Shear Force and Bending Moment Diagrams for an INTERESTING Beam With a Hinge

In this tutorial, we try to draw the shear force and bending moment diagrams for a beam with a hinge. We utilize most of the tricks we know from structural analysis and statics to draw the V and M diagrams.
#Engineering
#civil_engineering
#structuralengineering
#structural_engineering
#هندسة_مدنية
#تحليل_إنشائي

[@momin_ou]

I am back here after 8 years to express my gratitude towards you. I suddenly remembered you and came back to thank you again for this tutorial.

[@CTSCIVIL]

Wow! 8 years! Man I am getting old :) Thank you so much for your kind words. May God bless you

[@CTSCIVIL]

thank you for pointing that out what do you suggest?

[@Jean1juan]

Thank you for every second of explanation. I have been in class for 4 weeks and understand nothing until I watched this video. Thanks alot for sharing 52 minutes of your time. I truly appreciate your help.

[@h.x3831]

Thank you for making complicated problem easily understood. Even though i am no longer student i enjoy your lectures, because you help me to understand the subjects that i had difficulty when i was student. Thanks again and may Allah bless your work.

[@TheRenzer9]

ALL THE BEST for the exams..this comes for all of us whom u have provided your greatest help thank you :)

[@CTSCIVIL]

Look at the 11th minute of the video up to the 18th. That should tell you how :) thanks for stopping by

[@CTSCIVIL]

Abdulrahman, the answer is yes. the moment at the hinge is always zero since its mechanism does not permit the development of internal moment. So, the moment is always zero. Eid Mubarak Yours Admin

[@NerdyBirds007]

Dude, you saved my life honestly just signed on to tell you how good this video was. Much better than my lecturer! THANKYOU!!!

[@CTSCIVIL]

Bibek, I will start reading about the topic in a week since it was more than 12 years since I saw influence lines. let us see how it goes.

[@BG-uf8kh]

May Allah reward you brother. very clear and easy to follow teaching

[@kayzinc07]

wow this video was extremely helpful despite the vast difference in our methods of calculating. thanks so much!!!

[@isaacanani]

i really like your tutorial skill ,and please i will be happy to have more of your videos mainly on structural analysis. thanks sir.

[@CTSCIVIL]

the hinge does not have a "direct" effect on the load distribution. the effects comes in play when calculating the moment, shear force, and deflection. Moreover, the presence of the hinge will reduce the size of the beam since it will divide the beam into segments which ultimately leads to lower moments due to shorter lengths.

[@CTSCIVIL]

try to use the equation of the shear force for the right segment of the beam and see what you get and let me know

[@CTSCIVIL]

if you are referring to the horizontal reaction at A, this reaction is set to zero since all the forces acting on the member are vertical. hope that clarifies the concept.

[@Yigisa]

Thank you sir! Worth tens of pages of text book and at least week of lectures presented in a very understandable way in a less than an hour video on youtube. Top of that this saved my homework. Very efficient indeed.

[@CTSCIVIL]

Good to know that ir helped

[@lindalafi8522]

caould you please do a video on any of these topics? conjugate beam, energy method and superposition for beams? I have an exam in 10 days and although I have studied the material, I'm still struggling. I have looked at many videos, and out of about 10 videos on this specific topic, found yours most informative, clear and to the point. your explainations are wonderful and thorough and as with any matter of mind, once understandood it is no longer difficult. thank you sir for your time.god bless.

[@CTSCIVIL]

the 1/2*6*6 is the area of the triangular load which will convert the distributed load to a concentrated one. remember, when you have a distributed load, calculate the area represented by the load (in this case is a triangle) and that should give you the equivalent point load. in the case of uniformly distributed load (rectangular), the area is the load value multiplied by the distribution length (that is the width times the height which is the area of the rectangle) hope that was clear :)

[@igonesyt]

Thanks from Brazil!!! Awesome work!!

[@axlxavier]

Hello, very nice explanation about this topic, I have a question please: how did you get the moment Mo = -120 (min 37 of the video) thank you!

[@CTSCIVIL]

what exactly?

[@GuardianKphirak1113]

Thank so much for this video! Could you do another video about cantilever beam? I find it difficult to write the shear and bending equation of cantilever beam!

[@matthewharvey1963]

I love how you explain things and actually work through it all with us! It's a unbelievable help. I have a question. When making the moment diagram what is the effects of the 28k and the 6k on the diagram?

