Series & Parallel - Potential Divider Circuits - GCSE & A-level Physics

[@jackudygames90]

Really appreciated. Not enough A level content around, especially not quality content like yours.

[@ScienceShorts]

+Jackudy Games Thanks!

[@pavanrai6904]

I've learnt more from your 12 min video on how to tackle a potential divider problem than I have from my actual teacher for over a year, so thank you.

[@kyliek.9481]

Pavan Rai my teacher gives us questions to do but never properly teach the content

[@GameRanger46]

same, never thought i would understand this thing guess they just dont have any patience or aptitude for teaching

[@anikabhuta1326]

Same same

[@datonebro613]

@@anikabhuta1326 Man idk if youre in uni now, but this video brings me a tear of joy, a sliver of hope and a light at the end of the tunnel.

[@Nafeelllll]

Exactly there is barely any good physics teachers rn

[@Rich-Richards]

never seen such a clear and clean explanation in yt videos, many thanks

[@lidlpropagandaministry2901]

1:28 Stalin approved

[@wiktorblaszczynski7270]

I don't think I get the joke help me out please

[@lidlpropagandaministry2901]

@@wiktorblaszczynski7270 "equal share"

[@wirag4680]

pertaining to communism, if you still don't understand :D

[@nosir1479]

I thought it was an execution joke

[@alandingleton6975]

@@wiktorblaszczynski7270 communism

[@baheerbaz3329]

mocks tomorrow and these vids are helping

[@abdullahalanezi7407]

You know I can't thank you enough for your very thorough, clear and concise explanations! Electricity and light particle is my least favorite topics and you made it much easier for me to comprehend it! I salute your efforts sir! Love the videos, keep em coming

[@shaheenchowdhury3736]

The concept is laid down so clearly. Learned a lot. Thanks for the effort.

[@Erica-rv7ze]

This was very well explained- in fact, I believe this is the best video out there explaining this concept!! Very big thank you :)

[@sadafaslam8178]

Logged in just so that I could like this video.

[@l4430]

great for both initially understanding a topic and also for consolidating and recapping any topics that you are rusty on last minute - thank you so much for the help! (exam on monday and physics is my worst subject but I at least feel like I understand the whole course thanks to you and your videos- it's just the application that can trip me up so after today it's time to hunt for any remaining past papers i haven't done yet)

[@7490maddie]

good luck today!!

[@l4430]

@@7490maddie Thank you! Think it went okay thanks :)

[@danielcawley1051]

@@l4430how did it go and how is life 5 years later?

[@ytrew9717]

the last part (what we can do with it) blew my mind, I finally understood something!

[@AmanKumar-3303]

Nobody ever explained me potential divider better... I have my 9701 AS level tomorrow and I owe you!

[@sakifnewaz7212]

I actually love these videos whenever I am confused it really helps me out and simplifies the content, amazing content keep it going please!

[@sraheelaali9817]

It helped me a lot , I have entirely grasped the concept of potential divider which was required according to my syllabus.I truly appreciate your effort.

[@stanpeter8098]

Thanks for your videos! I've appreciated your videos in many of your videos' comments but I just cannot thank you enough. You're the one who gives us salvation from physics!

[@franknillard]

wow you help me understand a concept that i wasnt able to understand with any other person. THANK YOU SO MUCH!! AND KEEP IT UP WITH THE QUALITY CONTENT!!

[@Momo-ci9ug]

Just saved my whole a levels in 13 minutes love this guy

[@sugondhesenuts838]

My parents are wasting money on school frees. You can literally learn so much in such short time from youtube videos, thank you so much!

[@ScienceShorts]

Don't forget, your parents can always make a donation via PayPal to me instead! 😊 bit.ly/scienceshortsdonate2

[@heinzarniaung2915]

Thanks for the timestamps. One of the best edu channels around

[@charleyyross7164]

Very hard to revise for me, but after watching a few of your videos, i feel up to do date and ready for my second biology exam... Appreciate the videos a lot, and please keep doing more as they are helping me and alot of others getting reay for exams.

[@nehakumaran6000]

Never understood why resistance goes up in a light dependent resistor when light intensity decreases until I saw your video.. Thank you so much!! Finals are coming up in a week and I've been so stressed, so I'm really thankful for this video. Cheers!

[@josswheeldon9737]

Extremely helpful, been struggling with them a lot and this has clarified and answered all of my questions!

