We need a double thumbs up button. Great channel 👍👍
@sambenyaakov Жыл бұрын
😊👍🙏
@surendrarama2095Ай бұрын
Namaste Sam Ben Yakov Sir. Great explanation on ferrite beads. Greetings from India.
@sambenyaakovАй бұрын
👍🙂🙏
@QoraxAudio4 жыл бұрын
This is the best video about ferrite beads on KZbin I've seen so far. In most videos, the inductive characteristics are not mentioned or dismissed as insignificant.
@sambenyaakov4 жыл бұрын
Thanks for comment.
@ats891176 жыл бұрын
Excellent video. Ferrite beads are definitely more of an art than a science at this point. The scariest part is that not only does each manufacture have its own secret mixes for making their different ceramic types, but the ceramic is made in batches, and their isn't any real assurance on how closely the batches will match up in terms of the performance characteristics we are interested in. So even if you experiment and find something that works really well, it might not work as well over a period of time in production...
@sambenyaakov6 жыл бұрын
Well said.If not a member please join www.linkedin.com/groups/13606756/ .
@eddprst6 жыл бұрын
request sent.
@gsuberland Жыл бұрын
Am I right in saying that the reason for the example on the right at 19:55 being optimal is that the fundamental frequency of the falling edge is 5MHz, which matches the cross point on the ferrite bead's ZRX graph? (I estimated 5MHz from the fall time on the left graph appearing to be approximately 100ns, and a sine wave with a 100ns period between its peaks would have a total period of 200ns, i.e. 5MHz)
@sambenyaakov Жыл бұрын
It is optimal in that it is more a resistive than inductive at a lower frequency. Ideally we would like to get rid of XL
@ezbody28 күн бұрын
I miss the times when people were saying "jigahertz" instead of "gigahertz", when everything was new, mysterious and exciting. 🙂
@sambenyaakov27 күн бұрын
😊
@TalRegev-p2j Жыл бұрын
Hi Prof. Sam, I'd like to thank you for an insightful video. A few questions which popped while watching - 1. since Rac is basically core losses shouldn't we perceive the added Rac in parallel to the inductance part? I've saw that you disputed the "simple model" by TDK for example. 2. In Clamp bead, I've wondered if the MFR's are taking into account any misalignment in the clamp which might cause an air gap. Does the design takes into consideration that the magnetic path is solid or gapped? - I assume it's the former (just checking). If possible at all - can you help by sharing relevant publications
@sambenyaakov Жыл бұрын
1. It is not that I am against the lumped equivalent circuits,.They are good for emulating the impedance but, as I have pointed out, I think that the loose the phase information which in most cases is not that important. 2. The clamped bead are assumed to be with practically no gap,. The gap between the bead and wire does not matter (Ampere Law)
@leonardosoliszamora10613 жыл бұрын
Thanks for this video professor. Best regards from Chile 🇨🇱
@sambenyaakov3 жыл бұрын
Thanks and greeting from Israel. Never been to Chile. The closest I got is Brazil.
@deviantmultimedia9497 Жыл бұрын
The thing I don't understand is, isn't inductive reactance essentially frequency dependent resistance? Or is that precisely what you are saying? That the reactance is welcomed and the DC element of inductance is the parasitic part... in this application
@sambenyaakov Жыл бұрын
The bead has real power loss which increases with frequency. This can be modeled as a frequency dependent resistor. Reactance does not dissipate real power.
@deviantmultimedia9497 Жыл бұрын
@@sambenyaakov Thank you for the explanation. I was not aware of that distinction. I am studying alone, no schooling. Your response was helpful and much appreciated.
@geirha752 күн бұрын
Excellent lecture!
@sambenyaakovКүн бұрын
Many thanks!
@danielf81406 жыл бұрын
Thank you for this and for your other videos professor.
@sambenyaakov6 жыл бұрын
Thanks 😊. If not a member please join www.linkedin.com/groups/13606756/ .