[@dinkylicous1234]

Awesom work man

[@BibekTamang]

Hey, The videos and the tutorials that you've uploaded are fabulous. I don't have words to define them and thanks a lot..... I've a some questions related to structure... Can you upload tutorials realted to "Influence Line Diagram (ILD) For Simple Structures" Simple Structures may include Simply Supported Beam, Cantilever Beam etc... Hope you'll help me.

[@axlxavier]

Yes I missed that part, that is okay now, thank you for responding so quickly. One more question please if you don't mind: I tried to get a 12 value for x using the moment equation (minute 46)but it gave me -96 I don't know what I did wrong, thanks again...

[@MHSSA1]

how hinge affects the force distribution for the beam?

[@j235jo]

can yo do one with two support ? with the method's areas? english is no my native lenguaje ....

[@MrWcx2002]

thank you ... and Eid Mubarak for you

[@CTSCIVIL]

you are right but there is a huge difference between explaining the problem and doing the problem. when I explain it, I try to imagine every single question that might come up to the one who is watching and try to somehow answer it. but, if I am doing the problem, it will take me 10 minutes to go through it and then the tutorial is pointless. Thanks for the comment CTSCIVIL Aadmin

[@dengchang1296]

Awesome tutorial, Love ur video so much!!!

[@CTSCIVIL]

good one :) keep it up

[@guitarz1egendz]

if the parabola is spandrel sir, can 1/3 BxH and 2/3 BxH be used?

[@MHSSA1]

How is the third reaction force at A called?

[@kennethokolie9225]

Thanks for the video, it really helped, i need more light on y the reaction of -4 at the hing was neglected when drawing the diagram, or is it only useful in getting the other reactions, after which it becomes useless? thanks

[@CTSCIVIL]

basically it will switch the signs of the moment from negative to positive. BUT, why would you switch in the first place?

[@siphosyble8478]

Hello Sir, thank you so much for the video. But i am a bit confused why when you were finding v(x) you said minus the intergral of w(x). What determines the sign of the intergral?

[@illidan333]

Thanks you very much, this problem is from which book ?

[@CTSCIVIL]

+illidan333 I do not remember. It might be from Hibbler

[@cjjb]

I reckon you covered about half a semester's worth of material for my structures module here in one hour.

[@CTSCIVIL]

You are very welcome. Keep on going to class and go to the course TA, ask questions, silly and good ones, that is the only way you will learn. TRUST ME :)

[@CTSCIVIL]

The force By is being canceled from both sides. so it acts like a part of the beam. the only thing the hinge will do is effect the moment diagram.

[@eazuber]

جزاك الله خيرا يا هندسة

[@CTSCIVIL]

+Ahmed Zuber حياك الله

[@95lezan]

you are the best ... i love ur way to finding moment by integration thank you alot :)

[@CTSCIVIL]

+baban azad You are so welcome :)

[@abdulrahmanalshluwi4573]

What would change in the diagrams if you changed Ma= -120 clockwise to Ma = 120 counterclockwise ?

[@nelsonshiwakoti4894]

I don't know it sir. But it'll be better if we could see some thing much distinct then this one, so that we can watch ur video with more concentration. All the best :)

[@axlxavier]

Hi, I've got -22, it is okay? why not -12? thank you!

[@CTSCIVIL]

Thank you for your kind words

[@ebidash]

Thank u very much,it helped me alot for my peng exam preparation:)

[@CTSCIVIL]

That is so kind of you :)

[@cjjb]

You're the man!

[@caryperez1980]

for those who loves integration ,you actually can form two system of moment equation to find shear and moment @ A.

[@CTSCIVIL]

you are welcome and obrigado

[@tolulopeekundayo3914]

This is excellent. I have gained from this & you reminded me of some things.

[@CTSCIVIL]

TOLULOPE EKUNDAYO Great. Thanks for stopping by.

[@SafiMarroun]

Thanks for the video, but i think 52 minutes is very long for such a problem! it's helpful though :)

[@CTSCIVIL]

you are welcome

[@CTSCIVIL]

Great I am glad that helped

[@guitarz1egendz]

why is the M diagram at 0->12 = -12 sir? i cant get it, isnt the area positive?

