Simple Harmonic Motion - Springs in series vs parallel, and vertical springs

This is a standard AP physics and first year undergraduate physics problem. I compare springs in series to springs in parallel to vertical springs.

[@salehahmed4139]

Excellent explanation, simple and made easy. Thank you

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel

[@diyatakhar661]

thank you so much!🙇‍♀️

[@Muck-qy2oo]

What I always wonder is whether a series of different springs acts similar to a conical spring, in a nonlinear shape?

[@zzzweasel]

thank you!

[@yeonhojung7185]

I guess you are a new yoututor but I really have high reputation on this channel!

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel

[@BirnieMac1]

For a series spring, how does a block in series between the two springs change things? Is it just a matter of subtracting friction from the spring force in the equation of motion?

[@mnotil]

Hey, nice video! What about a mass that is being suspended by two parallel, vertical springs with different spring constants?

[@fourier6119]

Hi Physics Ninja. I really like to watch the next video that explains a spring constant when mass is 0 but I cannot find it. Would you give me the link, please? Thank you.

[@PhysicsNinja]

Simple harmonic motion including the mass of the spring

[@JB9196]

Good video - helped me a lot when doing coursework :)

[@PhysicsNinja]

Thanks, i'm glad you found it useful. Happy learning!

[@uasserkamal2002]

thx alot

[@deavl10]

Could someone tell me what would happen if you have two in parallel on one side and ONE (alone/in series) on the other side of the mass. How and why would you simplify it.

[@PhysicsNinja]

imagine pushing the mass a little on the side where there are 2 in parallel. All 3 springs would now try to return the mass back to the equilibrium position so the equation of motion would be ma=-k1*x-k2*x-k3*x. All 3 spring forces are in the same direction. The effective spring constant is simple the sum keff=k1+k2+k3.

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel

[@sumedh7130]

Is there a way to determine the spring constant of a parallel system without the use of simple harmonic motion. I am asking this because this showed up on the AP exam and I was surprised as I thought harmonics would not be tested.

[@PhysicsNinja]

You could hang the springs and see how much they stretch.

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel

[@evstath]

Can you saw and proove with maths that the force F in the spring system in series is the same in both springs? e.g. Why k1x1=k2x2=F ? Is it because the displacement of two springs are not equal as it is in the parallel system? And depends on the constant K of its spring? It results that if the system is at rest ΣFx=0 -> F=k1x1-k2x2 . this means that the k2 spring must be conpressed and not elongated. Is that correct ?

[@PhysicsNinja]

Blanqui imagine if it was a massless rope. In this case we say the the tension is the same everywhere. In our case we neglect the mass of the spring therefore the force must be the same or else you'd get a small piece of spring with infinite accelaration

[@evstath]

If you sketch the F.B.D with the force vectors on springs it is difficult to understand how can 2 equal spring forces with vectors pointed to the left can be equal with 1 force pointed to the right, so that the sytem be at rest. -k1x1-k2x2 = F ???? So, can you please write the ΣFx for the system in series ? It is difficult to understand it if you write the ΣFx without the equivalent spring, but with the 2 individual springs K1 and K2

[@swapnayak4348]

@@evstath Take the point exactly between both the springs, As both the springs are massless, net force has to be zero. F1x1=F2x2

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel

[@king-hm7gs]

Thank you

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel

[@ketanschannel5216]

cause teacher there are better things that i don't wanna learn and the last one i had made me cry

[@JoshMurphy424]

what is the frequency of two springs in series, in term of the frequenies of the two individual springs?

[@PhysicsNinja]

+Josh Murphy Starting from expression for at 16:13 of the video. Write down the frequency of the individual cases as w1^2=k1/M and w2^2=k2/M. For each of these cases write the spring constants as the angular frequency squared multiplied with the mass. k1=w1^2*M, k2=w2^2*M. All you need to do is eliminate the spring constants in the general equation. With a little algebra you should get to the solution w=sqrt[ (w1^2*w2^2)/(w1^2+w2^2) ]. If you're still having trouble should me an email [e-mail] and i'll forward you a PDF.

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel

[@dangisjakutis3754]

Very nice video,thanks bro

[@ganeshgalaxygg2549]

Good explanation , for easy watch here:-)kzbin.info/www/bejne/ambdZ6qth7KIqcU Like,share and subscribe my channel

[@phoenixelectronics2631]

Bro, can you solve for a block placed between two springs??

[@PhysicsNinja]

Phoenix Electronics the block between 2 springs will be the same as the 2 springs in parallel. For 2 springs in parallel like in the video both springs push and pull at the same time whereas for the block in between one spring will push and one will pull but both forces will be in the same direction.

[@phoenixelectronics2631]

@@PhysicsNinja yeah you are right I got the same result as in parallel springs. Thanks a lot.❤

[@antoniomantovani3147]

so not many likes its a shame, please use the button