Simple, elegant proof of Pythagoras's theorem.

Super-simple, super-elegant proof or Pythagoras's theorem using similar triangles.

[@tedszy7100]

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[@calemartin5398]

Awesome! Love it

[@tedszy7100]

Thank you!

[@dakcom-mk6mp]

Nice

[@tedszy7100]

Thanks!

[@catman8965]

There's a simpler way. Take 4 copies of the same right triangle. Arrange them so each hypotenuse forms a side of one square. Now add the area of each triangle to area formed in the middle of the square. The total area must be equal to area formed by the square of the hypotenuse (C-Squared). I hope you try this.😊.

[@tedszy7100]

This may be a shorter way, but the way in the video uses only similar triangles. It doesn't rely on a clever geometrical construction.

[@perfredlund]

Clever and short. What could be better?? Actually, I do NOT find it very clever. In fact it is a rather obvious idea/construction!!

[@catman8965]

@@perfredlund SOOOOO obvious you didn't think of it for yourself. LOL

[@catman8965]

@@tedszy7100 Didn't you just construct similar triangles in your proof thus relying on construction?