[@CTSCIVIL]

Adrian munoz for the -12 moment, you can easily calculate it from the right hand side since you have a single applied force at the tip of the beam at poit D ( 6 * 2 ) clockwise (i.e. negative)

[@aimanhashmi4461]

can some1 tell me that how in trapazoidal loading he was sure that the rectangle drawn was at the mid of 12 kipp loading or he assumed or what it?

[@abaajaah]

excellent excellent thanks brother

[@CTSCIVIL]

+Hussain alabbas You are so welcome brother

[@harichalla5295]

sir am not getting check in moments by integrating method while am choose moment is clockwise direction. at that time am gettingMa=+120 sir , sir plz clear my confusion.

[@dineshreddyr10s]

how to solve SFD and BMD if the beam itself is a parabola and concentrated load acting at vertex?

[@bongameboy]

the first graph u drew should be a bending moment diagram but not a shear force diagram right? thx

[@CTSCIVIL]

The first drawing is a the shear force diagram ( V )

[@MHSSA1]

At 08:53, why did you do this: 1/2*6*6? Isn't it 1/3*6*6?

[@atefemran9809]

I think you forgot adding " Normal force at hing " right ?

[@dIbRaNzOoALBO]

Hey, at x=12 for the moment equation you don't get 12. You get -96. That equation M(x) you derived should only work untill x=9 ft because at x=9ft the shear jumps. How can you use integration to get that value 12 for moment at x=12 ft

[@segoviapatricio]

excellent video, you helped me a lot. It would had been great if the distributed load were at x>3 and with an applied Moment at x=6, for example,,,,,, that would had made the exercise more interesting and complete. Thanks a lot,,,it really helped me a lot!!

[@CTSCIVIL]

papi chulo Thanks for the input.

[@KunalMagar23]

the moment 120 is wrong bcoz sir u took clockise +ve and anti - ve and before dta in frst part u took opp of dat y?????????????

[@abdullahalhussaini8833]

Very helpful!!

[@CTSCIVIL]

Great😀

[@mmiftahulazhar220]

+CTSCIVIL what if there is a moment in the internal hinge ?

[@guitarz1egendz]

i tried plugging M(12)= X^3-6x^2+50x^2-120 and the ans. isnt -12 sir its -96. Did I miss something else? I also tried using Integral its still -96. I dont get it. :(

[@CTSCIVIL]

Adrian munoz the moment equation is good for the length where the distributed load is applied. so you can apply the moment equation from 0 to 9. as for the -12 moment, you can easily calculate it from the right hand side since you have a single applied force at the tip of the beam at poit D ( 6 * 2 ) clockwise (i.e. negative)

[@CTSCIVIL]

I would love to help out the thing is that i am preparing for my PhD qualification examination and whenever i have some free time i would rather spend it with my wife and kids. please accept my apology and keep on digging or get some private tutoring from your college. I wish if i have more to say but good luck to you

[@BibekTamang]

No matter ... You can take your time.... :)

[@MrWcx2002]

hi guys i have Q i think it is stubied Q but no proplem Q say >> the moment in hinge ahways = 0 this inf. true or fules

[@Gahoole39owl]

tanks

[@gomerv1]

for 36:58=2/3 x 22 x ( 44)^.5 - 96 -120

[@CTSCIVIL]

can you draw the problem and e-mail it to me? use the email in the channel info Thanks

[@caryperez6629]

some people says that this has no practical use......

[@caryperez1980]

which are : V(0)=50 and M(0)=-120

[@k20aturbo]

Who the hell disliked this video? Come back and apologize now!

[@A999g]

wallah wa7sh bs we have to have 2 forces at the hinge one vertical and the other one is horizental on both sides and they r equal and opposite in direction its correct that u didnt use it in this question because X-forces are zeros ,,, anyway mashaa,a allah and keep it up ! from kuwait

[@CTSCIVIL]

Abo Gazi Mashkoor ya boghazi You are 100% right. No need to mention the horizontal forces since they do not play any role in the problem.Thanks for stopping by :)

[@nelsonshiwakoti4894]

very poor mouse indicator.

[@يااارب-ظ6ق]

لــﹷ⁽҉☹️҉₎ـٰ۪۫ﹷـٰٰيـشۦ˛⁽❥₎⇣ مو عربي

[@CTSCIVIL]

هذه بالعربي kzbin.info/aero/PLcjMZ8MBKWyo9C18df-CVb9_YBKitb7su