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@samuelpaes26 жыл бұрын
Thx u so much. I am brazilian student of Electrical Engineer and your videos help me so much. Thanks again.
@unmeshdange51176 жыл бұрын
These videos are really helpful. Thank you very much
@mohanvarri74392 жыл бұрын
mam your classes Cristal clear subject please teach us more subjects
@gskerbecs95132 ай бұрын
Thanks a lot Ma'am!!! Jai Shri Ram
@skkstudio19725 жыл бұрын
Wel explain mam.
@shravanthipabba81223 жыл бұрын
Thank you so much😊
@muhammetaytekin20425 жыл бұрын
So the unit step function itself is neither even nor odd function because it does not meet both of the conditions for even and odd function definitions, but it is a sum of one even and one odd function. Is that correct? From here can we say a signal does not have to be even or odd function, it can be neither of them?
@fjworkshop3 жыл бұрын
good video
@kprakash96656 жыл бұрын
Thx u so much
@abdirazakali90644 жыл бұрын
what ateacher thank you very much
@arindamsarkar4116 жыл бұрын
Mam if I keep odd 1st then even, I mean I want to substrate even from odd then will it correct??
@harishgollavilli90466 жыл бұрын
Thanq soo much mam
@chinnipatil77684 жыл бұрын
Super
@PurnaMutta-s9t3 ай бұрын
Can u suggest me some tips for gate preparation
@animeena23733 жыл бұрын
mam here little mistake Xe(t)=x(t)-x(-t)/2 should be n thanqq uhh mam ur video are so helpful 🙏🙏😊
@engr.mujahidbilal23873 жыл бұрын
Nope mam is right 😊
@el_05_amarborse68 Жыл бұрын
Mam, we don't have to give GATE or technical exam, we just have to pass, ss subject so teach us that way.
@vishalengg.mumdiv.25224 жыл бұрын
2x speed
@b23663 жыл бұрын
رحمله والديج
@ajj77946 жыл бұрын
is even part of u(t) not = (1+1)/2 = 1???
@biswadeepchakraborty24604 жыл бұрын
yes that is also my question...at t=0 both u(t)and u(-t) have a value 1 so the resultant should be 1+1=2..but by gibbs phenomenon it would be (1+1)/2=1
@himanshumishrabadal68064 жыл бұрын
actually u(-t) will be zero... , so Ue(t)=1/2
@vivekiyer94822 жыл бұрын
@@himanshumishrabadal6806 No I guess Because u(-t) is just reflection of u(t) like a mirror image so at t=0 it's 1 at u(-t) then it upto - infinity it remains 1 only 0 to - infinity is remain 1 only. Which I feel.
@vivekiyer94822 жыл бұрын
@@biswadeepchakraborty2460 Even I feel the same
@vivekiyer94822 жыл бұрын
Even signal= {....0.5,0.5,0.5,1,0.5,0.5,0.5...} Odd signal= {...-0.5,-0.5,-0.5,0,0.5,0.5,0.5...} u(t) = {0,0,0,1,1,1,1..} And u(-t) = {.....1,1,1,1,0,0,0}