, you will get the idea whether breakaway point is required or not and if required then between which poles it shall exist. Option-3: Number of roots located at infinity directly depends on availability of poles/zeros in the question. You can find it using the following expression; *Number of roots located at infinity = (Number of poles - Number of zeros) Option-4: Just go through the same process as in option-1 i.e. find the values of poles and then plot on the s-plane it will be clear whether there is complex poles exits or not. If there are further doubts, just let me know! Stay connected! Enjoy the learning😊

@Makarov-- 8 ай бұрын

@@triple.e.sudhanshu Thank you for the reply sir, I still have one doubt though. The Characteristic Equation will be 1+G(s)H(s)=0, correct? so to solve it what should be the value of k that I should choose?

@triple.e.sudhanshu 8 ай бұрын

@@Makarov-- Solve the numerator and denominator independently you will get the values of zeros and poles respectively without considering 'K'.

@tonystark9850 9 ай бұрын

What a clear explanation and Knowledge 👏👏 Subscribed!!!

@triple.e.sudhanshu 9 ай бұрын

thank you✨

@rajatpaul6067 2 ай бұрын

Thank you sir. You have explained this topic so well, My all confusions related to root luocus are cleared 😊

@triple.e.sudhanshu 2 ай бұрын

@@rajatpaul6067 😊

@dashgaming4254 7 ай бұрын

very well explained....

@MIXED_MOVIES 2 ай бұрын

Bahut hi badiya explaination tha shyad hi koi aapki tarah iss topic ko detail me clear karva payega Bahut badiya padhay sirji ❤❤❤

@triple.e.sudhanshu 2 ай бұрын

@@MIXED_MOVIES 😊

@tarak_80 7 ай бұрын

Thank you so much sir for this super beautiful lecture❤❤❤❤❤❤❤❤❤❤❤

@triple.e.sudhanshu 7 ай бұрын

❤️

@all.abt.shivangiii 7 ай бұрын

bhaiyaa you are a saver for me in exam time..😍🙌

@triple.e.sudhanshu 7 ай бұрын

@@all.abt.shivangiii That means a lot to me 😊

@bhatuyash9699 2 ай бұрын

Engineering kar rahi ho 😂

@nirajjj01 8 ай бұрын

Nice explanation sir.

@triple.e.sudhanshu 8 ай бұрын

Thank you! Niraj😊

@rishijoshi4792 8 ай бұрын

Bhaii aap yrr bhagwan se kamm nhi ho ....bhott bhott dhanyawad 😭😭

@triple.e.sudhanshu 8 ай бұрын

Shukriya bhai ❤️ such a kind words...lekin mai bhagwan nhi hu mujhe insan hi rehne do 😅🙏

@RajGupta-yx4yw 8 ай бұрын

sahi bat he rishi bhai

@rishijoshi4792 8 ай бұрын

@@RajGupta-yx4yw 😂😂hn bro

@NirajKumar-id7zw 21 күн бұрын

Aaj samaj me aaya root locus sir g

@fatimatulzahra1098 27 күн бұрын

Excellent 👍

@SahilVishwakarma-k3w 10 ай бұрын

Thank you sir ❤❤❤

@AUTHENTIC_VIEWS 7 ай бұрын

Sir S1 , S2 , S3 ke values kase liya pls bata dijiye 17:07

@anything-lr4fc 7 ай бұрын

s=1=0 karo to s=--1 aa jaega

@monishkumar5353 8 ай бұрын

bro you deserve so much followers, how come are you so underrated💔🙏🏻

@horjeet8704 4 ай бұрын

Thank u sir, ....One of the best professor 💥

@triple.e.sudhanshu 4 ай бұрын

@@horjeet8704 ❤️

@DamanS-vn8ov 5 ай бұрын

sir where is the video for root locus rules i am unable to find it

@triple.e.sudhanshu 5 ай бұрын

@@DamanS-vn8ov It has been deleted due to some issues, will be re uploaded.

@joydipmondal2763 Ай бұрын

Sir please re-upload it 🙏🙏@@triple.e.sudhanshu

@triple.e.sudhanshu Ай бұрын

@@joydipmondal2763 Why?

@joydipmondal2763 Ай бұрын

@@triple.e.sudhanshuMay be easy to Understand

@triple.e.sudhanshu Ай бұрын

@@joydipmondal2763 why are you requesting to re-upload? Is there any issue with this video?

