Semigroup in Group Theory | Discrete Mathematics

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Semigroup is an algebraic structure consisting of a set together with an associative binary operation.
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#semigroup #grouptheory #discreteMathematics #discrete_mathematics #discretemathematicsgate

[@ravirajkudal5626]

Bro you don't know how much you helped me in study... Thanks for Everything🙏🙏 , keep uploading

[@rohitsinghsde]

Best mentor ever i have seen.. amazing

[@AlokKumar-ow5uq]

i'm a MCA student it's my first year i started study after years again ... because of you i scored in my first and second MST sem exam is at door ...thank you sooo much sir .. love from bnaras❤️

[@AevyScience]

Mai bhi mca se aur banaras se

[@jasimuddingazi7521]

MCA

[@praveen_kr]

(Z, ÷) does not follow closure property as well as associative property.

[@tanishqgupta8470]

Kaise

[@tanishqgupta8470]

6, 2

[@hashfaqak1516]

@Utsav so?... There is infinity

[@RakeshGupta-xw5fx]

Because integer can not kept decimal number so it's not hold clouser and associative property for division

[@nupurhiray2318]

Thankyou is much sir ! This helped a lot.. I was struggling with algebraic structure until I watched your videos... keep going 🌟😇🔆

[@hellolearning5775]

Your explanation is always awesome.... Whenever I am stuck in any subject and that is available on your channel then i feel very relaxed that if i watch it before one day a paper , the paper will be awesome 😎.... Lot of pray for you sir 💓💓

[@khalnayak4461]

than you sir providing this type of video

[@InvinciblePepe]

Extremely helpful and easy way of teaching. Thanks

[@sachinv45]

Best way of explaining

[@muhammetuysalilematematik7997]

S= find the member of semigroup S using breeding coset enumeration technique

[@Anchal-73]

Clear cut explanation sir🎉 thank you so much ❤ 😊

[@amiteshsingh5960]

Best mentor 🙏

[@hasinimuvva9158]

The best teacher 💯💯

[@abhijitsakhare8094]

😂

[@erakshisharma1633]

you will never find a better teacher then him 😃😃

[@ਮਨਦੀਪਕੌਰ-ਹ7ਫ]

❤️Wonderful session ❤️❤️

[@khalnayak4461]

you are so great

[@educationvalashorts]

Big fan sir ❤❤❤

[@sohail_0786]

Very nice explanation every std can understand thanks a lot sir plz upload more and more videos

[@srinathbadugu9314]

(Z, ÷) => first of all its not an algebraic structure ,so no need to check whether it's semi group or not. 5÷ 2= 2.5 doesn't belong to Z.

[@technicalfacts8002]

My no1 favourite sir Thanks sir

[@balaji_prabhu]

taught so well …subscribe karna toh banta haj 😊😊😊

[@tanishqpaliwal1761]

Literally thank you so much sir ❤

[@rahilnaseem5700]

Finally found the best Mentor ☺️

[@asraarfiza701]

Thank you sir... For your continous effort😇😇

[@vittuyadav840]

Nice explain sir

[@Ask_0586]

Excellent brother

[@JaswinderSingh-Phy]

With the help of Gate Smasher, We Smash our our mst and all exam.😅😅

[@yashmayanil7852]

Thank you sooo much sir its very helpful....

[@Ucoepapers_1]

Wonderful ❤❤

[@JustwaitNwatch-w]

Semi group : an algebraic structure (S , *) is semi group if it follows associative property Algebraic structure must follow closure prop.

[@ojaskumar2355]

Thanku sir... U r amazing😍

[@trendingtechno9634]

Best way to teach 👍 Sir what about monoid for integer numbers with multiplication?

[@nisarahmedmathematics]

Z under multiplication is a Monoid as it has a Multiplicative identity element as 1.

[@eshamohan07]

Great explanation! Thank you sir

[@Sejal.Yadav_88]

Thanks !!!

