Root Mean Square (RMS) Calculation Based On Fourier Series Expansion Terms

[@janwrobel9734]

06:08 "... not that bad", proceeds to draw hell of a long square root XD

[@nurahmedomar]

I'm confused about the RMS current expression. The coefficient of each harmonic shouldn't be 1/sqrt(2) instead of sqrt(2)?

[@AJ-et3vf]

Phenomenal. Thank you!

[@PardeepSingh-wj8lc]

Nice mam