SD3: Steel Design (Tension Members): Part 3

[@bravofelixjuanadolfo8323]

thanks for excellent materials

[@civilengineeringfromgoldme3074]

Nice teaching method Appreciated

[@abbashomaei5860]

Thanks for these series of videos. Please continue all subjects about Steel design.

[@civiltechtime708]

Always useful for building concepts Plz keep it up

[@beatdeals4248]

Hi Dr, in the problem solution no.2, in finding the Net area for path 2, shouldnt 0.448 be substituted for t? It seems like there was a mis input there, since it shows 2 x 2²/10 x 7/8, while it should be 2 x 2²/10 x 0.448, if I am right. Through my calculation, the net area for path 2 is 5.0715 in², thus leaving this as my final effective area. Thanks

[@DrStructure]

You are correct. We have updated the solution file. Thank you for bringing this error to our attention.

[@DARVESHKAUSHIKHR09]

Excellent explaination.

[@manija4527]

Nice lecture , which application used ? For tutorial?

[@mariamabdu5069]

can u explain the " 4@2'' " like what is the units for " 4 " and why is ur L value when calculating U 8 in the denominator why not 2''?

[@DrStructure]

In exercise problem 2, the notation 4@2” means the spacing between two consecutive vertical lines (shown on the drawing) is 2 inches, and we have 4 of them, which makes the overall length of the connection 8 inches. That is why we use 8 in the denominator when determining U, since the length in the denominator for U is the overall length of the connection.

[@DARVESHKAUSHIKHR09]

Plz make video on dynamic analysis of structure