استاذ أكو خطآ مشتقة _x^2/2 موجودة _x ف النصف ما ينكتب
@abdulhusseinalsultani92222 жыл бұрын
Hello sir Please I put a new D.E instead of Bernoulli D.E dy/dx +P(x)y/n =Q(x)y^k where k=1_n (Alsultani D.E) For the example dy/dx +xy= xy^2 Solution k=2=1_n so n=_1 Multipy by (_1) _dy/dx _xy= _xy^2 I.f.=e^int.(_x)dx = e^(_x^2/2) y^_1e(_x^2/2)=int.(_xe^_x^2/2)DC y^_1e^_x^2/2=e^_x^2/2 +c Five steps without using the complex substitution Thank you very much