RSA Algorithm

RSA (Rivest-Shamir-Adleman) is an algorithm used to encrypt and decrypt messages. It is an asymmetric cryptographic algorithm.

[@sudhakar_yt]

Great explanation ❌ Great documentation ✅

[@editing_spotu]

Tomorrow my semester exam... Now only I'm studying this RSA😂.... It's clearly undershirt mam🙏🏻💥... Thank u so much❤️... Keep uploading more videos💥🔥

[@rashmib3794]

What r u studying

[@brienaustinclayton]

Situation right now😂

[@hemachandra6177]

Hype moment 😂

[@ayushraj8234]

Same same

[@Maha282k3]

Understand ah bro

[@badal8435]

Its an simplest explaination of rsa , i found on youtube, thank you mam

[@simoherman4454]

My first time learning RSA and it's clearly understood.Thanks very much 😊

[@chiruvellabalakarthikeyan6203]

Thanku for helping me by explaining rsa algorithm on KZbin madam. U r the supply sem exam saver madam.

[@botplayer1434]

Very good explanation...explained the whole topic in short time and simple way to understand amazing video

[@paraggawade9045]

Simple n easy explanation

[@ox3965]

wow wow, This is what I am talking about Great video, clear and precise and straight to the point. . Thank you

[@nishendu246]

Great Explanation

[@Imisambi]

Handwriting is Excellent like Art

[@yashaspa1260]

It's a very easisest way of explanation Mam, Thanks allot.

[@jenithasharu4257]

How did yu take d=3 out of nowhere? Isn't that what we need to find? And to find out the value yu consider 3 randomly?(someone explain if yu know)

[@harshbhobe2543]

We have to find the value of d such that d x e mod Φ(n) = 1. So put value of d such that it satisfies that condition. Watch the 5th step of key generation.

[@YijinYang]

A very good video with clear notes!!! Highly recommend!

[@mkson1]

3 hrs before exam, what's wrong with me😂

[@apeximperator]

your existence

[@noobmaster5066]

13 min before exam

[@anactor530]

2 minutes before quiz

[@43_ayonroy4]

​@@anactor530how did it go ?

[@eswarboss]

surely out of all, your's the simplest and easy way to understand. Use less duration so that it reaches all. Tq.

[@patelsmit57]

Love the simplicity !!

[@mubashar-nouman]

Very Nice Explaination

[@taotechsolutions]

Thank you very much 😊

[@adityamali1862]

Really simple and consise explanation! Thanks a lot mam !

[@Lioneltaklai]

Explain why you choose d=3 directly to solve (d.e)%Q(n)=1?

[@Khallnayakk]

So that 9 mod 8 equals 1 ... If d=3*3 which is 9

[@EstherIdang7]

Well explained Easily understandable Please make more videos on cryptographic algorithms, DES, SHA-256

[@virajgajdhar805]

Thank you maam i understand this concept now. If RSA algo asked in tommorow exam i will surely achieve full marks in that question.

[@erichalale6249]

if it was possible for to give a million likes i would have multiplied that by another nillion good explanation

[@sheikhraisulislam4483]

why did you take same public and private key ... ruined 😢

[@sankeerthsharma7542]

what is the case when we consider e=5 and e=7 how do you calucltae d then as d*e mod(8)=1 if you consider e=5 or 7 which satidfies the condition e is greate r than 1 and e

[@69bro._69]

Even they don't know they are simply repeating the words written on the book and nothing else don't know how come others understood this shit

[@mohamedrukais6919]

Well explained , thank you madam

[@RohitKumarLEECE]

Wow , i understand the concept of mod after various video ,easiest explanation

[@parthumylavaram7286]

Clear explanation, Thank you.

[@nkansahedward6584]

Fantastic explaination!

[@g.soujanya6704]

excellent explanation. ...

[@suprajaganne1567]

video is very informative. As it is RSA(asymmetric), can public and private key be the same? or should we consider 19 as private key when public key is 3

[@vandanakota3257]

Super explanation 👍

[@booky6149]

Thank you so much mam. It is very helpful and easy to understand!

[@solikurbonboyev2330]

THANK YOU VERY MUCH MISS

[@yogeshgawali7542]

Great Explanation Thank You!

[@buddhikachathuranga2968]

Super explanation ❤

[@CM-A--PriyankaBonde]

i like the way you represent 😊😊

[@wandelrand1283]

Awesome explanation,i find for this topic 🔥🔥

[@NareshKumar-kq5yz]

How did d-3 came??