[@gingjing3243]

there is just stuff i rather watch video on for revision than my notes, good video

[@singularity5500]

Wow amazing, the last part changed everything that I thought of electricity 😂. No more fear

[@cheesenpickles1241]

Wonderful potential divider segment - first channel I've found to actually explain how the equation is derived. Thanks :))

[@samuel3176]

Thanks man. You’ve actually helped so much. I’m gonna subscribe now because wow I’m amazed by how much I’ve learnt in just 12 mins

[@yougottabemadasllmao]

one of the best revision channel for as levels alongside Erintoul and mr pollock!

[@gus1755]

This helped, glad I saw this before my a level exam in 5 days

[@v0n12z]

ive been struggling to get my head around the meaning/"roles" of each element in electricity, (especially how p.d. interacts with current) in an intuitive way not just through equations, the explanation of "higher resistance means its harder for electrons to pass through therefore they need more energy" really helped, idk how its never been explained to me this way before 😅 electricity has been the bain of my existence, i'll stick to mechanics thanks 😭

[@elliewhiter]

Really useful. Could you do some more videos where you talk through A level electricity problems?

[@hillybilly3028]

Ellie Whiter Yeah i am also trying to find those videos

[@Berna--gg7xs]

DrPhysicsA tends to do more videos on the maths solutions for most topics

[@EpicAbid]

you are saving my a level physics. thank you

[@alpha.beta.gamma.1843]

I appreciate your channel a lot... you explain better than my teacher.... You just got a new subscriber

[@HoshikawaHikari]

In the end, KZbin teachers like you help me understand better~ Thanks~

[@igothacked3742]

guy made this 7 years ago, got almost 0 likes but still explains better than every a levels physics teacher on youtube

[@ScienceShorts]

I see 4700 likes 🤷‍♂️

[@YoungBrokeBoon]

thanks for the help, couldn't get my head around this but you make it really easy to understand!

[@jamiewhitehouse1708]

OMG you are so much better than my actual physics teachers, thank you so much

[@miesht430]

I absolutely love all your videos and they keep me going thank you so much

[@seasnek7024]

I don’t mean to sound dumb, but if the thermistor gets colder, shouldn’t resistance decrease? (Cause superconductors have almost zero electrical resistance when cooled to sub zero temperatures, so that’s why thought colder temp = lower resistance)

[@user-kl4hb7my1r]

A NTC; "Negative Temperature Coefficient" thermistor works in the opposite way a normal resistor does. At low temperatures, the thermistor has a high resistance. As the temperature increases, the resistance decreases. This is because at higher temperatures the electrons have enough energy to escape from their respective atoms, meaning there are more charge carriers available, therefore the resistance is lower.

[@eamonn5020]

I know its a bit late but for anyone reading in the future superconductors dont have almost 0 electrical resistance they have exactly 0 electrical resistance

[@minhtrinh99]

Thank you

[@Mirsab]

I was stuck at this for so long, thank you so much!!! It makes so much sense now!

[@taz4530]

Ur saving my GCSEs dude

[@swapnanilde7736]

Nice vid - anything about variable potential dividers would be a useful addition.

[@vamshidarisi8400]

swappy lmaooooo

[@lawrencewinter]

Hi there, I have a question... At 10:58 you said that anything in parallel will get the same voltage. But, surely the heater's resistance in combination with the Thermistor's resistance will give them both an effective resistance which is different. Presumably the Heater part of the circuit is separated by some kind of relay or something so as not to combine with the Thermistor and affect the resistance of that half of the Potential Divider Circuit? Thanks.

[@ScienceShorts]

Yes, in reality that is the case. This is just a general concept. Actually, in practice it will be a sensor, not the heater itself.

[@jacobsmusic4186]

Really helpful. Especially for revision! Great vids man,

[@shujamukhtar4563]

Now, that is what you call perfection.

[@lollies6865]

What is the purpose of the fixed resistor in the LDR set up?Why is it needed when the lamp depends only on the LDR's voltage and not the other one?

[@oscarpoll4324]

Slight mistake at 9:31 (in case you didnt know), you said total resistance instead of total voltage. Thanks a lot for these great videos!

[@AbdullahiIdri2001]

Are electrons sentient beings that can tell when there's more than one resistor in the circuit? Why don't they lose all their voltage to the first one? Sorry if i sound like an idiot lmao.