[@rudrajoshi1948]

Playlist ka main dailogue, Subscriber Bahot Jaruri hai😄😄😄❤❤❤

[@vittuyadav840]

Sir please continue to teach

[@aditisisodiya-xo8fh]

thank you sir

[@AyushVerma-ro1gh]

thank you

[@helloabtech5187]

i understand this topic

[@tanishqsingh8005]

Thanks sir for this video and a request you can make video on coset, lattice ,Homomorphism, Isomorphism and Automorphism of groups. Please sir a humble request

[@bijaykumarmohanta646]

The last example which is given for 2^n is not closure if one take n= 1 and n = -2, then the ans will be a rational number.

[@rajeshkumarsahu6662]

Thank sir.

[@RahulChaudhary-yb7ee]

Tysm sir!❤️

[@jugalpurohit3768]

Product and Quotient of semi groups please make video on it

[@p3nta-gon]

I like how you say subscriber jruri hai😂

[@ritikdahiya6946]

Topp brother

[@YashDabhade-cr5my]

[@ashutoshacharya7937]

Sir if we take -ve value of n in the (2^n) example then the answer we will get in -ve power of 2 which is not a integer That means it is not closer So it is not semi-group

[@bishalnath4820]

Yes... I have same question also

[@anweshabiswas19]

n should be an integer..not 2^n according to question..check again..

[@introverts_site]

​@@anweshabiswas19-ve is also an integer

[@anweshabiswas19]

@@introverts_site yeah -ve whole numbers are Also integers..

[@introverts_site]

@@anweshabiswas19 finally uhh got this 😁

[@riyapathak6743]

Division is not a semigroup in case of Z

[@apratick]

In example 2^n, where n is an integer, don't you think, its not an algebraic structure? because if you put n=-1, the output is 0.5 which is not an interger. Please correct me if I'm wrong.

[@sachinkoli6887]

Yaa bro , you are right 👍

[@mukulsaini2961]

Exactly, i am thinking same ....and you are right its not follow closure property.

[@krishlalwani5607]

Right ✅

[@annymous2.041]

How bro

[@annymous2.041]

2^-1 * 2^-4 ... if base same power add 2^-5 which is integer

[@anupamsaraswat5387]

Sir pls upload the full videos of this topic....

[@gitanshagarwal7597]

if we do (5/0), as both 5 and 0 are integers the answer would be infinity which is not an integer number, so it does not follow closure property and so it is not an algebraic structure and hence it is not a semigroup.

[@manasimore9828]

Sir please upload video on K-map. Please sir humble Request!🙏

[@SaurabhKumar-qb8ui]

In 2^n if we take n=-1, then it is not an integer.

[@Professor_MH]

kya pdhaate ho sir aap...👏

[@NehaSolanki-uz5fj]

Thankyou Thankyou thankyou

[@truptirekhapati1441]

Sir division doesn't follow associativity ,so can't be semigroup .. correct me if I am wrong

[@ravalanand2434]

It doesn't follow closer property...

[@learncseasily3385]

5:20 I think multiplication doesn't satisfying associative property

[@pooo8781]

sir, could you please make one video for triggers in SQL . i found you haven't made video on triggers . please sir .

[@thepromise6237]

What If we take negative values In 2^n /n is integer w.r.t. * {n=-1,-2 Plz explain

[@jigacharlaajay9464]

Integers can be negative too then it will not satisfy closure property then it is not a semi group

[@fazalsubhan5379]

❤❤❤❤❤

[@rayanbag907]

So, 2^n is not closer

[@supriyachauhan5341]

Sir please upload videos for group and abelian group..

[@kashishsharma9012]

In last, example 2^n is not an algebraic structure because if we take 2^0*2^-1 =0.5 is not an integer

[@trusteddestiny]

Given n is integer not 2^n So 2^0.2^(-1) gives 2^(-1) only where -1 is integer so it's algebric structure

[@shubham_paliwal]

The division will not be a semi-group with respect to the set of all integers Z, because it does not even follow closure property, i.e., it will even not be an algebraic structure.

