Session 8: Examples & different kind of questions one can ask on Fourier series.(see pinned comment)

[@DrMathaholic]

At 13:13 by mistake i wrote that sum of Fourier series at x=0 is (1+1)/2=1. There is a mistake, here left hand limit is -1 and right hand limit 1 so Average will be 0.

[@amansartaz5864]

At discontinuity the mid point of the Fourier function at the point of discontinuity is the sum of Fourier series at a discontinuity.

[@New_thinkers]

Hello sir , i have completed my syllabus from you , this playlist is great , have watched almost all 69 videos. You are a great teacher

[@DrMathaholic]

Good👏👏 all the best for exams Thank you 😊

[@DrMathaholic]

Now, also, solve tutorial problems on ur own.. your score will b v.good

[@vaishnavisabale7094]

Great video sir

[@muhammadrayanmansoor4301]

Sir please make a playlist on Fourier integrals ❤

[@DrMathaholic]

Ok, noted..hopefully soon 🙂

[@the.rajkumar.sawant]

Great video sir💥💥. Can you take some more problems on half range concept??

[@DrMathaholic]

Okay. I will make a video on half range in a day or two.

[@DrMathaholic]

Made one video on half range.. hope this will help you. Here is the link- kzbin.info/www/bejne/pZ7SZmSNetqkoac

[@the.rajkumar.sawant]

@@DrMathaholic thank you sir

[@abdurrahmanlabib916]

Sir can you make videos on fourier transform thank you

[@DrMathaholic]

I have made on fourier series.. Fourier transforms, hopefully soon :)

[@THUNDER-kw3wq]

Sir at 3:25 LHL is 0 and RHL is 1 at x=0 so avg must be 1/2 right...i mean should we check the values from graph or should we do it using formula?

[@DrMathaholic]

Yes you are right..average is 1/2.. thanks for pointing it out..you can approach by whichever way is easier for you

[@THUNDER-kw3wq]

@@DrMathaholic Ohkk..Thank you sir🙏🏻🙌🏻

[@DrMathaholic]

@@THUNDER-kw3wq 😊👍

[@THUNDER-kw3wq]

Sir will it be mentioned in the ques that we have to solve it by half range expansion?

[@DrMathaholic]

Yes...technically they should... If not, then other way of asking this is - find cosine series for the given function... Or Find sine series for the given function.. Then they will also fall under the category of half range..

[@THUNDER-kw3wq]

@@DrMathaholic ohkk Thank youu very much Sir...tmrw we have our UVC endsem...aapka aashirwaad saath rahe😊🙏🏻also Happy teachers day sir...couldnt wish yesterday😅...UVC aapke wajah se nikalne wala hai🙏🏻Thanks a lottt U r a saviour🙏🏻

[@DrMathaholic]

@@THUNDER-kw3wq thank you for your wishes.. Hahahaha..koi na, acha jaaega..mera aadhirwad hai tum logo k sath😉

[@THUNDER-kw3wq]

@@DrMathaholic 😂😊🙏🏻aced t1 t2 because of ur videos i hope its the same tmrw

[@DrMathaholic]

@@THUNDER-kw3wq oh great..Happy to hear that..Kal b Acha jaaega..

[@tomtac820]

Sir at 6:00 no need to find bn na as f(x) is even function ?

[@DrMathaholic]

See the graph for the function. Is it even?😀 We have defined from 0 to 1 and not -1 to 1.

[@DrMathaholic]

see graph which i drew before writing coefficients.

[@tomtac820]

@@DrMathaholic oh yes sir I was focusing on f(x)=f(-x) instead of intervals mentioned

[@DrMathaholic]

@@tomtac820 happens 😊

[@darshanwani8247]

At x=0, in sine series how we get that please explain it.

[@DrMathaholic]

At 13:13 by mistake i wrote that sum of Fourier series at x=0 is (1+1)/2=1. There is a mistake, here left hand limit is -1 and right hand limit 1 so Average will be 0.

[@sarthakpawar9303]

sir at 5:39 why is the limit of integration 0 to 1 and not -L to L

[@DrMathaholic]

Here the function is not defined from -1 to 1. It is defined over 0 to 1 and we have to fourier series of given function over 0

[@sarthakpawar9303]

@@DrMathaholic thank you sir

[@DrMathaholic]

@@sarthakpawar9303 welcome 😊