Came for the physics, stayed for the planet coaster content
@nanakwameomari32087 жыл бұрын
wow the explosion really caught me off guard and had me laughing. good vid tho
@wanstudent45025 жыл бұрын
Nearly wet myself in the library with me headphones in!
@marcusjenkins75195 жыл бұрын
"So that's where the GCSE ends pretty much"
@muhammadamrullah21474 жыл бұрын
This is probably my 3rd time watching this video and it still catches me off guard xD
@mk007__5 жыл бұрын
@ 6 mins: so that's where the GCSE ends, let's now look at A level stuff A level stuff: 13 mins why do I have to suffer so much
@aadhishshah41864 жыл бұрын
Muhaimen Khan little red daleks are cute
@mk007__3 жыл бұрын
@@aadhishshah4186 the TARDIS is blue tho
@themotosport_detective7 жыл бұрын
im currently doing physics in the irish version of your A Levels and we have the same topics as you and i just learned what my teacher thought us in 4 weeks in 19 minutes. Thank you so much :)
@kidslovef11552 жыл бұрын
How do you feel now that Kimi retired?
@bilaltaj17252 ай бұрын
@@kidslovef1155 kimi raikonnen?
@kidslovef11552 ай бұрын
@@bilaltaj1725 yes
@bilaltaj17252 ай бұрын
@@kidslovef1155 lol
@iwanttocomplain2 жыл бұрын
“The friction between the tyres and the road... is acting towards the center of the roundabout, at all times.” Makes perfect sense. Anything moving in a circle, is circular motion!
@annsmahboob34954 жыл бұрын
I had been flying with uniform circular motion until the vertical circle came into play, I was about to give up understanding it but this cleared my doubts. You just earned a subscriber.
@chrishodges12606 жыл бұрын
1:28 Nice one bro! You Pulled.
@garydickson4 жыл бұрын
I'm sorry, but I don't get it?
@garydickson4 жыл бұрын
@Christopher Hodges ohhhh 😂 thanks for explaining
@YesIlikebananasSo3 жыл бұрын
@Christopher Hodges to be fair I don’t think pull is strictly British slang but you probably don’t care 😂
@javedfaizal5473 Жыл бұрын
the GOAT of A Level Physics, ladies and gentlemen
@miaip34464 жыл бұрын
Thanks, this was really clear and useful, I liked the variety of examples and funny animated explosions are always welcome ahaha
@sameerrahman37673 жыл бұрын
3 years later and still helping me out. Appreciate it!
@Haris13 жыл бұрын
how
@haroonqadir34742 жыл бұрын
@@Haris1 this guy has got me wondering man.
@Haris12 жыл бұрын
@@haroonqadir3474 what has he got you wondering
@haroonqadir34742 жыл бұрын
@@Haris1 how he ever wants to come back to this after the exam. I do realise it could maybe be a levels now. Pray for me have my gcse in a couple days
@Haris12 жыл бұрын
@@haroonqadir3474 I don't pray
@kuchbatein69252 жыл бұрын
my AS in physics is finished and I'm quite happy with my marks its 80ish but I think some improvement needed but this channel is the only reason I survived my As and it's making me understand A level quite much now so just wanna say so much thank you for these videos as these helps a lot:)
@user-ji8br3dl9s2 жыл бұрын
Kuch Batein
@ProEpicGuya76c0075 жыл бұрын
7:50 ... turn on the subtitles and read it Thanks to me for making u laugh 😂
@user-hq6sp5 жыл бұрын
For anyone who cant be bothered to go to 7:50 he basically says "you are going to be using this equation a lot especially probably the second year of your ANAL"
@hackerpro67425 жыл бұрын
@@user-hq6sp no one cares
@ailtommoto12264 жыл бұрын
@@hackerpro6742 I care
@ritesha80503 жыл бұрын
😂😂😂😂😂😂
@blindshot9993 жыл бұрын
lol lol lol
@fibonacci3138 Жыл бұрын
you might just be the feynman of a level science... thank you so much!