@Bob_Celestine 8 ай бұрын

Sir baki ke videos nahi mil rahe like root locus property wala jo aap Chanel pe check karne ko bole?

@triple.e.sudhanshu 8 ай бұрын

Ha kuchh issue tha usme delete krna pda use...i will re-upload that video.

@vikashkumarmahanta3177 8 ай бұрын

Hnn jaldi kariye parso exam hei

@vikashkumarmahanta3177 8 ай бұрын

Rh wale ka bhi kuch kariye sir

@triple.e.sudhanshu 8 ай бұрын

whatsapp me i will teach uh for your exams....until i start uploading the contents

@mr.umerworld5402 6 ай бұрын

Sir ye break point apny direct kesy polynomial bna dia plz tell

@triple.e.sudhanshu 6 ай бұрын

@@mr.umerworld5402 Firstly, you have to find the characteristic equation and derive the function of 'K' subsequently differentiate the function with respect to "s" and then solve the polynomials. You will get multiple values of "s" then select the proper value according to the question as a break away point.

@kingfarooq6348 5 күн бұрын

Could you kindly urgently send me the link of your rules for Root locus vid as i have not found in your playlist

@abhishekmaurya5968 4 ай бұрын

Very nice explanation ❤

@triple.e.sudhanshu 4 ай бұрын

😊

@Sharma16230 7 ай бұрын

Very nice sir thank u 🎉

@mddanishalam5740 7 ай бұрын

Thnx bahut acha apne samjhaya

@noviceseries 8 ай бұрын

Perfect 😭😭😭😭❤️❤️❤️❤️❤️ mashallah 💖💖💖

@anyasharma7568 Ай бұрын

thanks bhaii, badhiya expanation haiii,

@nutcase7541 4 ай бұрын

Neso Academy ❌ Triple E Sudhanshu ✅

@triple.e.sudhanshu 4 ай бұрын

@@nutcase7541 Unexpected 😳🥹🥹🙏

@swaroopmishra9902 8 ай бұрын

20:31 pe thetha 2 straight kese hoga 270 degree hain na?

@triple.e.sudhanshu 8 ай бұрын

Measure 270 degree anticlockwise you will get the angle!

@mansimore1383 9 ай бұрын

Thankyou sir.. very well explained sir 👏

@sayalipawar5385 18 күн бұрын

Khup chan 👍🏽 explain kel aahe 😊....plz root locus che program code pn explain kra....

@triple.e.sudhanshu 18 күн бұрын

@@sayalipawar5385 ji

@anjaliaswalaswal8950 9 ай бұрын

Nice explanation

@cypherop7287 3 ай бұрын

what will be the stability of the system? how can we determine the stability? do we have to use RH array to find stability?

@triple.e.sudhanshu 3 ай бұрын

@@cypherop7287 In this case, the whole graph of root locus is depicted towards the LHS of s-plane, it's already a stable system. If the root locus crosses the imaginary axis and goes towards the RHS of the s-plane then system becomes unstable and to find the range of unstablity you need to apply RH criteria.

@laxmigadad1738 7 ай бұрын

crossover on imaginary axis is not calculated why please explain sir

@triple.e.sudhanshu 7 ай бұрын

The locus has the property that whatever shape it will take at an emanating point, same shall be followed up to the infinity. In this question, the locus is bent towards the left side of the s-plane in alignment with asymptotes so it will never cross the imaginary axis and it will follow the 90° upward up to infinity.

@arnavdeshpande4400 2 ай бұрын

Sir Can you add the link of root locus rules video in the description

@musicfromthemountains3021 7 ай бұрын

Bagar calculator ka s ka values kasy find kry kasy solve hoga

@triple.e.sudhanshu 7 ай бұрын

Sure! I will make a separate video for this.

@triple.e.sudhanshu 7 ай бұрын

Check the latest video! Maine is par video upload kr diya hai

@achiever2569 8 ай бұрын

sir how can you confirm the direction of arrow of locus originating from pole at -1 goes toward right side and locus starting from pole at zero goes toward left side, why cant it be the opposite plz clarify ?