[@AbdullahiIdri2001]

Also, this was a quality video so thank you very much!

[@dude_mude3366]

OH MAH GOD UR A LIFE SAVERERERERERER. Literal hero.

[@maddocksjos]

How did you get so much pen on your hands??

[@Awai_quotes]

You see for the last one if the light is bright (in a day ) can it reach this point where it wouldn't take any share of voltage and also would the lamp would still turn on even tho light is bright?

[@adiedaylight]

this is so helpful lol cleared all my confusions!

[@emmacole2296]

9:53 I can't find this equation on the AQA equation sheet? Do we have to memorise it? Thanks!

[@gaminghats813]

idk but just use ratios is kinda ez

[@Blueberrywee]

Nope, it isn’t on the eq sheet because it is a relatively simple and a derived formula from ratios. It’s pretty easy to learn so you can do that.

[@xkl-physics7287]

Sorry for asking lots of questions, electricity is very hard : why does the current through the LDR decrease?

[@sebastianstanley1597]

u are so good at explaining! Thanks.

[@jamienewman1488]

Hi in your potential divider circuit you drew at 7:11 , you included 2 rails 12V and 0 Volts instead of the battery. Could I ask where the other end of rails go at the opposite end of the circuit after the resistors? They are confusing because you did not give them any kind of reference.

[@grif.t7852]

He defines Perfection .

[@melodykamil]

Thank you! That was so helpful.

[@joshuapiper8190]

For parallel circuits with 2 resistors use R1xR2 divided by R1+R2 that’s a nicer equation. Only works for 2 resistors though.

[@Awai_quotes]

Are you sure??bc it mught now

[@sairemkhan6974]

THANK YOU SO MUCH!!! Really grateful for the help!

[@kevvonkev]

can you explain potential deviders in terms of current, the video was amazing!

[@entertainingvariety8893]

Thanks Sir ! You sound like Mike Thurston !!!! If you don't him search him up and compare his voice to yours

[@MasterZack1000]

In the last video you said that resistance increases with low temp in a thermistor and high light in a LDR (vice versa) but here you are saying the complete opposite?

[@LeonLuckyV]

which a level exam board is this for? AQA i hope :/

[@g-shockforlife1703]

Aren't thermistors and LDR cancelled in the new AS cie syllabus?

[@parttimeshorts8566]

Pls do some questions on Thermistor, LDR , Variable resistor

[@williamstephenjones3863]

Brilliant video.

[@giftayo6061]

12:23 why would the resistance increase if it gets darker. Isn't goes down beacuse it should allow more current passing through to get brighter?

[@randhawaheed2720]

When it gets darker less light falls on it so tmp would DECREASE and since LDR has LESS free electrons and tmp is decreasing due to darkness, there would be less no of free electrons means resistance would INCREASE , in short as it gets darker for LDR, resistance would increase because of its semiconductor properties

[@aditfahad2468]

Thank you so much for this sir. I really can't thank you enough. This helps so much to understand what I don't get in classes. Keep doing this sir. Cheers

[@bilalmuhammad1547]

11:24 if it isn't changing its resistance then how it is possible for it to get a higher voltage then thermistor

[@rkarox5858]

bilal tanweer it’s not changing voltage of the fixed resistor, the ratio of the fixed resistor to the thermistor is altered so that the the thermistor’s resistance decreases. This means the fixed resistor will get more share of the voltage as the share of the voltage for the thermistor is decreased when it gets hotter

[@bilalmuhammad1547]

@@rkarox5858 thnkx

[@motivationformuslims1214]

Thanks for the great explanation,😊

[@bramal-sharifi2036]

We got given a resistor (75ohms) and a LDR in series. The lamp is at 10cm from the LDR and the reading on the voltmeter in parallel to the resistor is 2.4V. Battery is 6V Calculate the resistance of the LDR at this distance.H How do we do this?

[@acerage6738]

its not possible without knowing the energy the lamp emits. surely?

[@yahusain2979]

Hi. Can the potential divider be treated as a proportion porblem For eg: (12/6) *2 = 4 which is correct

[@ScienceShorts]

No way! 😂

[@meharpalbasi4801]

For the fan example, could you also place it in series with the resistor and thermistor?

[@James-zs3vm]

Maybe that would work, just a lot less efficiently, as it acts as it's own resistor and gets a lesser share of the voltage

[@rayhanosman427]

What makes the lamp lights? the voltage or the current?!