@sharibjan54066 жыл бұрын
Thank you really helpful video. An example or two with numbers would make even better.
@abbsterjonesy5 жыл бұрын
good luck to anyone watching this with the exam today!
@crazyawesomegirl905 жыл бұрын
good luck to you too!
@kimobasha17063 жыл бұрын
the voice of u writing from ur marker really gives me goose bumps..
@jackr15536 жыл бұрын
Still safer than the smiler.
@joetspare26323 жыл бұрын
🤣🤣
@shikiagi62265 жыл бұрын
1 day until exam and im here, rip
@Aixzyl5 жыл бұрын
same g good luck :P
@shikiagi62265 жыл бұрын
@@Aixzyl u2 bro
@tompowell81905 жыл бұрын
big last day
@JohnDiggle215 жыл бұрын
Same here, hopefully the grade boundaries are low
@shikiagi62265 жыл бұрын
@@JohnDiggle21 yeah
@inthebackwiththerabbish6 жыл бұрын
5:56 tho 😂
@arnavsharma50692 жыл бұрын
this guy deserves a million views
@carolines22326 жыл бұрын
I have a test on this tomorrow and this saved me, THANK YOU SO MUCH!!!
@greasyboii54765 жыл бұрын
How did you do
@1_aaaa_16 ай бұрын
Please clarify 15:55 please. Because to my knowledge, the theta should be betn F and mg and which results in root rgtantheta however what you did also makes sense, so im confused
@ScienceShorts5 ай бұрын
See updated video, explained better
@goldybindra87853 жыл бұрын
I had a question at 18:25 when the car is at the top of the vertical circle, I think the support force should act upwards rather than down if it is in the circle as it needs reaction upwards from the track otherwise the car would just fall and support force will contribute to it. can somebody pls reply quickly as i have an exam tomorrow, thanks
@olliehubbard15353 жыл бұрын
I believe the support force is just the reactive force of the structure onto the car so will act towards the centre due to the track being round
@fatimahislam7925 жыл бұрын
This was very helpful. Thank you sir.
@nigeltnt4 жыл бұрын
this is some great work here. Thank you. It is quite clear and comprehensive
@nomadactual24842 жыл бұрын
i like how he used rollercoaster tycoon 3 to explain physics
@salehakhan24395 жыл бұрын
The video is superb, but can you please explain the example you showed at 17:30 when the car is at the right hand side, the resultant force does not comprise of weight acting downwards??
@mahnooromer87415 жыл бұрын
Really helpful for my test Tom Thankyou🙏
@samgurnett47087 жыл бұрын
5:18 Can you please explain why the seats of the chair swing are being flung outwards if there is no such thing as centrifugal force? Really confused about this
@joestinton78386 жыл бұрын
So imagine the diagram of the circle and how the line for the velocity is in a straight line. Due to this line being straight there is a small component of the velocity acting pushing the chair away from its circular path hence why the chair swings are being flung outward.
@hamedquraishi207 жыл бұрын
your vids are amazing!
@nandoboiii52157 ай бұрын
Quite a random question but what A Levels did you study at school and what did you study at uni?
@dronemonkey20383 жыл бұрын
Excellent tutorial
@finnreilly-mcqueen5435 жыл бұрын
Brilliant, thank you
@sea52055 жыл бұрын
Thanks so much!
@maximilianvonstern63652 жыл бұрын
thank you so much for this video
@yousufahmed9854 жыл бұрын
Love it man ❤❤❤
@internationalballerofficial3 жыл бұрын
5:33 lol :-). Bro caught me off gaurd.
@AEpicNinjaPie7 жыл бұрын
Is tension centripetal force, or is tension part of the centripetal force equation? For instance, mv^/r = T - mg for a string at the bottom of a circular path.