@scollyer.tuition2 жыл бұрын
This is by far the best explanation of ferrite bead principles that I've been able to find. It seems to be incredibly difficult to get a good theoretical overview of how these things work. I'm beginning to suspect that about 95% of people who put up information on this topic really don't have a good grasp of the topic themselves. Thank you. You've clarified the matter hugely. Do you have any videos that cover higher power ferrite bead applications, for motors and the like? I suspect that is another specialism on its own. [BTW, your two minute overview of noise induced by ground loops would have made the video worth watching on its own. That was a model of clarity]
@sambenyaakov2 жыл бұрын
Thanks. No no such videos. AS far as I know ferrite beads have not been used in motor control.
@scollyer.tuition2 жыл бұрын
@@sambenyaakov I was thinking about high power applications, such as the guy demonstrated (practically, at least) in this video: kzbin.info/www/bejne/envJmoKnlsp5esk
@sambenyaakov2 жыл бұрын
@@scollyer.tuition This video if full of errors, too many to count. To the point: he is showing the use of ferrite toroids. These are not the ferrite beads I am talking about i my video. The true ferrite beads include a substantial lossy part. The ferrite toroids used in thr video you referenced are a poor boy substitute common mode chokes. The problem of using FB in high power applications is that they saturate.
@technomaxcorporation10224 жыл бұрын
Excellent explanation... I am curious about that one dislike....He would possibly be searching for a necklace of beads....!
@sambenyaakov4 жыл бұрын
Yes, I think there is that one guy (i do not know who he is ) that waits until I publish a video and quickly, within a couple of hours or so, clicks the dislike.Go figure.
@Yorumcu633 жыл бұрын
Amazing video.Thank you proffesor.You had tell very simple this subject .Because you knowlodge very high. What had say Einstein: "If you can't explain it simply, you don't understand it well enough
@sambenyaakov3 жыл бұрын
😊🙏
@jamalhamdan53082 жыл бұрын
Hi Dr. Sam, Ideally, we would want a ferrite bead that doesn't have an inductance component. Just the resistance at high frequency. Correct? If yes, does that mean we should choose the lowest inductance over frequency ferrite bead every time?
@sambenyaakov2 жыл бұрын
Yes, but a low inductance bead will also have a low resistance. Try to get a bead with the highest R/L at the relevant frequency range.
@cuchulainkailen4 жыл бұрын
8:40 Earlier comment asked about your phase-accurate models. You said it would be public-domain. Can you provide any update???? I have an immediate need. At least, some pointers on your approach & methods (pspice or whatever). THANKS !!
@sambenyaakov4 жыл бұрын
Hi, I plan to prepare a video on that when time available😊. It short, one can use ELAPLACE behavioral model to create a non linear frequency dependent resistor and then add it to a non linear inductor
@lollannonaka50672 жыл бұрын
Hi Sam. The video is very nice. Congratulations. I have a question about the use of ferrite beads on both ends of the cable and when it is applicable. Sometimes people use this approach to minimize EMI effects on RF systems in the proximity of the cable (I think so)...
@sambenyaakov2 жыл бұрын
Ferrite beads on a cable act like a common mode filter
@billimew74962 жыл бұрын
Can you share the ferrite bead you have designed using equation at @26:25 which mimics the R,X and Z of the ferrite bead?
@sambenyaakov2 жыл бұрын
Sorry, I have no record.
@UnbornWarrior1233 жыл бұрын
Dear Dr.Sam, I really appreciate your efforts in making such an elobarate educational videos on current edge technology to help the upcoming students. However, I am completely confused and surprised to see a ferrite bead in the path of a gate driver on slide 3, 1:36, according to Transform company. It is highly desirable to keep length of gate tracks shorter and wider to maintain as minimum inductance as possible in the gate driver path. Higher inductance in gate path offers higher impedance to high frequency gate signal. Using same reason, how can we endorse a ferrite bead in gate driver path, which is also an inductor basically. (Its frequency response also proves it).
@sambenyaakov3 жыл бұрын
Thanks. You have a good point. I am not sure myself aout FB in gate driver. I tried it and did not se any benefit. But: THe FB might perhaps be useful cases of potential oscillations at very high frequencies 100's of MHz at which the bead is resistive while the added impedance at lower frequencies can be tolerated. i.e. wL/R is smaller than 1 .