[@arshsood544]

excellent videos man... really really helpful. thank you so much

[@ahmedsidiahmed2173]

for the same resistance, 1 coulomb of charge would lose all of its energy by flowing through it, but if we have two identical it would only lose half of its energy?? why is that?

[@turbothrottletrouble4217]

Could you make ib specific videos? It would be very very helpful

[@tarikadiwakar1035]

Super helpful. Thank you

[@mimishah9231]

your videos are amazing 🤓🤓🤓🤓

[@adampat6473]

Thank you so much. Its so easy to understand the way you teach and summarise everything. Your a life saver!

[@fahimal-huq6867]

THANKS A LOT SIR.PLEASE KEEP UPLOADING VIDEOS.

[@Nxck2440]

For the circuit at 5:31 how can I work out the current in one of the parallel branches. Here's my attempt, R_tot = 10 + 1/(1/50 + 1/50) = 35 V_tot = I_tot * R_tot --> 12 = I_tot * 35 --> I_tot = 12/35 = 0.34 A Current is shared in parallel so current in one branch = 0.34 / 2 = 0.17 A If this is correct, what about if one of the 50 resistors is changed to 40. How to we divide up the current?

[@mohamedrashed6643]

i think you would do it the same way.

[@Nxck2440]

@@mohamedrashed6643 I think I understand better since watching this. For the example in my comment, I did R_tot = 10 + 1/(1/50 + 1/40) = 32.22 I_tot = V_tot / R_tot = 12/32.22 = 0.372 A p.d. across series resistor / V_tot = R/R_tot --> V/12 = 10/32.22 --> V = 3.72 p.d. across parallel part = 12 - 3.72 = 8.28 V Current across 40 resistor = p.d. across parallel part / Resistance = 8.28/40 = 0.21 A Current across 50 resistor = p.d. across parallel part / Resistance = 8.28/50 = 0.17 A Check: Total current should equal 0.37. 0.21 + 0.17 = 0.38 (close enough, error due to rounding). (This whole thing was just to check my own understanding, hopefully someone else finds it useful too!)

[@mohamedrashed6643]

How do you now my name?

[@ethanmyles9448]

@@mohamedrashed6643 WTF 😆 your name is your username.

[@KAPOORVANSHIKA]

what is load in a battery?

[@fatmafaizal07]

hi ur videos help alot.. a humble request though.. could you upload videos of solving cie pastpaper question for the recent year..? 2016 2015 ? just paper 2?

[@purplebubbles3324]

Thank you this is a great video.

[@billy5030]

Brilliantly explained :)

[@123qwe321ify]

Thanks for another great video

[@ScienceShorts]

:)

[@Oranje014]

What happens to the current as the resistance of the LDR or thermistor increases and how do you explain that

[@M_B_T.]

pretty sure it remains constant since its a series circuit

[@mohasali5640]

​@M_B_T Think carefully. V(total)=IR(total). We know that V will remain constant and that resistance has increased. Therefore, the current will decrease. Another way of thinking about it is that resistance is how difficult it is for current to flow, so increasing resistance will decrease the current as less charge travelling per second.

[@Saad-rm8sd]

I hate ELECTRICITY but you make sense. AS EXAM in a month.

[@cookiesandcream3953]

SAMEEEEEEEEEEEE

[@EsotericMedic]

Mines in 2 weeks and I'm just learning content now :( definitely failing

[@Refract404]

We're all going to drop the grade boundaries together

[@sunnykim2134]

@@Refract404 yay

[@yololula3495]

@@Refract404 fingers crossed for unit 1

[@MuhammadBilal-ns3tb]

thank you sir!!

[@brandonadams3477]

Is this for AQA ?

[@Clark_Ken]

please help me understand whats happening at 10:50 onward

[@muluekebedom]

Thanks that’s extremely helpful...

[@mohammedsabri7226]

Best of the best

[@alexcook9373]

What happens when there is 2 cells connected in parallel and you are asked to work out the current or voltage of one of the resistors in the circuit?

[@Awai_quotes]

Watch video on kirchoff laws (ik I'm late)

[@sudhaverma2628]

Thank you so much !!! it was very helpful !!!

[@karatemario2760]

Bloody brilliant!

[@hi44098]

Thank you for the video

[@iSteelRazorBladeGAMING]

Great video, very helpful