Short Trick for Removable Singularity & Poles | Complex Analysis | Short Trick By Gp sir

[@Rakeshkumar-jf4ty]

Option A is correct thank you so much sir 🙏 🙏

[@abmath...8460]

Option A is correct

[@barkhakala8343]

Thank you so much sir

[@dineshkumar-pl3ix]

Option a is correct

[@soniasharma5141]

You are the best

[@sunitakumawat3609]

Option A is correct option, thank you sir

[@rashmideshmukh587]

Option A Thanks sir

[@SKREJAULHASSAN]

Ans A

[@sagarikasahoo3943]

opt A Thank you sir

[@sumitas8998]

Answer is A Thank you sir🙏

[@artigupta8755]

Removable singularity ❤

[@dronamrajuchanda3262]

ans a thank you sir

[@chandansahu6113]

Ans -A Thank you sir 🙏❤️

[@roshanisamarwal]

Option A , removal singularity

[@Bhawna_12352.]

Option A... Thanku so much sir 🙏🏻

[@duniyawithqamar2973]

Hmmm

[@rituyadav8148]

Option A 💯

[@souvikgiri4616]

Correct✅ option A.... Thank you🙏🙏 sir

[@koushikpal3445]

Option A

[@shaistha1346]

A is the ans

[@dipapal1567]

Thank You Sir ❤️🙏🏻 A ✅

[@adititiwari9019]

A option is correct,1 sec and thank you so much sir 🙏🙏

[@UmeshYadav-tg3tl]

A✅

[@priyaverma3247]

Option - C , pole of order one at z=π/2.

[@followersofthakurankulchan3287]

A is the answer

[@Vishalkumar-jr1rt]

Option A sir ji 🙏🙏

[@learn_Mathematics828]

Option A m=n So RS

[@sushmitagupta2453]

A

[@mathematicsclassesbyrkshar8993]

❤❤❤❤❤

[@ankitasinharoy6683]

Removable singularity(option A)

[@prasannabatchu3152]

Option a is true sir

[@deenakrishnadalabehera5334]

Ans is A & B

[@AmitSingh-em1tm]

a

[@PoojaLohamrod]

A (0/0form)

[@gappudewangan5077]

Option (A) removable singularity 0/0 form

[@priyaverma3247]

Option - C , pole of order one at z=π/2.

[@salma121]

Question no 2: answer option A sir. Can you please explain sir. I didn't understand

[@Thenishavermashow]

See....jo numerator h uska order 0 h kunki when we put 2 in z we get 16-2=14 so no need of first order derivative .

[@Vishalkumar-jr1rt]

Because form 0/0 and Z=π/2 par limit finitely exist

[@AshishRawat-ng5lj]

Z=1

[@Gyanendra.G.K.2M]

sir अपना नंबर दीजिये sir aap🙏🏻jankari चाहिए sir aapse🙏🏻🙏🏻🙏🏻🙏🏻

[@SKREJAULHASSAN]

Ans A

[@dhaneshvermacreator...9403]

A

[@themathematicssgodinfinity8933]

Option A

[@Sourabhkumarair]

Option A

[@dhenasaranya1614]

A

[@mathsbyprasanjit]

A

[@highermathseducation8831]

A

[@mazharalam1011]

A

[@debashislenka8160]

A

[@5Stars49]

A

[@PRIYANKAKUMARI-xl7pn]

A

[@shivanichoudhary374]

A

[@sariaray2001]

A

[@viveksoni014]

A

[@shraddhadubey7091]

A

[@iram673]

A

[@afrinhashmi5409]

A

[@shraddhadubey7091]

A

[@SSBBK46]

A

[@shaistha1346]

A