@ScienceShorts7 жыл бұрын
It's exactly the same as the support force of the track in the last example. For the bottom of a vertically circular path, the tension is solely responsible for the centripetal force, but also has to balance the weight, so T=mg+mv^2/r
@danyaalghafoor153 жыл бұрын
So much to remember anyone have any algorithms to remember them by
@armanhossain8474 жыл бұрын
Thank you lad
@uatty16 жыл бұрын
thou hast saved my soul
@abhijit_45594 жыл бұрын
you are the best
@mkpablie15164 жыл бұрын
Good explanation
@meharpalbasi48017 жыл бұрын
Do you need to know about Banking/Loop-de-loop for the AQA specification?
@I3uzzzzzz7 жыл бұрын
dont forget the 2 graphs for the practical 2moro
@spag52967 жыл бұрын
Meharpal Basi I'm pretty sure you do. Its in the main text book
@ScienceShorts7 жыл бұрын
Yes.
@eliakimalem53563 жыл бұрын
That was really helpful
@unbearable57195 жыл бұрын
Thank you!
@mdsayed61343 жыл бұрын
Love you man .....
@gooddeedsleadto74994 жыл бұрын
direction of resultant velocity would continually change toward the center? But magnitude of the resultant would never change? This means the acceleration would not change & point toward the center? because the velocity is continuously changing the direction & the direction of the resultant velocity remains toward the center, & the rate called centripetal acceleration? Is acceleration defined number of directional changes per unit time in this case?
@MrPiinQu7 жыл бұрын
how come at 15:34 you have divided by sin and cos, when Force is usually = cos x Theta not divided?
@ScienceShorts7 жыл бұрын
Because we know that the force responsible for circular motion must be greater than the centripetal force. For example, if centripetal force = 5N, it is impossible for say 3N of upthrust to provide this, which is what multiplying by cos or sin would get you.
@izarhossain86904 жыл бұрын
ur vid is helping like a charm sir thank you
@xUltraShadow3 жыл бұрын
Amazing content! Please keep making these videos they help us so much!
@mariamhussein71624 жыл бұрын
Thank you
@serkansimsek36446 жыл бұрын
Great content thanks
@Axashx4 жыл бұрын
I GOT SCARED. YOU KNOW WHAT I'M TALKING ABOUT T_T
@WritersDigest-b8f Жыл бұрын
BTW: I visited a sugar factory many years ago and I saw centrifuges turning very fast & centrifuging out crystals, separating the crystals? Also, I believe one would stick to wall inside a rotating wall? What force is that, is it not centrifugal force? Please explain, thank u
@ScienceShorts Жыл бұрын
Not a force pushing you out, just your body wanting to carry on going straight but the centripetal force pushing you inward.
@nahidalifazel90035 жыл бұрын
thats a greaaaaaaat video ('thumbs up')
@imogen91375 жыл бұрын
Thank you very much kind sir
@messaroundaccount11935 жыл бұрын
Sir Could you please just shed a bit more light on the Aeroplane example please? Much appreciated sir!
@moodymonstrosity14234 жыл бұрын
Yeah the upthrust force(F) is kinda confusing like what is it for when mg is there already?
@namename31302 жыл бұрын
A planes wing doesnt just generate lift in an upwards sense, it creates a force that is always perpendicular to it. In level flight all the force generated by the wing is matching the gravity - mg. But when the plane banks (rolls) the force generated by the wings changes direction accordingly. Also the wings lift changes depending on the application of the ailerons (up + down flight controlls). When the plane is banked the pilot will use the ailerons to increase the lift of the wing allowing for only the vertical component of lift to counter mg and the horizontal to provide the centripetal force. If the pilot didnt use the ailerons mg would be larger than the lift component and the plane would loose height.
@mohammadakib52895 жыл бұрын
I hope I score a* !!!
@faza210 Жыл бұрын
Very helpful
@ethitlan Жыл бұрын
For the last one, would the general form be S = (mv^2/r) + mgcosx, where x is the angle between the centripetal force and the vertical?
