Semaphore| Binary Semaphore| Mutex|Conting Semaphore| RTOS

  Рет қаралды 9,042

Easy Electronics

Easy Electronics

Күн бұрын

Пікірлер: 7
@RISHITHAMCSE
@RISHITHAMCSE 6 ай бұрын
thank u for saving my entire chapter for my tomorrow sem :)
@EasyElectronics_jobupdates
@EasyElectronics_jobupdates 6 ай бұрын
Welcome ❤️
@arupsarkar6871
@arupsarkar6871 2 жыл бұрын
Thank you ❤️☺️
@sachindubey5999
@sachindubey5999 3 жыл бұрын
doubt- why counting semaphore is a solution for critical section problem? since many processses will present in critical section ,and this violates mutual exclusion property.
@EasyElectronics_jobupdates
@EasyElectronics_jobupdates 3 жыл бұрын
its not a solution because as u have said it is not having ownership, any process can release it even though it has not acquired it
@focusman8801
@focusman8801 3 жыл бұрын
@@EasyElectronics_jobupdates maam if in binary semaphore other process can signal() it then how it can be mutual exclusive and how it helps in synchronization process ???
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