@triple.e.sudhanshu 8 ай бұрын

Pay attention!! 1. As per the root locus property, locus exists on the real axis on the left side of individual pole/zero if the total number of poles & zeros are odd in s-plane on the right side of that individual pole/zero. 2. Further, the other property of RL is that all the locus emanates from poles and terminates at zeros. Now, as per your doubt in this question the locus exists between 0 & -1 that & both are poles which means locus will start from poles. Therefore locus will start from -1 towards the origin and other locus will start from origin towards the -1 subsequently they will collide at some particular point and that point is calculated as BREAK-AWAY POINT in order to understand the bifurcation of locus on the s-plane.

@Manzoorbaloch-s5q 3 ай бұрын

Good explanation

@triple.e.sudhanshu 3 ай бұрын

@@Manzoorbaloch-s5q Thank you!

@amazingfacts-uv4kf 3 ай бұрын

Where is 11 rules vedio Please provide link It will very helpful

@triple.e.sudhanshu 3 ай бұрын

@@amazingfacts-uv4kf Due to some reason the video was deleted it will be uploaded back asap

@nayeemmufti0 2 ай бұрын

Sir i have fx 82 calci how can i directly calculate those roots of 3rd order polynomial

@triple.e.sudhanshu 2 ай бұрын

Press the MODE then look for the EQN option in your calculator there must be an option to choose the order of equation.

@nirmalpathak9501 2 ай бұрын

Sir ap new video kyu nai banate ho

@triple.e.sudhanshu 2 ай бұрын

@@nirmalpathak9501 Actually thoda settle hone me time lag rha hai... kosis kr rha hu jaldi hi start karne ka fir sb cover krunga

@Indianreal96 7 ай бұрын

Sir , root locus ke rules wala video ni milra apka ... share it please in comment

@triple.e.sudhanshu 7 ай бұрын

Actually, I deleted that video due to some issue but soon I will upload again!

@SyedaHamdani-h9j 3 ай бұрын

@@triple.e.sudhanshukia abi apn video upload ki?

@triple.e.sudhanshu 3 ай бұрын

@@SyedaHamdani-h9j abhi ni give me some days

@kumarsonu9290 Ай бұрын

lots of love from NIT patna

@triple.e.sudhanshu Ай бұрын

@@kumarsonu9290 ☺

@mddanishalam5740 7 ай бұрын

Sir Bode plot ka lecture upload kijye

@triple.e.sudhanshu 7 ай бұрын

On 9th it will be uploaded.

@niveshkothari Ай бұрын

thank billy biuchwe

@devilmonster7030 7 күн бұрын

Matlab baki lecture ki bhi need hai please

@DamanS-vn8ov 5 ай бұрын

sir i am getting 2s^3+10s^2+16s+6

@DamanS-vn8ov 5 ай бұрын

should i divide by 2.....

@triple.e.sudhanshu 2 ай бұрын

Avoid using manual calculations, feed the data in calculator for instant results, as calculators are allowed in semester exams

@Ayyaz_Mohd 9 ай бұрын

Can you please make videos on Bode Plot( Linear Control Systems)?

@triple.e.sudhanshu 9 ай бұрын

I will cover each and everything...stay connected 😊

@vikashkumarmahanta3177 8 ай бұрын

Sir parso exam hei bode plot aur polar plot ka bhi thoda dijiye sir

@devilmonster7030 7 күн бұрын

Sir air video to banaye

@ayushgupta22 3 ай бұрын

GOAT🗿🗿

@triple.e.sudhanshu 3 ай бұрын

@@ayushgupta22 💚🙏

@gaurav__5653 Ай бұрын

sir properties wala video nhi mil rha hai

@triple.e.sudhanshu Ай бұрын

It was deleted due to quality issues, will be uploaded back

@gaurav__5653 Ай бұрын

@triple.e.sudhanshu Sir actually mera kal exm hai islye sir need thi us video ki .Btw Sir outstanding teaching style hai apka🙏🏻❤️

@triple.e.sudhanshu Ай бұрын

That means a lot to me ❤ #whatsapp me, i will send you a pdf of 2pages you can go through that

@gaurav__5653 Ай бұрын

@@triple.e.sudhanshu Ok sir

@gaurav__5653 Ай бұрын

@@triple.e.sudhanshu Its showing the link is not valid

@MadniRaza-w8e 2 ай бұрын

Explanation was good but bit confusing too because of short cuts while explaining about break-away points

@triple.e.sudhanshu 2 ай бұрын

@@MadniRaza-w8e To really hit the mark, it's crucial to streamline the content and avoid overly complex calculations, like multiplication or division. Also, considering student's attention spans, I'll keep the video concise and engaging.