@scarletdesorgher63785 жыл бұрын
Why does acceleration= v^2/r ?
@ashala95 жыл бұрын
a bit late but v= ms-1, if you square that you get m^2 ^-2, dividing it by r gives ms^-2 therefore giving acceleration.
@Professorprime2 жыл бұрын
Gl guys for today!
@davidsykala53362 жыл бұрын
HERE WE GOOOOOOOOOOO
@kendo6669 Жыл бұрын
what exactly is the support force in the last example? if centripetal force is the resultant force and this is equal to mv^2/r. how is that you can write mv^2/r + mg = s?
@jadesolaadelekan49073 жыл бұрын
At 15.00, what exactly happens when a plane banks? Also, why is there a force that acts perpendicular to the wing?
@strict_asianbroccoli20232 жыл бұрын
why does the friction of the road against the wheels act towards the circle? other than it has to becuase it has to give the centripetal force. isnt friction against the direction of motion but the motion is tangential to the circular path? im abit confused about this point so would be grateful for some clarification. Thank you
@mountoubriandavid54724 жыл бұрын
Thanks alot sir
@Axashx4 жыл бұрын
Question: Is the resultant force experienced by the object in the last question different to the supportive force? o.O
@habibaptiofficial20073 жыл бұрын
Sir kindly help me in Q1 a level physics 2010 paper 4 summer varient 1. stone of weight 3.0 N is fixed, using glue, to one end P of a rigid rod CP, as shown in Fig. 1.1.85 cmCPωgluestone,weight 3.0 NFig. 1.1 The rod is rotated about end C so that the stone moves in a vertical circle of radius 85 cm. The angular speed ω of the rod and stone is gradually increased from zero until the glue snaps. The glue fixing the stone snaps when the tension in it is 18 N. For the position of the stone at which the glue snaps, (i) on the dotted circle of Fig. 1.1, mark with the letter S the position of the stone,
@florencejosiah-hp5yw Жыл бұрын
Thank u
@ryanmashru41195 жыл бұрын
Really helpful video. Keep it up!
@Science-sx8ho4 жыл бұрын
Actually you amazing
@awaisamer55815 жыл бұрын
What is a support force. What does it do?
@ritesha80503 жыл бұрын
Sir on the last part , what if the car is between the first and second position. How to derive an expression for acceleration.
@mohammedali786baller3 жыл бұрын
Thank
@xinfanguo8736 жыл бұрын
really nice video)))can you also do one for electronics and direct sensing ?
@anniemoses94784 жыл бұрын
you know how you said velocity is 90 degrees to the object's path, isn't the object's path going along with the direction of velocity and actually 90 degrees to the centripetal force? sorry i'm confused on that.
@ScienceShorts4 жыл бұрын
When do I say that?
@anniemoses94784 жыл бұрын
Science Shorts sorry I misunderstood when you said that “velocity is at a tangent to the object’s path.” But I see now that you mean it’s at a tangent to object’s path which is a circle. I understand now. Thankyou!
@rahulg.c48613 жыл бұрын
Awsom 👍👍
@WritersDigest-b8f Жыл бұрын
Why is the friction always acting toward the center ? If there is no friction which direction the car is going to move out, radially outward or along the tangent?
@ScienceShorts Жыл бұрын
No friction = no force = carries on straight into the hedge
@Hasnu77710 ай бұрын
isnt it v^2=gr tantheta?? It does say that in my physics textbook as well
@ScienceShorts10 ай бұрын
It depends what angle is used
@apurvmj4 жыл бұрын
Why do we have tension in string for rotating mass attached to it and not compressive force.
@ahmadghaffar67585 жыл бұрын
And why for the roller coaster example is there no friction ?
@jebnai74456 жыл бұрын
Why is the weight (mg) of the plane acting upwards? 14:07
@ScienceShorts6 жыл бұрын
All that is saying is that in order to fly level, there must be an upwards force equal to mg.
