Second derivative test | Using derivatives to analyze functions | AP Calculus AB | Khan Academy

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Sal justifies the second derivative test, which is a way of determining relative minima & maxima, and gives an example.
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[@mattwarrenAV]

Bless Khan Academy during corona virus pandemic 🙏🙏🙏

[@ethandiamond6542]

This makes sense if you’re looking at how the tangents change from left to right on the curves. If you look at the tangents from right to left it breaks down. On the concave down shape, from right to left, the tangent is decreasing to 0 then getting steeper but in a positive way.

[@johntindell9591]

thank you very Much, so helpful

[@black_jack_meghav]

Sir, thanks for _existing_

[@qwerty.760]

using of different colors is awesome!

[@jaredmorales9763]

Umair facts it looks really nice

[@jaredmorales9763]

Lowkey makes you more interested and makes it less monotonous

[@mohsinchaudhary4360]

Why is 2nd derivative of functions -ve for max and +ve for min

[@trwent]

Actually, there are TWO cases where the Second Derivative Test is inconclusive: (1) f"(c) = 0 (you have that one), and (2) f"(c) undefined (you missed that one). It IS possible for f'(c) to be DEFINED but f"(c) to be UNDEFINED. For example, consider the function f(x) = x^(4/3). Then f'(x) is essentially x^(1/3) which is 0 only for x = 0, so x = 0 is a critical number (the only one, since f'(x) is never undefined). Then, f"(x) is essentially x^(-2/3), which is UNDEFINED for x = 0, so the Second Derivative Test is INCONCLUSIVE for the only critical number for f, x = 0. However, if we use the First Derivative Test, we find that f'(x) is negative for x to the left of 0 and positive for x to the right of 0, so clearly (0,0) is a local MINIMUM point.

[@freyawoodrow7209]

What is the higher operation needed to determine the concavity of a function with a critical point of 0?

[@hippzhipos2385]

Noone knows answer

[@dineshmathsclasses8363]

How u set pen for writing

[@jintsuubest9331]

do sal do this with a mouse?

[@kingstarsky9739]

no...

[@nextgencs7]

this might be obvious but how did you get -4 for the second derivative?

[@notatruestatement]

It's a hypothetical.

[@HassHansson]

its just an example

[@nohackers2037]

wait. Isn't the second diff of a quadratic a point?

[@jimmybob609]

Let’s for example use x^2 f’x=2x so the rate of change of our function is 2x. The second derivative would be 2, which would be the rate of change of our first derivative which is constantly changing by a factor of 2.

[@nohackers2037]

@@jimmybob609 yes. Your comment helped out a lot dy/dx is y/x also known as rate Example d/t = S (distance travelled per unit time) is rate. Also gives you a slope at any given point (d/t)/t = second derivative which tells you what happens as the rate changes over time eg: speed/t = acceleration. is the change of speed

[@nohackers2037]

@@jimmybob609 wait. clarify this for me the second derivative determins how pointy is a function for x^3? and x^2 right?