@barronisme4 жыл бұрын
Thank you for posting such an good informative video. Does this mean that when IC manufactures recommend to put ferrites chips on nets powering the high- speed serdes (to get a clean power), they are actually degrading the serdes performance because the ferrite chip power filter hinders the serdes circuits to draw power rapidly?
@sambenyaakov4 жыл бұрын
Not if the bead are selected wisely
@raviteza85 жыл бұрын
Manufacturers like Transphorm and USci suggest to use a ferrite bead in the gate drive, but your lecture makes its very clear that its not so easy to fight the spikes and in fact may worsen it! Thank you very much for the Lecture Dr. Ben-Yaakov.
@sambenyaakov5 жыл бұрын
Good points. Thanks.
@cuchulainkailen4 жыл бұрын
16:34 to 17:00 ... You state the crossover R/X is the key factor. Why? Because lower freq of crossover is better, for higher freq of interest, so L resonance w/ parasitic C is pushed to higher freq. where R is higher (lower Q)? If so, it seems that would make the lower crossover freq a bad choice for filtering dc/dc converter ripple (lower freq).
@sambenyaakov4 жыл бұрын
Ferrite beads are not meant to replace filter inductors. They are meant to add damping (lower the Q). So if the inductive part dominates it is defeating its purpose.
@cuchulainkailen4 жыл бұрын
@@sambenyaakov I'll take that as either a "yes" or "you emitted an unclear question". Either way, your answer suffices. Thanks. :-))
@manojkumarsubramaniam71224 жыл бұрын
Thanks. It was very informative for even field designer.
@sambenyaakov4 жыл бұрын
Thanks
@thezodiace73993 жыл бұрын
Excellent video Professor Sam.
@sambenyaakov3 жыл бұрын
Many thanks!
@PSPS4376 жыл бұрын
Great lecture Dr. Sam
@sambenyaakov6 жыл бұрын
Thanks. How have you been?
@PSPS4376 жыл бұрын
Doing good Dr. Sam. Hope you are doing good as well.
@hamidk47726 жыл бұрын
Beautiful
@sambenyaakov6 жыл бұрын
Thanks 😊. If not a member please join www.linkedin.com/groups/13606756/ .
@EigenA3 жыл бұрын
Great job, thank you!
@sambenyaakov3 жыл бұрын
Thank you too!
@seinfan95 жыл бұрын
How do you account for linear regulators that require low ESR capacitors at their inputs? I found a paper from Linear Technology that details using ferrite beads at both the input and output reduces switching noise, but this renders useless the use of any damping resistors to limit high frequency spikes from the ferrite beads.
@sambenyaakov5 жыл бұрын
Ferrite beads are not the ultimate fixer, but could be very useful if used wisely.
@ruixiong52374 жыл бұрын
Great Explanation.
@sambenyaakov4 жыл бұрын
Thanks
@shashankgaonkar25464 жыл бұрын
Excellent tutorial
@sambenyaakov4 жыл бұрын
Thanks
@borsanflorin1036 жыл бұрын
Thank you very much.!
@sambenyaakov6 жыл бұрын
Thanks 😊. If not a member please join www.linkedin.com/groups/13606756/ .
@levnemets21486 жыл бұрын
Very useful information. In example 4 you say that you use a model, which you developed. Could you, please, explain which model you use for simulation in time domain and how the parameters for this model can be obtained from datasheet graphs Thanks
@sambenyaakov6 жыл бұрын
Hi Lev, Thanks for the comment. You have a keen eye. The simulation models are still in the making. Once published, I will make it public domain. Hold on😊
@ronvaiz1234 жыл бұрын
Thanks for the video, could you make a video about CM or DM chokes?
@sambenyaakov4 жыл бұрын
Will try.
@amirb7156 жыл бұрын
Excellent video as always :-) I have one question: Are all of these impedance charts for ferrite beads given for one wire going through the bead? What if I put several loops through the toroid?
@amirb7156 жыл бұрын
...I meant what happens to the resistive part. The inductance will roughly (not exactly because it is nonlinear) increase as n^2 but the resistive part I think should behave differently. also where will the resonance (peak) move to when I have several turns?
@sambenyaakov6 жыл бұрын
Manufacturers show measurement of Z for a number of terms and the impedance behaves as n^2 so both the inductive and resistive parts increase.