@evelynlau19296 жыл бұрын
Science Shorts what is the force acting at the top left of the plane? Why? 14:03
@cuzeverynameistaken12836 жыл бұрын
@@evelynlau1929 I know this is really late but thats the lift provided by the wings.
@ZainAli-ew6xj4 жыл бұрын
Angular displacement sir how does it relate to angular velocity?
@KM-sf5th4 жыл бұрын
Just 1 question: How does Time period and frequency link to the speed of the object going in a circle.
@ScienceShorts4 жыл бұрын
v=wr Where w is angular frequency (2pif)
@ackerman_amvs4 жыл бұрын
i had the video on high volume and now i have a heart attack
@jacobsuresh37433 жыл бұрын
same g also nice amvs
@ackerman_amvs3 жыл бұрын
@@jacobsuresh3743 thanks 😊😊
@namename31302 жыл бұрын
On the pronunciation of centripetal aside from centri-pee-tul and centrip-e-tal theres centri-puhtul
@AhmedHassan-xc8cn4 жыл бұрын
my concepts are still not clear with this video would you please make a new one ?
@ZiWARUDO6 жыл бұрын
@9:17 , how did it become 2”pie”fr ?
@spag52966 жыл бұрын
1/f = T, so 2πR/T can be re-written as 2πfR
@bakhtiarhossain075 жыл бұрын
Lifesaver
@mufarochiduwa6870 Жыл бұрын
WHERE DID THE COS THETA COME FROM
@chinmayvashishtha5 жыл бұрын
*RULER!!!*
@Khadijahx2384 жыл бұрын
Why does the International Space Station orbit the earth every 30 mins and why was a specific speed chosen for it?
@mauricegold93774 жыл бұрын
The ISS orbits the Earth every 90 minutes not 30, at an average altitude of 400 kilometres above the Earth. This was likely chosen as a safe minimum altitude that the Space Shuttle could reach, and that the ISS only required minimal occasional altitude boosts to avoid re-entry. The velocity it has is a function of its altitude. A higher altitude, less velocity. Lower altitude higher velocity. However, there is still some aerodynamic drag on the ISS due to residual atmosphere even at 400 kilometres, so it wouldn't be safe orbiting much lower, as the station is expected to remain in orbit for years, not just mere months.
@deadl1ght6196 жыл бұрын
hi, i'm just wondering, for the vertically circular path, at the end of the video, if the carriage is, say, slightly to the left of the top one would S become S = mv^2/r - Xmg where x is cos or sin of some angle?
@teamvolcan60714 жыл бұрын
So.......... Good
@ahmadghaffar67585 жыл бұрын
How is it that the friction is acting towards the centre ??
@rohankataria49265 жыл бұрын
When your going around a round about, there is a frictional force from your tires as your moving in a circle
@ahmadghaffar67585 жыл бұрын
Rohan kataria but how’s that acting towards the centre
@rohankataria49265 жыл бұрын
@@ahmadghaffar6758 friction will have a sideways component acting in the direction of the centre of the roundabout.
@mollyb73675 жыл бұрын
20 days until the exam......
@waleedmuhammad14845 жыл бұрын
dying slowly
@korduene7 ай бұрын
@@waleedmuhammad1484 what did you get?
@waleedmuhammad14847 ай бұрын
@@korduene c lol
@randomgameexperiments79183 жыл бұрын
10:06
@liquidfrog54593 жыл бұрын
circular
@Cardifyz7 жыл бұрын
isn't v^2 = grtanθ? I might be wrong. I mean you get different results depending on where your angle is which doesn't make much sense.
@ScienceShorts7 жыл бұрын
+Cardifyz That would be true if the angle was to the vertical.
@Cardifyz7 жыл бұрын
Why is it different?
@ScienceShorts7 жыл бұрын
Because the sin and cos would be swapped, resulting in cos(theta)/sin(theta), which is 1/tan(theta).