There is a lack of examples on web about sampling. It is very informative, thank you.
@iain_explains Жыл бұрын
Great. I'm glad it helped.
@Pulsonar18 күн бұрын
Very informative, I like the way you dive into the mathematics of it all as if its just tea and biscuits ;) As soon as maths notation comes into view Im done for. Im just thankful as an engineer I often figure problems and solutions from a practical perspective to 'cheat sheet' my way around the maths for most part, and my intuitive solution matches the final maths result. Good work.
@2002yeunglau Жыл бұрын
Your Intuitive+mathematic explanation is so good.
@iain_explains Жыл бұрын
I’m glad you like it.
@tjcogger1974Ай бұрын
Very good video! How would you go about taking the inverse Fourier Transform of Y(jw) in part C?
@iain_explains29 күн бұрын
I'm not sure what you mean, sorry. It would just be a case of applying the definition of the inverse FT. Perhaps you are asking what the time domain waveform would actually look like? That's a good question. It would be a distorted version of a squared sinc function. It's a bit hard to explain in words, but it's a good topic for a future video.
@alparslan48713 жыл бұрын
Please solve more examples about signals and systems
@iain_explains3 жыл бұрын
Thanks for the suggestion. Do you have any particular topics in mind?
@alparslan48713 жыл бұрын
@@iain_explains LTI sytems as filters would be very helpful
@iain_explains3 жыл бұрын
OK, I've added that topic to my list. Thanks.
@HaSongSon1232 жыл бұрын
Hello Prof, why do we need to multiply with the factor 1/2pi in the frequency domain? In other books, i see that sometime this factor appears sometime not.
@iain_explains2 жыл бұрын
When the Fourier transform is written/plotted in terms of angular frequency (omega) then the 2pi will appear, since omega = 2pi f .
@KisoreMuthiahAnnamalai4 күн бұрын
@@iain_explains But Sir why is this 2pi multiplied? What is the significance of doing so?
@sandhiyasahanapandiansamue1729 Жыл бұрын
Thank you so much Sir
@iain_explains Жыл бұрын
You're welcome. Glad it was helpful.
@mehdiamraoui84884 жыл бұрын
i didnt understand why we get the constant at the end ..i mean the constant value .. can u plz explain ? thank u
@iain_explains4 жыл бұрын
The final function is the summation of each of the component (offset) triangles (since the sampling function is a summation of offset delta functions). This means that at each frequency value (omega) you need to add the values of the component triangles that overlap with that frequency value (ie. that are non-zero for that frequency). Since the triangles have straight sides, the decreasing slope of one triangle is exactly matched by the increasing slope of the other overlapping triangle, so that the summation doesn't change for the range of frequencies where they overlap (and hence is results in a horizontal line , or a constant value, for that range of frequencies). Hope this helps.