[@shraddha429]

Integer (Z) ke isme division check krne ki kya jarurt sir wo closure property hi nhi follow krti..

[@parasinfo5397]

Right🤞🏻

[@honeymalhotra525]

2^n is not following closure property , if i take n = -5 which is integer 2^-5 is 1/32 is not an integer hence , (2^n, . ) is not a SG

[@gojothecoder]

thinking same bro

[@singmanassingh12345]

Sir devision ke method me natural number flow (semigraph) hoga Bhai koi bata do❤

[@elements8630]

last example mein n=-1 daal du toh? it should not be a SEMI GROUP, right? Please clarify this doubt

[@bishwadeeprana6856]

we are checking the value whether n is coming integer or not ,we are not checking the overall value of 2^n

[@elements8630]

@@bishwadeeprana6856 oh, thanks

[@harishmanral9077]

Good but when binary operation is * over set then how come + is defined to add power

[@maaz_gamming]

Tommarow is my exam of mca 😅

[@anubhabsaha3424]

which college?

[@whatssay6264]

Division is not a semi group because first of all it doesn't follow closer property and not a algebric structure 🤘😅

[@ashamach]

Division is not a semi group because it's doesn't follow associative property.

[@manojverma245]

For semi group first have to proof closure property

[@suhanimohanty197]

Will 2^n follow associative property? As an integer we can have -ve power also.

[@ApurbMishra]

yup at that case we can get decimal number which dont come in integer

[@cap10a19]

(Z , /) can not be a algebraic structure yet , so it is not a semi group Thank you

[@SHAIKSILAR07]

❤

[@adityabatra6248]

in the last expression n is an integer so it can be negetive aswell consider (2^-3)*(2^2)=0.5 which does not belong to integer so closure is not met how is this semi group please clarify

[@niteshparik6734]

Division on Integers set does not follow associative property and that's why it is not a semi-group.

[@gyanletechlo8975]

Sir R star ka mtlb kya hota h?

[@ayushpatil1189]

gud boi

[@archanaray4972]

Sir if (z,.) Monoid group hai to kya semi group hoga?

[@farzanhussain9427]

Sir please Solve the GATE 2021 paper topic wise

[@sanskritisamadhiya7505]

z is not a semi group as well as algebric structure bcoz it doesnt follow closure property as well as associative property .

[@tarakumar7787]

Sir (5-3)-2=5-(3+2) na sir, not 5-(3-2) right? In the example u have given

[@tarakumar7787]

At time 5.53

[@FREAKIN.07]

sir last question me n -ve value le to decimal me value ayega vo integer nahi hai to kaise closure property follow hui

[@anchalpandey7572]

❤❤❤🙏🙏

[@shubhangihatkar1347]

🌟🌟🌟🌟🌟

[@shikharagrahari6585]

Sir (N,.) is not shown closer property

[@taleemateahlebait3190]

Sir ic m truth table wly topics bhe cover krvain

[@muhammetuysalilematematik7997]

hello, I have a question about semigroup, can you solve my question?

[@AJEDUTALK]

(z,/)Does not follow closure property so it does not comes under algebraic structure so how it comes under Semi group .

[@syedtousif5666]

Integer is not semi group

[@Pratham__Sharma]

(z,/) does not even follow closure property ..so it's not a semi group

[@prathamvyas6640]

Hi ! brother please send me java program for sine wave pattern?

[@ketangupta1910]

(Z, /) does not follow closure property, so its not a semigroup

[@sv-nl5yd]

Does not follow the closure property

[@MaddyisLivee]

2 ki power integers m h to minus m lo power to wo rational number bnjaega to wo follow hi ni krega

[@avijeetgorai3697]

(Z,÷) nahi hoga kyu ki wo algebraic structure form nahi kar raha ha