Series RLC Circuit

This video discusses solving a Series containing Resistance, Capacitance, and Inductance. It goes through the steps of solving Coil Impedance, Circuit Impedance, Current, and Voltage Relationships.
Phasor Basics: • Adding Phasors - The B...
Adding Phasors: • Adding Phasors - HV Chart
RLC Circuits Playlist: • Single-Phase RLC Circuits
#RLC #Series

[@howto5870]

I love it. Thanks for making my life easier to calculate

[@richardranger4460]

Thanks this helped me out. I'm taking my second period electrical at home, so I appreciate your videos

[@eatonce]

These videos are amazing. Very clear and concise!

[@8989griff]

@@eatonce me too lol I’m stuck on this part and almost finished.

[@robgingras7127]

Thanks so much for these Zack. you really helped out with 2nd year RLC

[@ZackHartle]

Happy to help!

[@regbot4432]

Really like tutorials in which tuts are using these black transparent boards. It makes me hipnotized somehow and I'm able to focus a little better on the matter.

[@ZackHartle]

That's awesome. Thanks for watching!

[@anielskisowianin5199]

i have test from this in tuesday i finnaly know what i should do. Greetings form Poland

[@ZackHartle]

That's great! Thanks for watching!

[@loudhawsgaming2711]

thanks mate

[@ricklima2105]

great stuff thanks

[@CypherKing1]

thank u a lot

[@CypherKing1]

what light board are u using. I would like to know more details about it

[@jamesm6951]

You can't just throw in a phase angle of -90 for the capacitor without considering the phase angle of the current which comes from the total impedance Zt. This would give 14.9A with a phase angle of -35.9 which would result in a voltage and phase angle across the capacitor of 113.4V and an angle of (-90 PLUS -35.9 = -125.9) degrees, not 270/-90. Please correct me if I'm wrong.

[@ZackHartle]

The phase angle of -90 is just for the Voltage across the capacitor and the total current

[@jamesm6951]

Ah, I didn't watch the last minute where you solved for theta of the original voltage. I had assumed that a phase angle of 0 was implied for the voltage. So yes that would put your current at a phase angle of 0 and your cap voltage at a phase angle of -90 degrees. Thanks for clarifying.

[@TheFloatingIdiot]

What would you do if you had A circuit that consists of a coil and a capacitor connected in series across a 120 V, 60 Hz supply. The capacitor has a value of 35 µF. The circuit current is 8.5 A (lagging), and the wattmeter shows 250 W?

[@ZackHartle]

It would really depend what I was looking for. But for the capacitor you can easily calculate Ohms, Volts, and reactive Power If you know the total current and voltage, you know your totla apparent power, so you can put the watts and Qxc on a power diagram to figure out the QxL.

[@starlapenner]

How do you find the capacitive reactance if you only have the volt drop and current across the capacitor?

[@ZackHartle]

It would just be by transposing ohms law. Z = E / I

[@uberlycidas]

I keep getting a Xc= .00758 ohms: which converts to 7.58 micro ohms as you wrote it on the whiteboard.

[@uberlycidas]

Oops calculator error. I thought I could skip the * between 2 and pi

[@uberlycidas]

Nope that wasn't it. I believe your Xc is not in ohms but in mili-ohms

[@8989griff]

Awesome! How do I email you?

[@8989griff]

I have 2 questions that I need help with. First question: A coil and a resistor are connected in series with the following values: The resistor is 4.2 ohm The current through the circuit is 9 A The total power dissipated by the circuit is 800 W The supply is a 120 V, 60 Hz supply. Find XL of the coil Find the VD across the coil Find the pf of the coil

[@CypherKing1]

what light board are u using. I would like to know more details about it

[@ZackHartle]

It's a custom built one