[@Shehryar_Raja]

Mam I salute you because you explained this so well and tomorrow is my exam I am happy to learn from you. Thank you so much ❤❤❤❤❤

[@amankumar0351]

thanks a lot mam ...you helped me out in understanding the concept in a easy way

[@spicegirl1]

Thanks a lot ❤

[@mohammadamanalimyzada1462]

great job heartfelt thanks

[@StupidIdea489]

Nice explanation

[@rjfloat767]

Well explained.

[@didierfogha7414]

i have a question why do you choosed il value of d=3

[@skshaheena8565]

Thank you mam

[@user-sn8kp8ut6z]

Thanks alot, very well explained

[@sykelyte]

what a huge nose. ew

[@DinavahiRahul]

how come you could write directly 8 as the plain text while encryption?

[@apeximperator]

arey bro woh RSA mein na kuch hota hai

[@farzeenrasheed538]

Great 👍🏻

[@user-me1ry6lg6d]

when i try to encrypt P = 6 ,or P=5 , the algorithm does not work, what is the problem ?

[@user-ye7yu2zc4t]

Thank you maam

[@I-vk3tx]

Thank you!

[@ephrembedhaso7741]

how do you take the value of d for others ,like large numbers?

[@doukansurel]

What is mean Algoridem?

[@abul-karimcholo3010]

Thanks Madam 🤝

[@motabeenay1133]

Step 4 is little hard to understand

[@balawalrasool8703]

AWESOME

[@anonymous_squirl]

mam to to choty level py prhaay hy hmara to plain text 85 hy or pq ki value to 13,17 hy mod ni a ra

[@killwakonan]

thank youuuuuuu

[@edwinwanjira]

Thank you

[@tienatspyciovu5631]

nice video, thx u so much

[@nishanisha3481]

Vera level ✌️spr mam✨️tq u....

[@rohithvarshan7028]

Thank a lot Mam♥

[@ronishghimire8368]

Mam is it possible to take e and d value as a same number

[@revanthnmallol9842]

yes u can, solve p=3 q=5 e=3 M=4

[@sanakareemsano6716]

P ki value 8 kha sa aye hn

[@zxynb]

can we consider e's value as 13?

[@ssheikh_]

Thankk you !

[@eyayaebabu4927]

GOOD EXPLAIN

[@FomeKevin]

thank u so much maam

[@salambience12]

step 4, 5 no explanation why we take those values ...

[@kangqinyip2742]

Mdm I dont understand step 4 very well I have a question I have no idea how to solve now in step 4

[@ashiqurrahman1727]

Thanks ma'am

[@Keneel]

Mam I had a question if RSA is asymmetric key algorithm then why we here took same key for both doesn’t it make it symmetric key ?

[@05-cs-adarshgautam16]

yes i also have same doubt

[@samuelmayna]

No. {e,n} are public to everyone and anyone can use then to hash a message intended for the owner who has public key {e,n} but private key {d,n}. Anyone can create a cipher text with {e,n} key but only {d,n} key can be used to decrypt a message .Hope it makes sense. In the example the message could have been sent by anyone who has public key {e,n} but only the recipient with the private key {d,n} can decrypt the sent cipher text.

[@ravindrareddy8085]

Why we consider p=8 ?

[@devikaranib.5897]

It will be given in question itself....the value of plain text

[@vrushabgaikwad5254]

15 mod 8 = 7

[@fouziyat6445]

15 mod 8=7 . But Here comes no need for doing this operation in any steps. Here we only need to do 8 mod 15 and it is 8

[@hostd]

tanks maam ...😊

[@rahulchavali4472]

Why take d= 3 ??

[@kangqinyip2742]

Can someone explain on step 4 I seriously lost on there

[@MdFaruk-wg2hr]

You sound like Deepika padukone ❤

[@ItsDivyanshiforyou]

e and d cannot be same

[@Harshu30mki]

welcome

[@everything_u_need1072]

M-am also mention how to do gcd for selecting e

[@luckyeslavath110]

Mam encryption the message: hello world

[@shreyashshelke2343]

🔥🔥

[@aishu4980]

Tanqqqq so nuch akkaa❤❤❤

[@apeximperator]

thank you so much*

[@syeddaniyal1273]

How can the public and private key can be same? E=3 , d=3 as well? Logically this is useless considering your private and public key same

[@aestheticart4955]

❤❤❤❤❤

[@loisowusu377]

But e and d cannot be the same

[@koikoilpigon6900]

queen

[@eswarvamsi8612]

Tnq

[@youtubexaimgod3970]

Jai baba ki ❤️

[@mathsgettingeasyfouadrabhi5006]

🙏🙏🙏🙏

[@shreyas_._]

Thank God not in hindi

[@Varun-fs9ft]

Everyone have exams tmr so came today😂😂😂😂

[@raviranjanrajeev]

[@user-fb9rr4xb3y]

its cool keep it up !! thank you may be can you post your email